课本AC代码 #include <cstdio> struct Poly { int exp;//指数 double cof; } poly[1001];//第一个多项式 double ans[2001];//存放结果 int main() { #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif // ONLINE_JUDGE int n, m, number = 0; scanf…

A1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a po…

题目 This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​ ​​ N​2​​ a​…

This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a pol…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009 Product of Polynomials (25分)   This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polyno…

1009 Product of Polynomials (25 分)   This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polyn…

题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1009 分析:简单题.相乘时指数相加,系数相乘即可,输出时按指数从高到低的顺序.注意点:多项式相乘后指数最高可达2000. 题目描述: This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test…

This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, wh…

This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N​1​​ a​N​1​​​​ N​2​​ a​N​2​…

简单模拟. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> using namespace std; ],b[],c[]; int k; int main() { ;i<=;i++) a[i]=b[i]=c[i]=; ; scanf("%d",&k); ;i<=k;i++) {…

多项式相乘 注意相乘结果的多项式要开两倍的大小!!! #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <string.h> using namespace std; //两个多项式相乘 +; int k; //原本定义个exp导致编译错误,没想到定义成exp1.exp2也会编译错误,估计引起函数名冲突了 double ex…

题意: 给出两个多项式,计算两个多项式的积,并以指数从大到小输出多项式的指数个数,指数和系数. trick: 这道题数据未知,导致测试的时候发现不了问题所在. 用set统计非零项时,通过set.size()输出非零项个数,set.count()与否来判断是否输出该项时结果第0个测试点答案错误. 用fabs(mp[i])>=0.05时结果全部正确,因为考虑到保留1位小数所以用这个语句来判断保留小数后是否非零. 问题是当去掉fabs()时采用mp[i]>=0.05结果第0个测试点答案错误. 而不管…

This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, wh…

problem This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 a~N1~ N2 a~N2~ ..…

This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, wher…

#include <stdio.h> struct MyStruct { int exp; double coe; }; int main() { int k1,k2,i,j; MyStruct ans1[],ans2[]; ]; //两个 最高幂相乘 , 最高幂为2000 while(scanf("%d",&k1)!=EOF) { ;i<=;i++) dans[i]=0.0; ;i<k1;i++) scanf("%d%lf",&am…

#include<iostream> using namespace std; struct { int a; double b; }poly[1001]; double a[2001];//至少2000个位置 int main(){ int n,m,cnt=0,aa; double bb; cin>>n; for(int i=0;i<n;i++){ cin>>poly[i].a>>poly[i].b; } cin>>m; for(int…

1009 Product of Polynomials (25)(25 分) This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a pol…

1009. Product of Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A*B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case oc…

1009 Product of Polynomials (25 分) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynom…

题目 1009 Product of Polynomials (25 point(s)) This time, you are supposed to find A×B where A and B are two polynomials. Input Specification: Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of…

PAT (Advanced Level) Practice 1002 A+B for Polynomials (25 分) 凌宸1642 题目描述: This time, you are supposed to find A+B where A and B are two polynomials. 译:这一次,你要找到 A + B ,其中 A , B 是两个多项式 Input Specification (输入说明): Each input file contains one test case…

1002. A+B for Polynomials (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, an…

1002. A+B for Polynomials (25) This time, you are supposed to find A+B where A and B are two polynomials. Input Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN…