作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Python解法 Java解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/implement-queue-using-stacks/ Total Accepted: 42648 Total Submissions: 125482 Difficulty: Easy 题目描述 Implement t…

题目: Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes:…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Implement the following operations of a queue using stacks. push(x) – Push element x to the back of queue. pop() – Removes the element from in front of queue…

#-*- coding: UTF-8 -*-#双栈法class Queue(object):    def __init__(self):        """        initialize your data structure here.        """        self.inStack=[]        self.outStack=[]            def push(self, x):        "…

232 - Implement Queue using Stacks Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whe…

155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } void push(int x) { if(s1.empty() && s2.empty()){ s1.push(x); s2.push(x); } else{ if(x < s2.top()){ s1.push(x); s2.push(x); } else{ s1.push(x); s2…

1. 232 Implement Queue using Stacks 1.1 问题描写叙述 使用栈模拟实现队列.模拟实现例如以下操作: push(x). 将元素x放入队尾. pop(). 移除队首元素. peek(). 获取队首元素. empty(). 推断队列是否为空. 注意:仅仅能使用栈的标准操作,push,pop,size和empty函数. 1.2 方法与思路 本题和用队列实现栈思路一样,设两个辅助栈stk1和stk2. push(x): 将x入栈stk1. pop(): 依次将stk1…

232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front o…

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You…

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You…

题目描述: Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Note…

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You…

这是悦乐书的第195次更新,第201篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第57题(顺位题号是232).使用栈实现队列的以下操作. push(x) - 将元素x推送到队列的后面. pop() - 从队列前面删除元素. peek() - 获取前面的元素. empty() - 返回队列是否为空. 例如: MyQueue queue = new MyQueue(); queue.push(1); queue.push(2); queue.peek(); //返回1…

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front of queue.peek() -- Get the front element.empty() -- Return whether the queue is empty. 代码如下: class M…

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Example: M…

Stack<Integer> stack=new Stack<Integer>(); public void push(int x) { stack.push(x); } // Removes the element from in front of queue. public void pop() { stack.remove(0); } // Get the front element. public int peek() { return stack.get(0); } //…

本题用两个栈实现队列,用栈的基本操作去实现队列的所有基本操作push(),pop(),peek()以及empty() sa作为输入栈,sb作为输出栈,将sa输入元素的反转过来放到sb中 push与sa有关,而pop(),peek()与sb有关,即将sa输入元素出栈放到sb中(函数move). 为此,只有两个栈为空才能让队列为空 class Queue { public: // Push element x to the back of queue. stack<int> sa; stack&l…

class MyQueue { public: /** Initialize your data structure here. */ MyQueue() { } /** Push element x to the back of queue. */ void push(int x) { stkPush.push(x); } /** Removes the element from in front of queue and returns that element. */ int pop()…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/implement-stack-using-queues/#/description 题目描述 Implement the following operations of a stack using queues. push(x) – Push element x onto…

题目: Implement the following operations of a stack using queues. push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. empty() -- Return whether the stack is empty. Notes: You must use on…

▶ 栈和队列的相互表示.发现内置的队列和栈结构都十分高效,相互表示后性能损失都很小. ▶ 第 225 题,用队列实现栈 ● 自己的代码,3 ms,单队列实现,入栈 O(1),读取栈顶元素 O(n),出栈 O(n) . class MyStack { private: queue<int> fakeStack; public: MyStack() { fakeStack = queue<int>(); } void push(int x) { fakeStack.push(x); }…

使用栈来实现队列的如下操作: push(x) -- 将一个元素放入队列的尾部.pop() -- 从队列首部移除元素.peek() -- 返回队列首部的元素.empty() -- 返回队列是否为空.注意: 你只能使用标准的栈操作-- 也就是只有push to top, peek/pop from top, size, 和 is empty 操作是可使用的.你所使用的语言也许不支持栈.你可以使用 list 或者 deque (双端队列)来模拟一个栈,只要你仅使用栈的标准操作就可以.假设所有操作都是有…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 find函数 遍历+切片 日期 题目地址:https://leetcode.com/problems/implement-strstr/description/ 题目描述 Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:Leetcode, 力扣,Trie, 前缀树,字典树,208,Python, C++, Java 目录 题目描述 题目大意 解题方法 从二叉树说起 前缀树 构建 查询 应用 代码 刷题心得 日期 题目地址:https://leetcode.com/problems/implement-trie-prefix-tree/description/ 题目描述 I…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典 汉明间距 日期 题目地址:https://leetcode.com/problems/implement-magic-dictionary/description/ 题目描述 Implement a magic directory with buildDict, and search methods. For the method buildD…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Solution:  class Solution { public: int strStr(string haystack, string needle) { //runtime:4ms int len1=haystack.size(), len…

Implement strStr() Implement strStr(). Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack. 解法一:暴力解 class Solution { public: int strStr(string haystack, string needle) { int m = haystack.size();…

Implement Trie (Prefix Tree) Implement a trie with insert, search, and startsWith methods. Note:You may assume that all inputs are consist of lowercase letters a-z. 一个字母代表一个子树,因此为26叉树,end标记表示是否存在以该字母为结尾的字符串. class TrieNode { public: TrieNode* childre…

比较典型的一个题目,easy,不过可以有许多实现方式. 这里用的方式是每次pop完成之后再将stack2中的内容立即倒回stack1中.但是其他的实现也可以不是这样,可以是需要push的时候检查再,如果内容在stack2中,这时候将其倒回在进行push.这里采取第一种比较笨的方法,代码如下所示: class Queue { public: // Push element x to the back of queue. void push(int x) { s1.push(x); } // Rem…

Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Example 1: Input: haystack = "hello", needle = "ll" Output: 2 Example 2: Input: haystack = "aaaaa",…