t记录每个格子最早被砸的时间,bfs(x,y,t)表示当前状态为(x,y)格子,时间为t.因为bfs,所以先搜到的t一定小于后搜到的,所以一个格子搜一次就行 #include<iostream> #include<cstdio> #include<queue> using namespace std; const int N=505,inf=1e9,dx[]={-1,1,0,0,0},dy[]={0,0,-1,1,0}; int n,m,t[N][N]; bool v[…
POJ 3669 Meteor Shower(流星雨) Time Limit: 1000MS Memory Limit: 65536K Description 题目描述 Bessie hears that an extraordinary meteor shower is coming; reports say that these meteors will crash into earth and destroy anything they hit. Anxious for her sa…