three version are provided. disjoint set, linked list version with weighted-union heuristic, rooted tree version with rank by union and path compression, and a minor but substantial optimization for path compression version FindSet to avoid redundanc…
Ubiquitous Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 26678 Accepted: 13127 Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in findi…
partial sort. first use std::nth_element to find pivot, then use std::stable_partition with the pivot to partition the largest k, whose indices are in acsending order, print them in reverse order. p.s. lambda expression is also used. STL is powerful.…
To Check current users permissions using Ecmascript\Javascript client object model SharePoint 2010. function checkifUserHasEditPermissions() { context = new SP.ClientContext.get_current(); web = context.get_web(); this._currentUser = web.get_currentU…
Shuffle'm Up Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7529 Accepted: 3466 Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of pok…
Play on Words Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 10620 Accepted: 3602 Description Some of the secret doors contain a very interesting word puzzle. The team of archaeologists has to solve it to open that doors. Because there is…
Walk Out Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 2724 Accepted Submission(s): 548 Problem Description In an n∗m maze, the right-bottom corner is the exit (position (n,m) is the exit). In e…
Magician Time Limit: 18000/9000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1771 Accepted Submission(s): 515 Problem Description Fantasy magicians usually gain their ability through one of three usual methods…
K - Work Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 5326 Appoint description: System Crawler (2015-07-28) Description It's an interesting experience to move from ICPC to work, end my coll…
MessageFlood TimeLimit: 1500ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 Well,how do you feel about mobile phone? Your answer would probably besomething like that "It's so convenient and benefits people alot". However, If you ask Merlin this question…
The 3n + 1 problem Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 53927 Accepted: 17142 Description Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In th…
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 92090 Accepted: 40012 Description Fred Mapper is considering purchasing some land in Louisiana to build his house on. In the process of investigating the land,…
Speed Limit Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 17967 Accepted: 12596 Description Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately…
n a^o7 ! Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 All brave and intelligent fighters, next you will step into a distinctive battleground which is full of sweet and happiness. If you want to win the battle, you must do warm-up accord…
转自:http://blog.csdn.net/bcmissrain/article/details/7190886 其实就算是现在,我还是有不少地方概念模糊,但是下面的内容是是没有什么问题的.稍微介绍一下,或许有些地方我无法解释: 大部分内容都是查的Java SE 5.0 API Icon: Icon位于javax.swing包中,它是一个接口 public interface Icon,介绍为:一个小的固定大小的图片,通常用于装饰组件 有三个方法: int getIconHeight();…
胜利大逃亡(续) Time Limit : 4000/2000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 22 Accepted Submission(s) : 10 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Ignatius再次被魔王抓走了(搞不懂他咋这么讨魔王喜…
#include<stdio.h> struct apple{ int m; int v; }app[1010]; int money(int i,int v); int main(){ int n,v; int x,y,z; while((scanf("%d%d",&n,&v))&&(n||v)){ for(x=0;x<n;x++){ scanf("%d %d",&app[x].v,&app[x].…
