Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 思路:利用 C++ 中的set 容器.…

这两道题都是求两个数组之间的重复元素,因此把它们放在一起. 原题地址: 349 Intersection of Two Arrays :https://leetcode.com/problems/intersection-of-two-arrays/description/ 350 Intersection of Two Arrays II:https://leetcode.com/problems/intersection-of-two-arrays-ii/description/ 题目&&am…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique. The…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 题目标签:Hash Table 题目给了我们两个 array, 让我们找到在两…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. Subscribe to see which companies asked…

题目要求 Given two arrays, write a function to compute their intersection. 题目分析及思路 给定两个数组,要求得到它们之中共同拥有的元素列表(列表中元素是唯一的).可以将所给数组转成集合,利用集合的交集的概念,最后将结果转成列表即可. python代码 class Solution: def intersection(self, nums1: List[int], nums2: List[int]) -> List[int]: n…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] 思路 代码 class Solution { public int[] intersection(int…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…

283. Move Zeroes var moveZeroes = function(nums) { var num1=0,num2=1; while(num1!=num2){ nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0); } num1 = nums ; }); nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0);…

最近,在用解决LeetCode问题的时候,做了349: Intersection of Two Arrays这个问题,就是求两个列表的交集.我这种弱鸡,第一种想法是把问题解决,而不是分析复杂度,于是写出了如下代码: class Solution(object): def intersection(self, nums1, nums2): """ :type nums1: List[int] :type nums2: List[int] :rtype: List[int] &q…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2,2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [4,9] Note: Each element in the result should appear as…

350. Intersection of Two Arrays II Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:Java解法,HashSet 方法二:Python解法,set 日期 [LeetCode] 题目地址:https://leetcode.com/problems/intersection-of-two-arrays/ Difficulty: Easy 题目描述 Given two arrays, write a function to com…

Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 我们可以使用两个指针来做,先给两个数组排序,然后用两个指针分别指向两个数组的…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique. The…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 代码如下: public class Solution { public in…

题目描述: Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in a…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 给出两个数组,求他们的交集.出题的意图何在? public int[] int…

找两个数组的交集(不要多想,考虑啥序列之类的,就是简单的两堆数求交集啊!!!最后去个重就好了) //LeetCode里用到很多现成函数的时候,苦手だな- //这个题的思路是,先sort,把两个vector进行排序 //然后同时遍历两个字符串,找到相等的数字就放在结果vector里 //最后unique,求vector里独一无二的数字 //erase,得到没有重复的结果 class Solution { public: vector<int> intersection(vector<int…

不重复的: 方法一 ［一句话思路］:排序之后用归并. ［一刷］: 根据返回方法的类型来判断corner case.判断空.0数组的corner case还不一样,得分开写 由于先排序了,nums1[i] < nums2[j]时,i++可以继续在nums2[j]里找是否有相同的 index=0时肯定不会重复,一定要插入 写法是Arrays.sort(nums1) 定义int i还不够,要初始化为0 并列用几个if可能会越界,还是用else if吧 result定义的长度不能是temp.length…

给定两个数组,写一个函数来计算它们的交集.例子: 给定 num1= [1, 2, 2, 1], nums2 = [2, 2], 返回 [2].提示:    每个在结果中的元素必定是唯一的.    我们可以不考虑输出结果的顺序.详见:https://leetcode.com/problems/intersection-of-two-arrays/description/C++: class Solution { public: vector<int> intersection(vector<…

题目描述 Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique…

查找问题 查找有无(只有键) 元素'a'是否存在 set(集合) 查找对应关系(键值对应) 元素'a'出现了几次 map(字典) set和map的底层实现是红黑树 常见操作 insert() find() erase() change(map):改变某个键对应的值 要求 给定两个数组nums,求两个数组的公共元素 输出结果中每个元素唯一 不考虑输出结果的顺序 举例 nums1=[1,2,2,1] nums2=[2,2] 结果:[2] 实现 将公共元素放入公共的set中 1 class Solut…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in t…

349. Intersection of Two Arrays Easy Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each elem…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in any ord…