Codeforces791 C. Bear and Different Names】的更多相关文章

C. Bear and Different Names time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output In the army, it isn't easy to form a group of soldiers that will be effective on the battlefield. The communicati…
C. Bear and Different Names 题目连接: http://codeforces.com/contest/791/problem/C Description In the army, it isn't easy to form a group of soldiers that will be effective on the battlefield. The communication is crucial and thus no two soldiers should s…
C. Bear and Different Names time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output In the army, it isn't easy to form a group of soldiers that will be effective on the battlefield. The communicati…
B. Bear and Friendship Condition time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bear Limak examines a social network. Its main functionality is that two members can become friends (then th…
如果某个位置i是Y,直接直到i+m-1为止填上新的数字. 如果是N,直接把a[i+m-1]填和a[i]相同即可,这样不影响其他段的答案. 当然如果前面没有过Y的话,都填上0就行了. #include<cstdio> #include<string> #include<iostream> using namespace std; int n,m,a[60],e; string ma[60]; int main(){ // freopen("a.in",…
[题目链接]:http://codeforces.com/contest/791/problem/C [题意] 给你n-k+1个限制 要求 a[i]..a[i]+k-1里面有相同的元素,或全都不同; 让你输出可能的一个序列 [题解] 先找到YES的一段 (找不到就全都输出一样的); 然后以这段YES作为种子 假设YES的段为pos..pos+k-1 往左往右构造 如果往左构造的话 就是for (int i = pos-1;i>=1;i–) 接下来要给第i个位置确定数字; 则如果i..i+k-1为…
和FallDream组队瞎打一通--B两个人写的都挂了233,最后只剩下FallDream写的A和我写的C,最后我yy了个E靠谱做法结果打挂了,结束之后改了改就A了,难受. AC:AC Rank:180 Rating:2133-8->2125 A.Bear and Friendship Condition 题目大意:问一个无向图是否满足若a到b有边且b到c有边则a到c有边.(n<=150,000) 思路:判定每个连通块是不是团,不是则不满足,复杂度O(n). #include<cstdi…
A. Bear and Big Brother time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob. Right now, Limak…
Bear and Big Brother 签到题,直接模拟就可以了. Bear and Friendship Condition 满足只能是每个朋友圈中每个人和其他人都是朋友,这样的边数的确定的. 然后并查集求每个朋友圈大小再判断是否合法就可以啦. #include<cstring> #include<cstdio> #include<cmath> #include<algorithm> #define LL long long #define maxn 3…
Codeforces Round #405 (rated, Div. 2, based on VK Cup 2017 Round 1) 全场题解 菜鸡只会A+B+C,呈上题解: A. Bear and Big Brother 题意:我也没看太清,就是给你两个10以内的数a,b.a每天乘以3,b每天乘以2,求多少天后a大于b. 思路:应该是有公式的,不过看到数据这么小直接暴力乘求解.官方题解貌似就是这样,数据小就是水题. const int N=1e3+10; int main() { int a…
F. Bear and Fair Set time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a grizzly bear. He is big and dreadful. You were chilling in the forest when you suddenly met him. It's very u…
C. Bear and String Distance time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Limak is a little polar bear. He likes nice strings - strings of length n, consisting of lowercase English letter…
最近遇到一个关于发布订阅(Replication)的奇葩问题,特此记录一下这个案例.我们一SQL SERVER数据库服务器出现大量告警.告警信息如下所示: DESCRIPTION: Replication-Replication Distribution Subsystem: agent xxxxxx failed. Column names in each table must be unique. Column name 'xxxxx' in table 'dbo.xxxxxx' is sp…
在ubuntu下配置yolo(v2)的时候,编译了源码后,尝试运行demo: ./darknet detect cfg/yolo.cfg yolo.weights data/dog.jpg 结果报错提示: couldn't open file: data/coco.names google上找不到同样的问题.那就是我的使用方式有问题了. 因为ubuntu上临时无法上网,从windows上用git clone下载的darknet的源码.然后vim查看了下源码文件,果然,都是dos格式的. 果断弃坑…
30.8 Structure And Representation Of MIB Object Names We said that ASN.1 specifies how to represent both data items and names. However, understanding the names used for MIBvariables requires us to know about the underlying namespace. Names used for M…
Repinted:http://blog.csdn.NET/class1/archive/2006/12/30/1469298.aspx 为了让你的网页能在更多的服务器上正常地显示,还是加上"SET NAMES UTF8"吧(可以根据你的喜欢选择相应的编码,如gb2312),即使你现在没有加上这句也能正常访问. 先说MySQL的字符集问题.Windows下可通过修改my.ini内的 # CLIENT SECTION [mysql] default-character-set=utf8…
