LeetCode-268-丢失的数字】的更多相关文章

GridView导出成Excel字符"0"丢失/数字丢失的处理方式 收藏 GridView 导出成Excel文件,这个代码在网上比较多.但是发现存在一个问题,导出的数据中如果有"012457890"的内容,用Excel打开后就变成 了"12457890",少了前面的0;原因是Excel把它当作数字来格式化了,就把"0"给去掉了.   解决思路:在Excel中作一个包含有"012457890"的内容,设定单元…
丢失的数字 Time Limit: 1000 ms Memory Limit: 64 MB Total Submission: 1552 Submission Accepted: 273 Description 有N个数字是来自一个长度为N+1的连续整数序列,但是给你的并不是有序的,请你帮忙找出来是缺失的那个数字是在序列的两边还是中间 Input 有多组测试数据,每组测试数据包括2行,第一行包括一个整数N(0 Output 每组测试数据输出结果: 中间缺失输出M,两边缺失输出S Sample I…
转载:http://www.cnblogs.com/grandyang/p/4756677.html Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in li…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it u…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. Example 1 Input: [3,0,1] Output: 2 Example 2 Input: [9,6,4,2,3,5,7,0,1] Output: 8 Note:Your algorithm should run in linear runtime c…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi…
268. 缺失数字 给定一个包含 0, 1, 2, -, n 中 n 个数的序列,找出 0 - n 中没有出现在序列中的那个数. 示例 1: 输入: [3,0,1] 输出: 2 示例 2: 输入: [9,6,4,2,3,5,7,0,1] 输出: 8 说明: 你的算法应具有线性时间复杂度.你能否仅使用额外常数空间来实现? PS:位运算 class Solution { public int missingNumber(int[] nums) { int res = nums.length; for…
给定一个包含 0, 1, 2, ..., n 中 n 个数的序列,找出 0 .. n 中没有出现在序列中的那个数. 示例 1: 输入: [3,0,1] 输出: 2 示例 2: 输入: [9,6,4,2,3,5,7,0,1] 输出: 8 说明: 你的算法应具有线性时间复杂度.你能否仅使用额外常数空间来实现? 思路 因为给定的序列也是从0开始,所以可以进行排序,比较索引和索引对应的值,如果两个不等于说明就确实一个值了,还要注意一个情况是,没出现的数字是n 代码 class Solution(obje…
转载:https://leetcode.windliang.cc/leetCode-35-Search-Insert-Position.html    思路 Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume n…
题目: Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. Example 1: Input: [3,0,1] Output: 2 Example 2: Input: [9,6,4,2,3,5,7,0,1] Output: 8 Note:Your algorithm should run in linear run…
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Follow up: Could you do it without an…
Validate if a given string is numeric. Some examples:"0" => true" 0.1 " => true"abc" => false"1 a" => false"2e10" => true Note: It is intended for the problem statement to be ambiguous. You…
需要注意overflow,特别是Integer.MIN_VALUE这个数字. 需要掌握二分法. 不用除法的除法,分而治之的乘方 2. Add Two Numbers You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the tw…
We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself. Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not. Example: Input:…
写在前面 前面研究OS的经历实在是令人心力憔悴..所以换个新鲜的,把自己的刷题感悟整理一番.刷了有些题了,就先拿最近几天hard题打头阵吧.首先说的是(065)Valid Number这个题,其实一眼看起来很简单,不就是for/while/if/else吗?那么你可能不知道这道题其实有一个更加简(bian)洁(tai)的方法,听我慢慢道来. 题目要求 Validate if a given string is numeric. Some examples: "0" => true…
