题目大意: 就是根据它给的程序的要求,不断平移,缩放,旋转三维的点,最后计算出点的位置 这里主要是要列出三种转换方式的齐次矩阵描述 平移translate tx ty tz1 0 0 00 1 0 00 0 1 0tx ty tz 1缩放scale a b ca 0 0 00 b 0 00 0 c 00 0 0 1绕任意轴(过原点)旋转(注意要把轴向量归一化,否则点在旋转轴上时有问题) 这里是以(x,y,z)向量指向我们人的方向逆时针旋转 d 的弧度rotate x y…
War on Weather Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 494 Accepted Submission(s): 270 Problem Description After an unprovoked hurricane attack on the south shore, Glorious Warrior ha…
Special Tetrahedron Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 328 Accepted Submission(s): 130 Problem Description Given n points which are in three-dimensional space(without repetition)…
人类史上最大最好的希望事件 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1198 Accepted Submission(s): 337 Problem Description 作为CNCS的半壁江山,狗哥常常在宇宙中心邵阳眺望黄浦江,夜晚的星空总是迷人,有时候还能见到彗星滑落. 狗哥是幸运的,他在两秒钟内看到了十七颗彗星划过天…
题意:求最小生成树,和任意两个点之间距离的期望 官方题解: 最后求两遍点的积的时候,还是要判断父子关系. 注意 long long #include <bits/stdc++.h> using namespace std; typedef long long LL; +; int father[maxn]; int Find_Set(int x) { if(x!=father[x]) father[x] = Find_Set(father[x]); return father[x]; } st…