[CC-CHEFGRPH]Time to Study Graphs with Chef 题目大意: 一个有向图可以分成\(n+2(n\le10^{12})\)层,第\(0\)层和第\(n+1\)层有\(1\)个点,剩下每一层\(m(m\le10^5)\)个点.每个点到下一层的每一个点都有连边.另外有\(k(k\le5\times10^4)\)条新边,从层数小的点到层数大的点. 问从第\(0\)层到第\(n+1\)层有几种方案. 思路: 将额外边上的点离散出来单独计算答案,不是额外边的点可以直接通…
https://www.codechef.com/DEC17/problems/GIT01 #include<cstdio> #include<algorithm> using namespace std; #define N 101 char s[N]; int main() { int T; scanf("%d",&T); int n,m; int OddG,OddR,EvenG,EvenR; int ans; while(T--) { OddG=O…
AIX Study之--AIX网卡配置管理(ent0.en0.et0) 1.查看AIX系统网卡信息: [root@aix211 /]#lsdev |grep et en0 Available 1L-08 Standard Ethernet Network Interface en1 Available 14-08 Standard Ethernet Network Interface en2 Defined 1D-08 Standard Ethernet Network Interface e…
Extracting knowledge from knowledge graphs using Facebook Pytorch BigGraph 2019-04-27 09:33:58 This blog is copied from: https://towardsdatascience.com/extracting-knowledge-from-knowledge-graphs-e5521e4861a0 Machine learning gives us the ability to t…
Calculus on Computational Graphs: Backpropagation Introduction Backpropagation is the key algorithm that makes training deep models computationally tractable. For modern neural networks, it can make training with gradient descent as much as ten milli…
Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. Unfortunately, the longer he learns, the fewer he gets. That means, if he reads books from ll to rr, he will get a…
Portal --> CC Chef and Graph Queries Solution 快乐数据结构题(然而好像有十分优秀的莫队+可撤销并查集搞法qwq) 首先考虑一种方式来方便一点地..计算一个图的联通块数量:我们可以考虑容斥,维护每个连通块的生成树,然后\(n-\)生成树边数就是答案了 这样有一个好,加边的时候比较好处理,但是光这样并不能解决我们的问题 顺着这个思路思考,先不考虑时间复杂度,对于一个询问,考虑将编号为\(l\sim r\)的边一条一条加入第\(1\sim l-1\)条…
Chef and Rainbow Array Problem Code: RAINBOWA Chef likes all arrays equally. But he likes some arrays more equally than others. In particular, he loves Rainbow Arrays. An array is Rainbow if it has the following structure: First a1 elements equal 1.…
262144K Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. Unfortunately, the longer he learns, the fewer he gets. That means, if he reads books from ll to rr, he…
Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. Unfortunately, the longer he learns, the fewer he gets. That means, if he reads books from ll to rr, he will get a…
Ryuji is not a good student, and he doesn't want to study. But there are n books he should learn, each book has its knowledge a[i]a[i]. Unfortunately, the longer he learns, the fewer he gets. That means, if he reads books from ll to rr, he will get a…
Posted on August 31, 2015 Introduction Backpropagation is the key algorithm that makes training deep models computationally tractable. For modern neural networks, it can make training with gradient descent as much as ten million times faster, relativ…
Atitti.dw cc 2015 绿色版本安装总结 1.1. 安装程序无法初始化.请下载adobe Support Advisor检测该问题.1 1.1.1. Adobe Application Manager无法安装解决办法1 1.2. Need Adobe Application Manager??2 1.3. 启动的时候儿accept不能启动..冉green.bat运行给挂走ok兰..gujyi sh del oobe le ..zai run bat bg oobe install…
1.Plan your time carefully. Make a list of your weekly tasks.Then make a schedule or chart of your time.Fill in committed time such as eating,sleeping,meeting,classes,etc. Then decide on good ,regular times for studying.Be sure to set aside enough ti…
------------------------本文为自己实践所总结,概念性的东西不全,这里粗劣提下而已,网上很多,本文主要说下目前较流行的syn洪水攻击和cc攻击------------------------------------- 何为syn flood攻击: SYN Flood是一种广为人知的DoS(拒绝服务攻击)是DDoS(分布式拒绝服务攻击)的方式之一,这是一种利用TCP协议缺陷,发送大量伪造的TCP连接请求,从而使得被攻击方资源耗尽(CPU满负荷或内存不足)的攻击方式(TCP协议…
gcc 是GNU Compiler Collection,原名为Gun C语言编译器,因为它原本只能处理C语言,但gcc很快地扩展,包含很多编译器(C.C++.Objective-C.Ada.Fortran. Java),可以说gcc是GNU编译器集合. g++ 是C++编译器. cc 是 Unix系统的 C Compiler,一个是古老的 C 编译器.而 Linux 下 cc 一般是一个符号连接,指向 gcc:可以通过 $ ls -l /usr/bin/cc 来简单察看,该变量是 make 程…
包括两种计算方法:精确计算和近似计算(思考:local density=单位面积的点数 vs local density =1/单个点所占的面积) 每种方法可以实现三种模式的点云密度计算,CC里面的点云计算依赖于 给定的近邻半径所对应的最佳八叉树层级 (通过findBestLevelForAGivenNeighbourhoodSizeExtraction()方法实现) 在GeometricalAnalysisTools类文件中实现. //volume of a unit sphere stat…
