题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3018 Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1658    Accepted Submission(s): 641 Problem Description Ant Country consist of N to…

Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,together with his friends,wants to go through every part…

Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 904    Accepted Submission(s): 338 Problem Description Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,to…

Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3660    Accepted Submission(s): 1455 Problem Description Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3018 题目大意:有n个点,m条边,人们希望走完所有的路,且每条道路只能走一遍.至少要将人们分成几组. 解题思路:先用并查集求出所有的连通块,然后判断每个连通块内点的度数,如果有奇数点则需要的组数ans+=奇数点/2:反之,所需组数ans+=1.注意:如果遇到孤立点即度数为0的点则不用算进去,因为没有跟他相连的边. 代码: #include<iostream> #include<cstdio&…

九野的博客,转载请注明出处:  http://blog.csdn.net/acmmmm/article/details/10858065 题意:n个点m条边的无向图,求用几笔可以把所有边画完(画过的边不再画) 思路: 并查集+欧拉回路 对于每个连通分量,若是欧拉回路则一笔画完,若不是则 需要: 奇度数点个数/2 然后把每个连通分量所需的笔数相加 这里要注意一个点是不用画的 #include<stdio.h> #include<algorithm> #include<iostr…

Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3524    Accepted Submission(s): 1393 Problem Description Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3018 思路分析:题目可以看做一笔画问题,求最少画多少笔可以把所有的边画一次并且只画一次: 首先可以求出该无向图中连通图的个数,在每个无向连通图中求出需要画的笔数再相加即为所求.在一个无向连通图中,如果所有的点的度数为偶数则存在一个欧拉回路, 则只需要画一笔即可:如果图中存在度数为奇数的点,则需要画的笔数为度数为奇数的点的个数 /2:需要注意的孤立的点不需要画: 代码如下: #include <cst…

HDU - 3018 Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,together with his friends,wants to go through every part of the country. They intend to visit every road , and every road must be visited for exact one time.Ho…

1530:Ant Trip [题目描述] 原题来自:2009 Multi-University Training Contest 12 - Host by FZU 给你无向图的 N 个点和 M 条边,保证这 M 条边都不同且不会存在同一点的自环边,现在问你至少要几笔才能所有边都画一遍.(一笔画的时候笔不离开纸) [输入] 多组数据,每组数据用空行隔开. 对于每组数据,第一行两个整数 N,M 表示点数和边数.接下去 M 行每行两个整数 a,b,表示 a,b 之间有一条边. [输出] 对于每组数据,…

Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2461    Accepted Submission(s): 965 Problem Description Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,t…

题目链接: Ant Trip Time Limit: 2000/1000 MS (Java/Others)     Memory Limit: 32768/32768 K (Java/Others) Problem Description   Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,together with his friends,wants to go through ev…

题意: Ant Tony和他的朋友们想游览蚂蚁国各地. 给你蚂蚁国的N个点和M条边,现在问你至少要几笔才能所有边都画一遍.(一笔画的时候笔不离开纸) 保证这M条边都不同且不会存在同一点的自环边. 也就是蚂蚁分组遍历整个无向图,他们试图把所有的人分成几个小组,每个小组可以从不同的城镇开始. Tony想知道最少需要几组.  Input输入包含多组测试用例,由多个空行分隔. 每个测试用例的第一行是两个整数N(1<=N<=100000).M(0<=M<=200000),表明蚂蚁国有N个城镇…

Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,together with his friends,wants to go through every part of the country. They intend to visit every road , and every road must be visited for exact one time.However,it ma…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3018 题目: Problem Description Ant Country consist of N towns.There are M roads connecting the towns. Ant Tony,together with his friends,wants to go through every part of the country. They intend to visit…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2425 Hiking Trip Description Hiking in the mountains is seldom an easy task for most people, as it is extremely easy to get lost during the trip. Recently Green has decided to go on a hiking trip. Unfort…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3018 题意:给你一个图,每条路只能走一次.问至少要多少个人才能遍历所有的点和所有的边. 这是之前没有接触过的知识点.设计欧拉图,不理解直接记住就好啦. 欧拉图:若图G中存在这样一条路径,使得它恰通过G中每条边一次,则称该路径为欧拉路径. 若该路径是一个圈,则称为欧拉(Euler)回路.具有欧拉回路的图称为欧拉图. 具有欧拉路径但不具有欧拉回路的图称为半欧拉图. 一个无向图存在欧拉回路,当且仅当该图所…

http://acm.hdu.edu.cn/showproblem.php?pid=1242 感觉题目没有表述清楚,angel的朋友应该不一定只有一个,那么正解就是a去搜索r,再用普通的bfs就能过了. 但是别人说要用优先队列来保证时间最优,我倒是没明白,步数最优跟时间最优不是等价的吗?就算士兵要花费额外时间,可是既然先到了目标点那时间不也一定是最小的? 当然用优先队列+ a去搜索r是最稳妥的. #include <cstdio> #include <cstring> #inclu…

