题目链接: Problem - B - Codeforces 题目 Example input 4 3 1 1 1 5 1 2 3 4 5 5 0 2 0 3 0 4 1 3 5 1 output 6 0 36 4 题意 给一串数,用这n个数排几种序列,使得 i=1~(n-1) 输出有几种序列满足情况 题解 附  : & -- 位运算之一,有0则0 不用怀疑,一堆数&完后,得到的数<=这堆数的任意一个数 因为每一位只要有一个数==0,这一位就=0,否则为1 记最后&完所有数的…

C. Vus the Cossack and Strings Vus the Cossack has two binary strings, that is, strings that consist only of "0" and "1". We call these strings aa and bb. It is known that |b|≤|a||b|≤|a|, that is, the length of bb is at most the length…

题意:给你一组数,求有多少对\((i,j)\),使得\(a_{i}\)&\(a_{j}\ge a_{i}\ xor\ a_{j}\). 题解:对于任意两个数的二进制来说,他们的最高位要么相同要么不相同,如果相同,那么肯定是满足题目条件的,因为异或是不进位的加法,所以我们只要找到所有最高位相同的数的个数,用桶存下来,然后再对他们求个和就行了. 代码: int t; int n; ll x; map<ll,ll> mp; int main() { ios::sync_with_stdio(…

题目传送门 /* 数学:这题一直WA在13组上,看了数据才知道是计算cost时超long long了 另外不足一个区间的直接计算个数就可以了 */ #include <cstdio> #include <cmath> #include <iostream> #include <algorithm> #include <cstring> using namespace std; typedef unsigned long long ull; int…

地址:http://codeforces.com/contest/768/problem/D 题目: D. Jon and Orbs time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Jon Snow is on the lookout for some orbs required to defeat the white wal…

地址:http://codeforces.com/contest/768/problem/C 题目: C. Jon Snow and his Favourite Number time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output Jon Snow now has to fight with White Walkers. He has…

地址:http://codeforces.com/contest/768/problem/B 题目: B. Code For 1 time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Jon fought bravely to rescue the wildlings who were attacked by the white-w…

地址:http://codeforces.com/problemset/problem/768/A 题目: A. Oath of the Night's Watch time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output "Night gathers, and now my watch begins. It shall not end…

C题卡了好久,A掉C题之后看到自己已经排在好后面说实话有点绝望,最后又过了两题,总算稳住了. AC:ABCDE Rank:191 Rating:2156+37->2193 A.Oath of the Night's Watch 题目大意:给定N个数,求有多少个数存在严格比它大的数和严格比它小的数.(N<=100,000) 思路:阅读能力训练+手速,排序一遍就没了. #include<cstdio> #include<cstring> #include<algori…

思路:把边看成点,然后每条边只能从下面的边转移过来,我们将边按照u为第一关键字,w为第二关键字排序,这样就能用线段树维护啦. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define pii pair<int,int> using namespace std; ; + ; const int inf = 0x3f3f3f3f…