Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in dict. If two such substrings overlap, you need to wrap them together by only one pair of closed bold…

Given a set of keywords words and a string S, make all appearances of all keywords in S bold. Any letters between <b> and </b> tags become bold. The returned string should use the least number of tags possible, and of course the tags should fo…

原题链接在这里:https://leetcode.com/problems/add-bold-tag-in-string/description/ 题目: Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in dict. If two such subst…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 日期 题目地址:https://leetcode-cn.com/problems/add-bold-tag-in-string/ 题目描述 Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b&g…

［抄题］: Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in dict. If two such substrings overlap, you need to wrap them together by only one pair of closed…

题目:Reverse Words in a String Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 比较基础的一个题,拿到这个题,我的第一想法是利用vector来存每一个子串,然后在输出,这是一个比较简单的思路,此外,还有第二个思路,就是对所有的字符反转,然后在针…

1.单纯的Unicode 转码 String a = "\u53ef\u4ee5\u6ce8\u518c"; a = new String(a.getBytes("UTF-16"),"Unicode"); 2.String 字符串中含有 Unicode 编码时,转为UTF-8 public static String decodeUnicode(String theString) { char aChar; int len = theString…

/** * 方法名称:replaceBlank * 方法描述: 将string字符串中的换行符进行替换为"" * */ public static String replaceBlank(String str) { String dest = ""; if (str != null) { Pattern p = Pattern.compile("\t|\r|\n"); Matcher m = p.matcher(str); dest = m.re…

C++ 提供的 string 类包含了若干实用的成员函数,大大方便了字符串的增加.删除.更改.查询等操作. 插入字符串 insert() 函数可以在 string 字符串中指定的位置插入另一个字符串,它的一种原型为: string& insert (size_t pos, const string& str); pos 表示要插入的位置,也就是下标:str 表示要插入的字符串,它可以是 string 变量,也可以是C风格的字符串. 请看下面的代码: #include <iostrea…

Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo"…