pid=5288">http://acm.hdu.edu.cn/showproblem.php?pid=5288 Problem Description OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there's no j(l<=j<=r,j<>i) satisfy ai mod aj=0,now…
Answers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 25    Accepted Submission(s): 16 Problem Description   Sample Input 2 4 2 2 2 1 0 1 2 3   Sample Output NO YES YES YES   Source 2013 Mul…
Arc of Dream Time Limit: 2000/2000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0 Problem Description An Arc of Dream is a curve defined by following function:wherea0 = A0ai = ai-1*AX+…
Hyperspace Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 67    Accepted Submission(s): 32 Problem Description The great Mr.Smith has invented a hyperspace particle generator. The device is v…
// 多校5 1001 HDU5781 ATM Mechine // http://acm.hdu.edu.cn/search.php?field=problem&key=2016+Multi-University+Training+Contest+5&source=1&searchmode=source // 记忆化搜索 // 每次二分,决策最优,所以最多查询11次 // dp[i][j] 当前能确定i元情况下,还能被警告j次 // 下次取k,实际剩余t // dp[i][j]=…
 HDU 5288 OO’s Sequence http://acm.hdu.edu.cn/showproblem.php?pid=5288 OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there’s no j(l<=j<=r,j<>i) satisfy a i mod a j=0,now OO want to k…
Description OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there's no j(l<=j<=r,j<>i) satisfy a imod a j=0,now OO want to know [∑i=1n ∑j=i n f(i,j) ] mod (10^9+7)   Input There are mu…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5288 题意:在闭区间[l,r]内有一个数a[i],a[i]不能整除 除去自身以外的其他的数,f(l,r)表示在这区间内a[i]这样的数的个数,,现给你n个数,求所有区间的f(l,r)的和. 思路:对于每个数a[i]求出他的左右侧最靠近他的且是他的因子的位置L.R,并记录,那么对于每个数a[i]都有了他的L,R,而对于每个a[i]在f(l,r)有价值的次数之和就是(i-L+1)*(R-i+1) 代码:…
OO's Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 955    Accepted Submission(s): 358 Problem Description OO has got a array A of size n ,defined a function f(l,r) represent the nu…
Cut Pieces Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 133    Accepted Submission(s): 62 Problem Description Suppose we have a sequence of n blocks. Then we paint the blocks. Each block sho…
Palindrome subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65535 K (Java/Others)Total Submission(s): 88    Accepted Submission(s): 26 Problem Description In mathematics, a subsequence is a sequence that can be derived from…
Balls Rearrangement Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 25    Accepted Submission(s): 8 Problem Description Bob has N balls and A boxes. He numbers the balls from 0 to N-1, and numbe…
GSM Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 622    Accepted Submission(s): 206 Problem Description Xiao Ming is traveling around several cities by train. And the time on the train is ver…
Problem Description DouBiXp has a girlfriend named DouBiNan.One day they felt very boring and decided to play some games. The rule of this game is as following. There are k balls on the desk. Every ball has a value and the value of ith (i=1,2,...,k)…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5768 题目大意: T组数据,求L~R中满足:1.是7的倍数,2.对n个素数有 %pi!=ai  的数的个数. 题目思路: [中国剩余定理][容斥原理][快速乘法][数论] 因为都是素数所以两两互素,满足中国剩余定理的条件. 把7加到素数中,a=0,这样就变成解n+1个同余方程的通解(最小解).之后算L~R中有多少解. 但是由于中国剩余定理的条件是同时成立的,而题目是或的关系,所以要用容斥原理叠加删…
