poj--3620--Avoid The Lakes(dfs)】的更多相关文章

Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6795   Accepted: 3622 Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of wate…
Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6826   Accepted: 3637 Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of wate…
Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8173   Accepted: 4270 Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of wate…
题意:给出一个农田的图,n行m列,再给出k个被淹没的坐标( i , j ).求出其中相连的被淹没的农田的最大范围. 思路:dfs算法 代码: #include<iostream> #include<stdio.h> using namespace std; int t[150][150]; int visit[150][150]; int n,m,k; int dfs(int i,int j){ if(i<1||j<1||i>n||j>m||t[i][j]=…
Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid of water. His insurance agency will only repay him, however, an amount depending on the size of the larges…
http://poj.org/problem?id=3620 DFS 从任意一个lake出发 重置联通的lake 并且记录 更新ans #include <iostream> #include <string.h> #include <stdio.h> using namespace std; int N,M,K; ][]; ][] = {-, , , , , , , -}; ; ; bool OK(int x, int y) { || x > N || y &l…
题目 找最大的一片湖的面积,4便有1边相连算相连,4角不算. runtime error 有一种可能是 数组开的太小,越界了 #define _CRT_SECURE_NO_WARNINGS #include<stdio.h> #include<string.h> #include<math.h> #include<algorithm> #include<queue> using namespace std; #define MAXN 110 in…
Avoid The Lakes Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 190   Accepted Submission(s) : 106 Problem Description Farmer John's farm was flooded in the most recent storm, a fact only aggrav…
Avoid The Lakes Time Limit: 1000MS   Memory Limit: 65536KB   64bit IO Format: %I64d & %I64u Submit Status Description Farmer John's farm was flooded in the most recent storm, a fact only aggravated by the information that his cows are deathly afraid…
POJ 1321-棋盘问题 K - DFS Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u   Description 在一个给定形状的棋盘(形状可能是不规则的)上面摆放棋子,棋子没有区别.要求摆放时任意的两个棋子不能放在棋盘中的同一行或者同一列,请编程求解对于给定形状和大小的棋盘,摆放k个棋子的所有可行的摆放方案C. Input 输入含有多组测试数据. 每组数据的第一行是两个正整数,n k…
题意: 给你n*m的矩形,有k个坏点 问最大坏点连通块的坏点数. 一发水题.. 裸的DFS // by SiriusRen #include <cstdio> #include <algorithm> using namespace std; int n,m,k,jy,jyx,jyy,xx[]={1,-1,0,0},yy[]={0,0,1,-1},a[105][105],vis[105][105],ans=0; void dfs(int x,int y){ for(int i=0;…
Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25904   Accepted: 7682 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…
http://poj.org/problem?id=1979 #include <cstdio> #include <cstring> using namespace std; const int maxn = 21; bool vis[maxn][maxn]; char maz[maxn][maxn]; int n,m; const int dx[4] = {1,-1,0,0}; const int dy[4] = {0,0,1,-1}; int ans; bool in(int…
题目链接:http://poj.org/problem?id=2378 一棵树,去掉一个点剩下的每棵子树节点数不超过n/2.问有哪些这样的点,并按照顺序输出. dfs回溯即可. //#pragma comment(linker, "/STACK:102400000, 102400000") #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring&…
http://poj.org/problem?id=1659 Frogs' Neighborhood Time Limit: 5000MS   Memory Limit: 10000K Total Submissions: 6050   Accepted: 2623   Special Judge Description 未名湖附近共有N个大小湖泊L1, L2, ..., Ln(其中包括未名湖),每个湖泊Li里住着一只青蛙Fi(1 ≤ i ≤ N).如果湖泊Li和Lj之间有水路相连,则青蛙Fi和…
题目:http://poj.org/problem?id=2531 题意:一个矩阵,分成两个集合,求最大的 阻碍量 改的 一位大神的代码,比较简洁 #include<stdio.h> #include<string.h> int n,max; ][]; ]; void dfs(int x,int sum) { int i,t=sum; v[x]=; ; i<=n; i++) { ) t+=g[x][i]; else t-=g[x][i]; } if(t>max) max…
