题目就是给两个序列,第一个是排序前的,第二个是排序中的,判断它是采用插入排序还是堆排序,并且输出下一次操作后的序列. 插入排序的特点就是,前面是从小到大排列的,后面就与原序列相同. 堆排序的特点就是,后面是从小到大排列的最大的几个数p~n-1,前面第一位则是p-1. 所以只要先按照插入排序的特点来判断是否为插入排序,接下来再进行操作就可以了,这里要手动写下最大堆的更新操作. 代码: #include <iostream> #include <cstdio> #include <…
http://www.patest.cn/contests/pat-a-practise/1098 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data,…
1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. At each iteration, i…
简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; ; int a[maxn],b[maxn],n; int main()…
题意: 输入一个正整数N(<=100),接着输入两行N个数,表示原数组和经过一定次数排序后的数组.判断是经过插入排序还是堆排序并输出再次经过该排序后的数组(数据保证答案唯一). AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],b[]; ][]; int main(){ ios::sync_with_stdio(false); cin.tie(NUL…
题目 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted…
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted li…
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted li…
注意两点:1.系数也有可能加起来为负!!!一开始我if里面判断为>0导致有样例没过...2.如果最后所有指数的系数都为0,输出一个0即可,原本以为是输出 1 0 0.0... #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> using namespace std; ; double exps[maxn]; //exps[i]存储结果指数为i的项对…
博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6789157.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 题意:给出要查询的n个学生,k个课程接下来对于k门课,给出其id和学生数量,以及对应的学生名字租后给出n个查询的学生名字,让你输出其选的课程数量和对应的课程id,id从小到大排序. 题目简单,然而建立映射的想法不错~~推荐一开始发生段错误,才发现n的范围只是…