POJ 3159 最短路 SPFA

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POJ 3159 最短路 SPFA

#include<iostream> using namespace std; const int nMax = 30005; const int mMax = 150005; const int inf = 1000000000; struct node{ int v, w, next; }edge[mMax]; int n, edgeHead[nMax], dict[nMax]; int stack[nMax]; bool vis[nMax]; void spfa(){ for(int i…

POJ 3159 Candies（SPFA+栈）差分约束

题目链接:http://poj.org/problem?id=3159 题意:给出m给 x 与y的关系.当中y的糖数不能比x的多c个.即y-x <= c 最后求fly[n]最多能比so[1] 多多少糖? 差分约束问题, 就是求1-n的最短路, 队列实现spfa 会超时了,改为栈实现,就可以有负环时,用栈比队列快数组开小了,不报RE,报超时 ,我晕 #include <iostream> #include <cstdlib> #include <cstdio>…

POJ 1511 最短路spfa

题很简单就是有向图中求给出的源点到其余所有点的最短路的和与其余所有点到源点的最短路之和一开始以为dij对于正权图的单源最短路是最快的写了一发邻接表的dij 结果超时把所有的cin改成scanf 还是超时(过去并没有用cin的坏习惯..近两个星期才开始疯狂的使用cin..因为懒..) 后来想了一下 spfa也可以求单源最短路就试着写了一发scanf 然后wa...看了半天题目发现是有很大可能爆int的改了后1800+msAC 用cin仍然超时所以cin害人不浅 scanf大法好23…

poj 3013 最短路SPFA算法

POJ_3013_最短路 Big Christmas Tree Time Limit: 3000MS Memory Limit: 131072K Total Submissions: 23630 Accepted: 5125 Description Christmas is coming to KCM city. Suby the loyal civilian in KCM city is preparing a big neat Christmas tree. The simple s…

It's not a Bug, It's a Feature! (poj 1482 最短路SPFA+隐式图+位运算)

Language: Default It's not a Bug, It's a Feature! Time Limit: 5000MS Memory Limit: 30000K Total Submissions: 1353 Accepted: 516 Description It is a curious fact that consumers buying a new software product generally do not expect the software to…

POJ 3159 Candies（spfa、差分约束）

Description During the kindergarten days, flymouse was the monitor of his class. Occasionally the head-teacher brought the kids of flymouse’s class a large bag of candies and had flymouse distribute them. All the kids loved candies very much and ofte…

POJ 3159 Candies （图论，差分约束系统，最短路）

POJ 3159 Candies (图论,差分约束系统,最短路) Description During the kindergarten days, flymouse was the monitor of his class. Occasionally the head-teacher brought the kids of flymouse's class a large bag of candies and had flymouse distribute them. All the kids…