小A 和 小B 在玩猜数字.小B 每次从 1, 2, 3 中随机选择一个,小A 每次也从 1, 2, 3 中选择一个猜.他们一共进行三次这个游戏,请返回 小A 猜对了几次? 输入的guess数组为 小A 每次的猜测,answer数组为 小B 每次的选择.guess和answer的长度都等于3. 示例 1: 输入:guess = [1,2,3], answer = [1,2,3] 输出:3 解释:小A 每次都猜对了. 示例 2: 输入:guess = [2,2,3], answer = [3,2,…
题目描述: Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement…
Missing Number Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you…
X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X.  Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after rotat…
1.题目描述 X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. Each digit must be rotated - we cannot choose to leave it alone.  A number is valid if each digit remains a digit afte…
1.题目大意 Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements. For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0]. Not…
题意: 给出一个整数n,判断其是否为幸运数. 规则是,将n按十进制逐位拆出来后,每个位各自进行取平方,再将这些平方数求和作为新的数字n.若最后n=1,就是幸运数. 思路: 计算例子:n=47,接着n=4*4+7*7=65,接着n=6*6+5*5=61,接着.... 注意有可能陷入无限循环,就是迭代的过程产生了一个环路,即n又重复出现了. class Solution { public: bool isHappy(int n) { unordered_set<int> sett; ) { if(…
地址 https://leetcode-cn.com/problems/hexspeak/ 题目描述字母大写的十六进制字符串,然后将所有的数字 0 变成字母 O ,将数字 1  变成字母 I . 如果一个数字在转换后只包含 {“A”, “B”, “C”, “D”, “E”, “F”, “I”, “O”} ,那么我们就认为这个转换是有效的. 给你一个字符串 num ,它表示一个十进制数 N,如果它的十六进制魔术数字转换是有效的,请返回转换后的结果,否则返回 “ERROR” . 示例 : 输入:nu…
最近在项目中遇到一个问题,js中传带有数字的参数时,如果参数开头有数字0,会把0给去掉. 例如: 方法abc(0123456,789); 方法abc中获取的参数0123456就会变为123456. 原因推测: 由于js对数据类型没有一个具体的声明,传入的数值有可能被其默认当中数字  而将多余的0给自动去除了. 当参数含有0的时候,如果没有对它进行处理,自动会去0, 可能js认为其是一个整数 有时候发现数字不仅抹去开头的0,也会发生改变 例如: onclick="test(036)",…
双指针最基础的题目是一个区间里找两个数字的和等于Target.首先将区间从小到大排序.接下来只要一个le指针,一个ri指针,分别从区间左右边界往中间推进即可.复杂度是排序的nlogn. 下面几道题都是一个区间里找三个数字的和满足xx条件的.这个题目的做法首先还是先排序.之后先固定一个数字,然后在该数字的右侧区间内重新使用之前找两个数字的和的算法. 即i 从0到n-1,j 从i+1开始增加,k 从n-1开始减小直到j和k碰撞.这样的复杂度是n平方.外层i从0到n-1是O(n),内层从i+1到n-1…
给定一个仅包含数字 2-9 的字符串,返回所有它能表示的字母组合.给出数字到字母的映射如下(与电话按键相同).注意 1 不对应任何字母. class Solution { List<String> temp=new ArrayList<String>(); Map<String,String> map=new HashMap<String,String>(){{ put("2","abc"); put("3&…
754. 到达终点数字 在一根无限长的数轴上,你站在0的位置.终点在target的位置. 每次你可以选择向左或向右移动.第 n 次移动(从 1 开始),可以走 n 步. 返回到达终点需要的最小移动次数. 示例 1: 输入: target = 3 输出: 2 解释: 第一次移动,从 0 到 1 . 第二次移动,从 1 到 3 . 示例 2: 输入: target = 2 输出: 3 解释: 第一次移动,从 0 到 1 . 第二次移动,从 1 到 -1 . 第三次移动,从 -1 到 2 . 注意:…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it u…
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example,Given nums = [0, 1, 3] return 2. Note:Your algorithm should run in linear runtime complexity. Could you implement it usi…
题意:先将0, 1, 2, ..., n放入数组,然后去掉其中一个值,找到那个值. 这题与singe number 是一个类型,变形的地方就是首先需要将0, 1, 2, ..., n再次放入这个数组,这样就和singe number 一样. class Solution { public: int missingNumber(std::vector<int>& nums) { ; ; i < nums.size(); ++i){ ans ^= nums[i]; } ; i <…