CF1854E Games Bundles 题解】的更多相关文章

题目大意 给出一个n个点m条边的DAG,记为G. 可以删掉若干条边成为G′,显然有 2m 种不同的G′. 连边保证:若有 (xi →yi​) 边,则 xi​ < yi . 初始点1和点2有一个标记,Alice和Bob玩游戏,每次可以将任意一个标记沿边移动. 不能移动#者输,求这 2m 张图有多少先手必胜. 对 109 + 7取模. 思路 这题的1和2两个点显然是可以互相独立的 所以可以分开考虑,当做两个不同的子游戏 根据sg定理可以知道当sg[ 1 ]与sg[ 2 ]不同时先手必胜 但是发现直接…
D - A Lot of Games CF#260 Div2 D题 CF#260 Div1 B题 Codeforces Round #260 CF455B D. A Lot of Games time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Andrew, Fedor and Alex are inventive guys. No…
[codeforces 325]B. Stadium and Games 试题描述 Daniel is organizing a football tournament. He has come up with the following tournament format: In the first several (possibly zero) stages, while the number of teams is even, they split in pairs and play on…
A Lot of Games 题目链接: http://acm.hust.edu.cn/vjudge/contest/121334#problem/J Description Andrew, Fedor and Alex are inventive guys. Now they invent the game with strings for two players. Given a group of n non-empty strings. During the game two player…
The Frog's Games Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 5676    Accepted Submission(s): 2732 Problem Description The annual Games in frogs' kingdom started again. The most famous game i…
Baby Ming and Matrix games Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1210    Accepted Submission(s): 316 Problem Description These few days, Baby Ming is addicted to playing a matrix game…
题目链接:hdu_5873_Football Games 题意: 有n个队,每个队都会给其他队打一场,赢一场得2分,平局得一分,输了不得分,然后给你全部比赛结束后的得分,问你是否有假分 题解: 可以知道每打一场分数总和会加2,然后奇数得分的个数是偶数个,0得分的个数最多一个,因为不可能两个队全部都是输,然后就这样xjb水过去了 #include<bits/stdc++.h> #define F(i,a,b) for(int i=a;i<=b;++i) using namespace st…
With the 2010 FIFA World Cup running, football fans the world over were becoming increasingly excited as the best players from the best teams doing battles for the World Cup trophy in South Africa. Similarly, football betting fans were putting their…
2016 ACM/ICPC Asia Regional Qingdao Online(部分题解) 5878---I Count Two Three http://acm.hdu.edu.cn/showproblem.php?pid=5878 Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1287    Accepted Submissi…
[CF446D]DZY Loves Games 题意:一张n个点m条边的无向图,其中某些点是黑点,1号点一定不是黑点,n号点一定是黑点.问从1开始走,每次随机选择一个相邻的点走过去,经过恰好k个黑点到达n的概率. $n\le 500,m\le 500000,k\le 10^9$,黑点个数不超过100. 题解:一眼就知道是高斯消元和矩乘什么的.我们先预处理出f[i][j]表示从第i个黑点开始走到的下一个黑点是j的概率.这个用高斯消元容易搞定.然后上矩乘即可.但是问题在于如果这样做的话我们要做n遍高…