Problem Description Hiking in the mountains is seldom an easy task for most people, as it is extremely easy to get lost during the trip. Recently Green has decided to go on a hiking trip. Unfortunately, half way through the trip, he gets extremely ti…

欧拉回路的题: 主要利用的是并查集,为了节省时间,压缩了它的路径: 代码: #include<cstdio> #include<cstring> #define maxn 100009 using namespace std; int f[maxn],rank[maxn],du[maxn]; bool vis[maxn],mark[maxn]; void make_set(int x) { f[x]=x; rank[x]=; } int find(int x) { int p=x,…

题意:给你一个图 判断最少用几笔把这个图画出来(画过的边不能重新画) 思路: 并查集+欧拉回路 仔细想一想. 在一个强连通分量中 所有度为奇数的点之和÷2就是要画的笔画数 Now question :如果这是个欧拉回路怎么办? +1就OK啦 答案就是奇度数的点÷2+欧拉回路的个数 // by SiriusRen #include <cstdio> #include <cstring> #define N 100500 using namespace std; int ans,n,m…

摘要:最近是不适合写代码么?忘记初始化wa到死<_=_=_>.唔--最近在学习图论,从基础搞起,先搞了拓扑排序和欧拉(回)路. Part 0. 拓扑排序 ==挖坑== Part 1. 欧拉(回)路 先判连通性 欧拉回路: 有向图:每个顶点入度等于出度 无向图:每个顶点度数都为偶数 欧拉路: 有向图:每个顶点入度等于出度,或者,一个顶点入度比出度大一,一个顶点入度比出度小一(起点),其余顶点入度等于出度 无向图:每个顶点度数都为偶数,或者,只有两个顶点度数为奇数 HDU 3018 Ant Tri…

欧拉路: 如果给定无孤立结点图G,若存在一条路,经过图中每边一次且仅一次,这条路称为欧拉路: 如果给定无孤立结点图G,若存在一条回路,经过图中每边一次且仅一次,那么该回路称为欧拉回路. 存在欧拉回路的图,称为欧拉图. 一. 对于无向图G,具有一条欧拉路,当且仅当G是连通的,且有零个或两个奇数度结点. 且有零个奇数度结点,存在欧拉回路:有两个奇数度结点,存在欧拉路. 判断无向图G是否连通,可以从任意结点出发,进行深度优先遍历,如果可以遍历到所有点,也可以用并查集,判断根节点的个数, 说明,图G连通…

转自——http://blog.csdn.net/qwe20060514/article/details/8112550 =============================以下是最小生成树+并查集======================================[HDU]1213   How Many Tables   基础并查集★1272   小希的迷宫   基础并查集★1325&&poj1308  Is It A Tree?   基础并查集★1856   More i…

=============================以下是最小生成树+并查集====================================== [HDU] 1213 How Many Tables 基础并查集★ 1272 小希的迷宫 基础并查集★ 1325&&poj1308 Is It A Tree? 基础并查集★ 1856 More is better 基础并查集★ 1102 Constructing Roads 基础最小生成树★ 1232 畅通工程 基础并查集★ 123…

=============================以下是最小生成树+并查集====================================== [HDU] 1213 How Many Tables 基础并查集★ 1272 小希的迷宫 基础并查集★ 1325&&poj1308 Is It A Tree? 基础并查集★ 1856 More is better 基础并查集★ 1102 Constructing Roads 基础最小生成树★ 1232 畅通工程 基础并查集★ 123…

转自:http://blog.csdn.net/shahdza/article/details/7779385 欧拉回路[HDU]1878 欧拉回路 判断3018 Ant Trip 一笔画问题1116 Play on Words2894 DeBruijin 兹鼓欧拉回路1956 Sightseeing tour 混合欧拉3472 HS BDC 混合欧拉=========================================================================…

http://acm.hdu.edu.cn/showproblem.php?pid=3018 Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3794    Accepted Submission(s): 1502 Problem Description Ant Country consist of N towns.Th…

=============================以下是最小生成树+并查集====================================== [HDU] How Many Tables 基础并查集★ 小希的迷宫 基础并查集★ &&poj1308 Is It A Tree? 基础并查集★ More is better 基础并查集★ Constructing Roads 基础最小生成树★ 畅通工程 基础并查集★ 还是畅通工程 基础最小生成树★ 畅通工程 基础最小生成树★ 畅通…

Ant Trip Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1107    Accepted Submission(s): 404 Problem Description Ant Country consist of N towns.There are M roads connecting the towns.Ant Tony,t…