时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 You must have seen the very famous movie series,"Mission Impossible", from 1 to 4. And "Mission Impossible 5" is now on screen in China. Tom Cruise is just learning programming through my MOOC cour…

Problem Description Elves are very peculiar creatures. As we all know, they can live for a very long time and their magical prowess are not something to be taken lightly. Also, they live on trees. However, there is something about them you may not kn…

http://acm.hdu.edu.cn/showproblem.php?pid=5441 Travel Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 2061    Accepted Submission(s): 711 Problem Description Jack likes to travel around the wo…

http://acm.hdu.edu.cn/showproblem.php?pid=5444 Elven Postman Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 939    Accepted Submission(s): 520 Problem Description Elves are very peculiar crea…

Elven Postman Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 591    Accepted Submission(s): 329 Problem Description Elves are very peculiar creatures. As we all know, they can live for a very…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5458 Problem Description Given an undirected connected graph G with n nodes and m edges, with possibly repeated edges and/or loops. The stability of connectedness between node u and node v is defined by…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5489 题目大意: 一个N(N<=100000)个数的序列,要从中去掉相邻的L个数(去掉整个区间),使得剩余的数最长上升子序列(LIS)最长. 题目思路: [二分][最长上升子序列] 首先,假设去掉[i,i+m-1]这L个数,剩余的LIS长度为max(i左端最后一个不大于a[i+m]的LIS长度+a[i+m]开始到最后的LIS长度). 所以,我们从n到1逆向先求最长下降子序列的长度f[i],就可以知…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5493 题目大意: N个人,每个人有一个唯一的高度h,还有一个排名r,表示它前面或后面比它高的人的个数,求按身高字典序最小同时满足排名的身高排列. 题目思路: [线段树] 首先可以知道,一个人前面或后面有r个人比他高,那么他是第r+1高或第n-i-r+1高,i为这个人是第几高的. 所以先将人按照身高从小到大排序,接下来,把当前这个人放在第k=min(r+1,n-i-r+1)高的位置. 用线段树维护包…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5492 题目大意: 一个N*M的矩阵,一个人从(1,1)走到(N,M),每次只能向下或向右走.求(N+M-1)ΣN+M-1(Ai-Aavg)2最小.Aavg为平均值. (N,M<=30,矩阵里的元素0<=C<=30) 题目思路: [动态规划] 首先化简式子,得原式=(N+M-1)ΣN+M-1(Ai2)-(ΣN+M-1Ai)2 f[i][j][k]表示走到A[i][j]格子上,此时前i+j-1…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5491 题目大意: 一个数D(0<=D<231),求比D大的第一个满足:二进制下1个个数在[s1,s2]范围内.D已经满足[s1,s2]. 题目思路: [贪心][模拟] 首先将这个数转成二进制统计总共1的个数s,再求出末尾连续0和1的个数n0,n1. 如果最后一位是0: s=s2,那么为了保证s<s2且答案>D,先设ans=d+lowbit(d),此时满足了新的s<s2且答案&g…