CF 429B B.Working out 四个角递推

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CF 429B B.Working out 四个角递推

B. Working outtime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputSummer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where they go is a…

Code Force 429B Working out【递推dp】

Summer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where they go is a matrix a with n lines and mcolumns. Let number a[i][j] represents the calories burned by performing workout at the…

Android 二维码扫描框加四个角及中间横线自动下滑

红色为加四个角黄色为扫描线自动下滑 /* * Copyright (C) 2008 ZXing authors * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http:/…

unity3d 获取相机视口四个角的坐标

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[转]JAVA 根据经纬度算出附近的正方形的四个角的经纬度

csv文件转化为geojson文件中,涉及到路测图的打点生成,打点是由一个个正方形组成,而正方形是由四个点组成的,这四个点根据经纬度和范围生成,具体的实现代码是从网上找来的: /** * * @param longitude 经度 * @param latitude 纬度 * @param distance 范围(米) * @return */ public static Map<String, double[]> returnLLSquarePoint(double longitude, d…

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四角递推(CF Working out,动态规划递推)

题目:假如有A,B两个人,在一个m*n的矩阵,然后A在(1,1),B在(m,1),A要走到(m,n),B要走到(1,n),两人走的过程中可以捡起格子上的数字,而且两人速度不一样,可以同时到一个点(哪怕这个点离A很近,离B很远),现在A,B起码相遇于一个点点,相遇点的数字A,B都得不到,求最后A,B总数字之和的最大值 B. Working out Summer is coming! It's time for Iahub and Iahubina to work out, as they both…

cf 429B Working out（简单dp）

B. Working out time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Summer is coming! It's time for Iahub and Iahubina to work out, as they both want to look hot at the beach. The gym where the…

GMap获取可视范围内四个角的坐标

原理: 先获取控件的四个顶点,逐一将其转换成经纬度坐标. private void GetBonds() { //左上↖ PointLatLng pLeftTop = map1.FromLocalToLatLng(map1.Left, map1.Top); //左下↙ PointLatLng pLeftDown = map1.FromLocalToLatLng(map1.Left, map1.Top + map1.Height); //右上↗ PointLatLng pRightTop = ma…