题目链接:Shuffle'm Up 题目大意 模拟纸牌的洗牌过程,已知两个牌数相等的牌堆.求解经过多少次洗牌的过程,使牌的顺序与目标顺序相同. 思路 直接模拟,主要是字符串的操作.问题是,如何判断出不可能的情况.这个题好像除了找是否会出现无限循环以外找不到更好的判断方法了. 如果是用字符数组来写的话,要注意末尾'\0'要有,并且strcmp返回0是说明字符数组相等. 题解 #include <iostream> #include <cstring> #include <map…

Shuffle'm Up Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10766   Accepted: 4976 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks o…

http://poj.org/problem?id=3087 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stac…

Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several…

题目链接:http://poj.org/problem?id=3087 Shuffle'm Up Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12305   Accepted: 5708 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is per…

Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several…

题意:就是给你两副扑克,然后一张盖一张洗牌,不断重复这个过程,看能不能达到目标的扑克顺序 分析:然后就模拟下,-1的情况就是有循环节 #include<cstdio> #include<algorithm> #include<iostream> #include<cstring> #include<cmath> #include<map> #include<queue> #include<stdlib.h> #…

题目链接. AC代码如下; #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <string> #include <queue> #include <algorithm> #include <map> #include <ctype.h> #include <set>…

http://poj.org/problem?id=3087 注意复制字符串的时候,要在末尾加上'\0',否则导致strcmp出错. 还有就是开数组大小的时候看清楚一点,别开错了debug了好久. #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include<se…

题目: 现有字符串s1.s2.s12,其中s1.s2的长度为len,s12的长度为2*len. 是否可以通过一些操作使s1和s2转换合并成s12? 变换的操作规则如下: 假设s1=11111,s2=00000 变换后的序列 s=0101010101 假设s1=12345,s2=67890 变换后的序列 s=6172839405 如果s和s12完全相同,那么输出变换次数 如果不完全相等,s的前半部分作为s1,后半部分作为s2,重复上述过程 输入: 第一行T(1≤T≤1000),代表有T组数据. 每…