By default, the Entity Framework will assume that all of the names of your tables in your database are either pluralised(复数形式的), or in the case of code first, you would like them to be pluralised when created. E.g. you have a table called "Product&qu…
Saddest:adj,可悲的,悲哀的,polar,两级的,极地额,YorkShire,约克郡 A UK wildlife park has confirmed that it is offering a new home to a lonely polar bear named Pizza who is living trapped in a chinese mall. 一个英国野生公园报告称他们为名为Pizz的一个孤独的北极熊提供了一个新家,它在中国生活陷入困难. A UK wildlife…
Repinted:http://blog.csdn.net/class1/archive/2006/12/30/1469298.aspx 为了让你的网页能在更多的服务器上正常地显示,还是加上“SET NAMES UTF8”吧(可以根据你的喜欢选择相应的编码,如gb2312),即使你现在没有加上这句也能正常访问. 先说MySQL的字符集问题.Windows下可通过修改my.ini内的 # CLIENT SECTION [mysql] default-character-set=utf8 # SER…
The following are the general formats for ARNs; the specific components and values used depend on the AWS service. arn:aws:service:region:account:resource arn:aws:service:region:account:resourcetype/resource arn:aws:service:region:account:resourcetyp…
调试网站时,异常出现:Unrecognized attribute 'targetFramework'. Note that attribute names are case-sensitive. Server Error in '/' Application. Configuration Error Description: An error occurred during the processing of a configuration file required to service t…
错误截图: 错误信息: --------------------------- Message from webpage --------------------------- File names can't contain the following characters: & " ? < > # {} % ~ / \. --------------------------- OK --------------------------- 解决方案:http://thesh…
先看下面的执行结果: (root@localhost)[(none)]mysql>show variables like 'character%'; +--------------------------+-------------------------------------------------------------+ | Variable_name | Value | +--------------------------+------------------------------…
CF 628C 题目大意:给定一个长度为n(n < 10^5)的只含小写字母的字符串,以及一个数d,定义字符的dis--dis(ch1, ch2)为两个字符之差, 两个串的dis为各个位置上字符的dis之和,求和给定的字符串的dis为d的字符串,若含有多个则输出任意一个,不存在输出-1 解题思路:简单贪心,按顺序往后,对每一个字符,将其变为与它dis最大的字符(a或者z),d再减去相应的dis, 一直减到d为0,剩余的字母则不变直接输出.若一直到最后一位d仍然大于0,则说明不存在,输出-1. /…
题目链接:http://codeforces.com/contest/510/problem/C 题目大意:构造一个字母表,使得按照你的字母表能够满足输入的是按照字典序排下来. 递归建图:竖着切下来,将每个名字的第x个字母从上到下连接建图.然后求拓扑排序. 之所以要拓扑排序,因为要判断在x-1里面有a-->b  在x中有b-->a,这样就形成了一个环.这样一来,就不能够构造字母表了. [经验教训]:在递归建图的函数中开了两个数组,用来记录字母第一次出现和最后一次出现的位置..结果就RE在12上…
---恢复内容开始--- Meaningful Names: use Intention-Revealing Names //nice,Everyone who reads your code (including you) will be happier if you do. The name of a variable, function, or class, should answer all the big questions. It should tell you why it exi…
tar: Removing leading `/’ from member names+2 分类:Web服务器 标签:tar 3,910人浏览   这并不是一个错误,而是一个警告,原因很简单,就是你在用tar打包一个绝对路径,要避免这个警告信息的话,在执行tar之 前,先cd到要打包的文件所在的路径. 下面文章很详细的解释了为什么,已经写得相当好了,我这里就不重新造轮子了,拿来主义一下~ ************************************************* 首先应该…
                                                A. Bear and Elections                                                                                                                                                                            time limi…
                                      B. Bear and Three Musketeers                                                                             time limit per test  2 seconds                                                                            …
                                              C. Bear and Poker                                                                  time limit per test  2 seconds                                                                  memory limit per test  25…