作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目大意 题目大意 解题方法 递归 记忆化搜索 动态规划 空间压缩DP 日期 [LeetCode] 题目地址:https://leetcode.com/problems/climbing-stairs/ Total Accepted: 106510 Total Submissions: 290041 Difficulty: Easy 题目大意 You are climbing a…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 日期 题目地址:https://leetcode.com/problems/min-cost-climbing-stairs/description/ 题目描述 On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Onc…

[LeetCode]120. Triangle 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址https://leetcode.com/problems/triangle/description/ 题目描述: Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjac…

70. Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. 思路:到第n个台阶的迈法种数＝到第n-1个台…

题目描述 假设你正在爬楼梯.需要 n 阶你才能到达楼顶. 每次你可以爬 1 或 2 个台阶.你有多少种不同的方法可以爬到楼顶呢? 注意:给定 n 是一个正整数. 示例 1: 输入: 2 输出: 2 解释: 有两种方法可以爬到楼顶. 1. 1 阶 + 1 阶 2. 2 阶 示例 2: 输入: 3 输出: 3 解释: 有三种方法可以爬到楼顶. 1. 1 阶 + 1 阶 + 1 阶 2. 1 阶 + 2 阶 3. 2 阶 + 1 阶 思路 思路一: 递归 思路二: 用迭代的方法,用两个变量记录f(n-…

lc 70 Climbing Stairs 70 Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. D…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/ransom-note/ Difficulty: Easy 题目描述 Given an arbitrary ransom note string and another string containing letters…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/distribute-candies/#/description 题目描述 Given an integer array with even length, where different numbers in this array repre…

Climbing Stairs  You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 思路:题目也比較简单.类似斐波那契. 代码例如以下: public class Solution { public int climb…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanation:…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanation:…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 设置当前节点的值为下一个 日期 [LeetCode] 题目地址:https://leetcode.com/problems/delete-node-in-a-linked-list/ Total Accepted: 78258 Total Submissions: 179086 Difficulty: Easy 题目描述 Write a functio…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:Java解法,HashSet 方法二:Python解法,set 日期 [LeetCode] 题目地址:https://leetcode.com/problems/intersection-of-two-arrays/ Difficulty: Easy 题目描述 Given two arrays, write a function to com…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 异或 字典 日期 [LeetCode] 题目地址:https://leetcode.com/problems/single-number/ Total Accepted: 183838 Total Submissions: 348610 Difficulty: Easy 题目描述 Given a non-empty array of integers…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:首尾指针 方法二:头部双指针+双循环 方法三:指针指向第一个0的位置 日期 题目地址:https://leetcode.com/problems/move-zeroes/ Total Accepted: 77443 Total Submissions: 175420 Difficulty: Easy 题目描述 Given an array n…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历子串 日期 [LeetCode] 题目地址:https://leetcode.com/problems/repeated-substring-pattern/ Difficulty: Easy 题目描述 Given a non-empty string check if it can be constructed by taking a subs…

题目描述: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 解题思路: 利用DP的方法,一个台阶的方法次数为1次,两个台阶的方法次数为2个.n个台阶的方法可以理解成上n-2个台阶,然后2步直接上最后一步:或者上n-1…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 回溯法 日期 题目地址:https://leetcode.com/problems/subsets/description/ 题目描述 Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution se…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 方法一:库函数 方法二:递归 方法三:回溯法 日期 题目地址:https://leetcode.com/problems/permutations/description/ 题目描述 Given a collection of distinct numbers, return all possible permutations. For example, [1,…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS 日期 题目地址:https://leetcode.com/problems/minesweeper/description/ 题目描述 Let's play the minesweeper game (Wikipedia, online game)! You are given a 2D char matrix representing th…

翻译 你正在爬一个楼梯. 它须要n步才干究竟顶部. 每次你能够爬1步或者2两步. 那么你有多少种不同的方法爬到顶部呢? 原文 You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 分析 动态规划基础题,首先设置3个变量用于…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 栈 递归 数组 日期 题目地址:https://leetcode-cn.com/problems/cong-wei-dao-tou-da-yin-lian-biao-lcof/ 题目描述 输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回). 示例 1: 输入:head = [1,3,2] 输出:[2,3,1] 限制: 0 <= 链表长度 <=…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/h-index/description/ 题目描述: Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 日期 题目地址:https://leetcode.com/problems/heaters/ 题目描述 Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:递归 方法二:回溯法 日期 题目地址:https://leetcode.com/problems/combinations/description/ 题目描述 Given two integers n and k, return all possible combinations of k numbers out of 1 - n. For…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Input: 2 Output: 2 Explanation: There are…

题目: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanat…

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanation:…

其实就是斐波那契数列 参考dp[n] = dp[n-1] +dp[n-2]; class Solution { public: int climbStairs(int n) { ; ; ; ; i < n; ++i){ f3 = f2 + f1; f1 = f2; f2 = f3; } return f3; } };…

[思路] a.因为两种跳法,1阶或者2阶,那么假定第一次跳的是一阶,那么剩下的是n-1个台阶,跳法是f(n-1); b.假定第一次跳的是2阶,那么剩下的是n-2个台阶,跳法是f(n-2) c.由a.b假设可以得出总跳法为: f(n) = f(n-1) + f(n-2) d.然后通过实际的情况可以得出:只有一阶的时候 f(1) = 1 ,只有两阶的时候可以有 f(2) = 2 e.可以发现最终得出的是一个斐波那契数列. 由于直接用递归会超时,于是用数组来存储每一个位置的走法数目.代码如下: cla…