题目:http://poj.org/problem?id=3009 参考博客:http://www.cnblogs.com/LK1994/ #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack> #include<queue> #include<iomanip> #include<cmath>…
题目: http://poj.org/problem?id=1129 开始没读懂题,看discuss的做法,都是循环枚举的,很麻烦.然后我就决定dfs,调试了半天终于0ms A了. #include <stdio.h> #include <string.h> ][], vis[][]; int n, ans; void calc() { ; ; i < ; i++) { ; j < n; j++) { if(vis[j][i]) { cnt++; break; } }…
题目链接:http://poj.org/problem?id=1979 思路分析:使用DFS解决,与迷宫问题相似:迷宫由于搜索方向只往左或右一个方向,往上或下一个方向,不会出现重复搜索: 在该问题中往四个方向搜索,会重复搜索,所以使用vis表来标记访问过的点,避免重复搜索. 代码如下: #include <iostream> using namespace std; ; int vis[MAX_N][MAX_N]; char map[MAX_N][MAX_N]; int red_count,…
思路:记录每行每列每一个宫已经出现的数字就可以.数据比較弱 另外POJ 3074 3076 必须用剪枝策略.但实现较麻烦,还是以后学了DLX再来做吧 //Accepted 160K 0MS #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> using namespace std; const int N =15; char sudo[N][N]; bool vi…
题目链接:http://poj.org/problem?id=1321 很久没有敲搜索了啊,今天敲了个水题练练手,哈哈.... 题目大意: 就是求在n*n的方格上放置k个棋子的方案数 代码: #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> using namespace std; int n,k; ][]; ]; int sum; int ans; bool Ju…
题目链接:http://poj.org/problem?id=1321 Time Limit: 1000MS Memory Limit: 10000K Description 在一个给定形状的棋盘(形状可能是不规则的)上面摆放棋子,棋子没有区别.要求摆放时任意的两个棋子不能放在棋盘中的同一行或者同一列,请编程求解对于给定形状和大小的棋盘,摆放k个棋子的所有可行的摆放方案C. Input 输入含有多组测试数据. 每组数据的第一行是两个正整数,n k,用一个空格隔开,表示了将在一个n*n的矩阵内描述…
题目链接:http://poj.org/problem?id=3764 Time Limit: 2000MS Memory Limit: 65536K Description In an edge-weighted tree, the xor-length of a path p is defined as the xor sum of the weights of edges on p: $_{xor}length(p) = \bigoplus_{e \in p}w(e)$ $\oplus$…
题目链接:http://poj.org/problem?id=3009 题意: 题目很复杂,直接抽象化解释了.给你一个w * h的矩形格子,其中有包含一个数字“2”和一个数字“3”,剩下的格子由“0”和“1”组成,目的是计算从“2”走到“3”的最短步数,“1”代表障碍物,“0”代表可以通行.“2”可以往周围四个方向走,如果往某一个方向走,那么停下来的条件是,当这个方向上存在障碍物“1”,且会停在这个障碍物的前一个格子,并会击碎这个障碍物;如果选择的方向上没有障碍物“1”也没有终点“3”,那么就会…
http://poj.org/problem?id=1481 The Die Is Cast Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 860   Accepted: 358 Description InterGames is a high-tech startup company that specializes in developing technology that allows users to play…
POJ - 2528 Mayor's posters 思路:分治思想. 代码: #include<iostream> #include<cstdio> #include<cstring> using namespace std; #define ll long long #define ls rt<<1,l,m #define rs rt<<1|1,m+1,r #define pb push_back const int INF=0x3f3f3f…
link:http://poj.org/problem?id=3087 题意:给你两串字串(必定偶数长),按照扑克牌那样的洗法(每次从S2堆底中拿第一张,再从S1堆底拿一张放在上面),洗好后的一堆可以把下面的一半作为S1,上面的一半作为S2,问能否洗出题目给出的最终字串. 思路:很好能够找到规律,就是先把两串合并,分别存a[i],a[i+n/2]到新串中,这个新串就是当前洗出的结果.因此进行DFS,由于给出的串长为偶数(?)所以必定能够洗回初始状态,所以出口就是初始串. /** @Date :…
Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 16202   Accepted: 4349 Description Given a M×N matrix A. Aij ∈ {0, 1} (0 ≤ i < M, 0 ≤ j < N), could you find some rows that let every cloumn contains and only contains one 1. Input There a…
题目传送门:http://poj.org/problem?id=1191 棋盘分割 Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16150   Accepted: 5768 Description 将一个8*8的棋盘进行如下分割:将原棋盘割下一块矩形棋盘并使剩下部分也是矩形,再将剩下的部分继续如此分割,这样割了(n-1)次后,连同最后剩下的矩形棋盘共有n块矩形棋盘.(每次切割都只能沿着棋盘格子的边进行) 原棋盘上每一格…
题目传送门:http://poj.org/problem?id=1416 Shredding Company Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6860   Accepted: 3710 Description You have just been put in charge of developing a new shredder for the Shredding Company Although a "…