HDU 5063 Operation the Sequence 题目链接 把操作存下来.因为仅仅有50个操作,所以每次把操作逆回去执行一遍,就能求出在原来的数列中的位置.输出就可以 代码: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; const int N = 100005; const ll MOD = 1000…
Operation the Sequence                                                                     Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)                                                                            …
http://acm.hdu.edu.cn/showproblem.php?pid=5063 题目大意: 题目意思还是比较简单.所以就不多少了.注意这句话,对解题有帮助. Type4: Q i query current value of a[i], this operator will have at most 50. 解题思路: 因为给定n和m都是100000,我们每一步都做具体的操作,时间将是O(n*m),肯定超时.最开始的时候 我怎么想都不知道怎么解决.以为是线段树.比赛完了以后,看了解…
http://acm.hdu.edu.cn/showproblem.php?pid=5063 思路:因为3查询最多50,所以可以在查询的时候逆操作找到原来的位置,然后再求查询的值. #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #define ll long long using namespace std; ; int n,m; ]; ]; ll…
题目链接:pid=5063" target="_blank">http://acm.hdu.edu.cn/showproblem.php?pid=5063 Problem Description You have an array consisting of n integers: a1=1,a2=2,a3=3,-,an=n. Then give you m operators, you should process all the operators in order…
注意到查询次数不超过50次,那么能够从查询位置逆回去操作,就能够发现它在最初序列的位置,再逆回去就可以求得当前查询的值,对于一组数据复杂度约为O(50*n). Operation the Sequence Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 463    Accepted Submission(s): 187 Problem…
Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not small than 0. Input The input consists of multiple test cases. Each test case…
OO’s Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1549    Accepted Submission(s): 559 Problem Description OO has got a array A of size n ,defined a function f(l,r) represent the nu…
#include <cstdio> #include <cstring> #include <cstdlib> #define MAXN 100005 #define MOD 1000000007 , rear = ; int n; void query(int index) { int r = rear; ; )>>; while (r-- > front) { ) { ++square; } ) { index = n+-index; } else…
Problem Description You have an array consisting of n integers: a1=1,a2=2,a3=3,-,an=n. Then give you m operators, you should process all the operators in order. Each operator is one of four types: Type1: O 1 call fun1(); Type2: O 2 call fun2(); Type3…
Operation the Sequence Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 842    Accepted Submission(s): 288 Problem Description You have an array consisting of n integers: a1=1,a2=2,a3=3,…,an=n. T…
// 判断相同区间(lazy) 多校8 HDU 5828 Rikka with Sequence // 题意:三种操作,1增加值,2开根,3求和 // 思路:这题与HDU 4027 和HDU 5634 差不多 // 注意开根号的话,遇到极差等于1的,开根号以后有可能还是差1.如 // 2 3 2 3... // 8 9 8 9... // 2 3 2 3... // 8 9 8 9... // 剩下就是遇到区间相等的话,就直接开根号不往下传 #include <bits/stdc++.h> u…
题目链接:http://acm.hdu.edu.cn/showproblem.php? pid=5288 题面: OO's Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 985    Accepted Submission(s): 375 Problem Description OO has got a arra…
 HDU 5288 OO’s Sequence http://acm.hdu.edu.cn/showproblem.php?pid=5288 OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there’s no j(l<=j<=r,j<>i) satisfy a i mod a j=0,now OO want to k…
HDU - 1711 A - Number Sequence   Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... ,…
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HDU 2096 /* HDU 2096 小明A+B --- 水题 */ #include <cstdio> int main() { #ifdef _LOCAL freopen("D:\\input.txt", "r", stdin); #endif int a, b, c, n; scanf("%d", &n); while (n--){ scanf("%d%d", &a, &b); a…
HDU 1248 寒冰王座(全然背包:入门题) http://acm.hdu.edu.cn/showproblem.php?pid=1248 题意: 不死族的巫妖王发工资拉,死亡骑士拿到一张N元的钞票(记住,仅仅有一张钞票),为了防止自己在战斗中频繁的死掉,他决定给自己买一些道具,于是他来到了地精商店前. 死亡骑士:"我要买道具!" 地精商人:"我们这里有三种道具,血瓶150块一个,魔法药200块一个,无敌药水350块一个." 死亡骑士:"好的,给我一个血…
题目链接:hdu 4983 Wow! Such Sequence! 题目大意:就是三种操作 1 k d, 改动k的为值添加d 2 l r, 查询l到r的区间和 3 l r. 间l到r区间上的所以数变成近期的斐波那契数,相等的话取向下取. 解题思路:线段树.对于每一个节点新增一个bool表示该节点下面的位置是否都是斐波那契数. #include <cstdio> #include <cstring> #include <cstdlib> #include <algo…
Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an integer N…
题目链接: Hdu 5496 Beauty of Sequence 题目描述: 一个整数序列,除去连续的相同数字(保留一个)后,序列的和成为完美序列和.问:一个整数序列的所有子序列的完美序列和? 解题思路: 考虑位于i位置数字x的贡献值,假设x是子序列中连续相同数字的第一个,那么x对于i后面的数有2(n-i)个贡献值,对前面的数,要么不选取,要么选取结尾不为x的方案数目. #include <map> #include <cstdio> #include <cstring&g…
Hdu 5806 NanoApe Loves Sequence Ⅱ(双指针) Hdu 5806 题意:给出一个数组,求区间第k大的数大于等于m的区间个数 #include<queue> #include<cmath> #include<cstdio> #include<cstring> #include<cstdlib> #include<iostream> #include<algorithm> #define ll l…
Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27028    Accepted Submission(s): 11408 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 89984    Accepted Submission(s): 21437 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <=…
http://acm.hdu.edu.cn/showproblem.php?pid=5806 题意:给你一个n元素序列,求第k大的数大于等于m的子序列的个数. 题解:题目要求很奇怪,很多头绪但写不出,选择跳过的题,简称想法题. 首先考虑区间的更新方法:区间左端l不动,右端r滑动, 滑到有k个数>=m时,此区间符合条件,并且发现右端点再往右滑到底,此条件一直符合(因为若加入的数小于“第K大的数”,则毫无影响.若不然,加入该数会产生一个新的第k大数,保证>=“第K大的数”>=m) 所以一找…
OO's Sequence 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5288 Description OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there's no j(l<=j<=r,j<>i) satisfy ai mod aj=0,now OO wan…
Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11691    Accepted Submission(s): 5336 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
Number Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 148003    Accepted Submission(s): 35976 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A…
题目 //找规律,123321123321123321…发现这样排列恰好可以错开 // 其中注意题中数据范围: M是行,N是列,3 <= N < 2×M //则猜测:m,m,m-1,m-1,m-2,m-2,……,2,2,1,1求出前m个数字的和就是答案. //发现案例符合(之前的代码第二天发现案例都跑不对,真不知道我当时眼睛怎么了) #include <iostream> #include<stdio.h> #include<string.h> #inclu…