题解:http://bestcoder.hdu.edu.cn/blog/ 多校6 HDU5793 A Boring Question // #pragma comment(linker, "/STACK:102c000000,102c000000") // #include <conio.h> #include <bits/stdc++.h> using namespace std; #define clc(a,b) memset(a,b,sizeof(a))…
题目链接:http://acm.hdu.edu.cn/showproblem.php? pid=5288 题面: OO's Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 985    Accepted Submission(s): 375 Problem Description OO has got a arra…
What is N? Problem's Link: http://acm.hdu.edu.cn/showproblem.php?pid=4335 Mean: 给你三个数b.P.M,让你求有多少个n满足下式. analyse: 看到数据被吓到了,没半点思路,后来看了解题报告,方法竟然是暴力! 当然暴力是有条件的. 有这样一个公式: A^x = A^(x % Phi(C) + Phi(C)) (mod C) (x>=Phi(C)) 这个公式的具体证明原来在aekdycoin的百度空间有,但是随着百…
OO's Sequence 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5288 Description OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there's no j(l<=j<=r,j<>i) satisfy ai mod aj=0,now OO wan…
First One Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 672    Accepted Submission(s): 193 Problem Description soda has an integer array a1,a2,-,an. Let S(i,j) be the sum of ai,ai+1,-,aj. N…
Problem Description OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there's no j(l<=j<=r,j<>i) satisfy ai mod aj=0,now OO want to know ∑i=1n∑j=inf(i,j) mod (109+7).   Input There are m…
题意:给一个序列,函数f(l, r)表示在[l, r]区间内有多少数字不是其他数字的倍数,求所有区间的f(l, r)之和. 解法:第一次打多校……心里还有点小激动……然而一道签到题做了俩点……呜呜呜……今天的题还算简单……明天就更难了……写个题解纪念一下多校…… 对于序列中的每一个数,要找到从它的位置起向左右找最远连续不能被它整除的数的位置设为l和r,这个数的位置为pos,答案就是(pos - l + 1) * (r - pos + 1),只要分析一下样例就可以得到这个式子……然后为了找到l和r…
我还有什么好说,还有什么好说...... 我是SBSBSBSBSBSBSBSBSBSBSBSBBSBSBSBSBSBSBSBSBS........................ 题意 思路什么的都不写了...........我只是为了记录一下我是SBSBSBSBSBBSBSBSBSBSBSBSBSBSBB 以后不要再SBSBSBSBSBSBSBSBSBBSBSBSBSBSBSBSBBSBSBSBBSBSBSBBSBSBSBSBSBBSBSBSBSBBSBSBSBSB /************…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5753 Sample Input Sample Output 6.000000 52.833333 分析:??? #include<stdio.h> #include<string.h> #include<math.h> #include<queue> #include<algorithm> #include<time.h> using n…
题意: 给你一个序列, 有一个函数 F(L,R) 其中 ai 均不能 被 aL - aR整除的  函数值是这个ai个数 思路 : 反过来求 满足这样的条件的 ai 的区间,然后求和 #include<iostream> #include<vector> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef __int64 LL; ;…
题意: 给你一个序列, 有一个函数 F(L,R) 其中 ai 均不能 被 aL - aR整除的  函数值是这个ai个数 思路 : 反过来求 满足这样的条件的 ai 的区间,然后求和 #include<iostream> #include<vector> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef __int64 LL; ;…
OO’s Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1549    Accepted Submission(s): 559 Problem Description OO has got a array A of size n ,defined a function f(l,r) represent the nu…
一.题意 好人必然说真话,坏人不一定说真话,给定N个人的言论<每人一个发言.不谈及自己>,要求指出有多少个人一定是好人,有多少个人一定是坏人.#define 狼人 坏人#define 村民 好人 The Werewolves" is a popular card game among young people.In the basic game, there are 2 different groups: the werewolves and the villagers.Each p…
一.题意 给定一个树状地图,每个树节点上有一只怪物,打死一只怪物的过程中将会消耗A点HP,打死之后将会获得B点HP.因为树状结构,所以每只怪物必须先打死父节点的怪兽之后在打死子节点的怪物.现在,给定每只怪兽的a,b和树状结构的联通关系,求初始HP最小的击败顺序. Little Q is fighting against scary monsters in the game ``Monster Hunter''. The battlefield consists of n intersection…
一.题意 Sudoku is a logic-based, combinatorial number-placement puzzle, which is popular around the world.In this problem, let us focus on puzzles with 16×16 grids, which consist of 4×4 regions. The objective is to fill the whole grid with hexadecimal d…