Poj 3062 Celebrity jeopardy】的更多相关文章

1.Link: http://poj.org/problem?id=3062 2.Content: Celebrity jeopardy Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15015   Accepted: 8471 Description It's hard to construct a problem that's so easy that everyone will get it, yet still…
It's hard to construct a problem that's so easy that everyone will get it, yet still difficult enough to beworthy of some respect. Usually, we err on one side or the other. How simple can a problem really be? Here, as in Celebrity Jepoardy, questions…
下次不要被长题目吓到,其实不一定难. 先看输入输出,再揣测题意. 原文: 2548.   Celebrity jeopardy Time Limit: 1.0 Seconds   Memory Limit: 65536KTotal Runs: 1306   Accepted Runs: 898 It's hard to construct a problem that's so easy that everyone will get it, yet still difficult enough…
题目链接:http://poj.org/problem?id=3026 Svenskt Masterskap我程序员/ Norgesmesterskapet 2001 Description The Borg is an immensely powerful race of enhanced humanoids from the delta quadrant of the galaxy. The Borg collective is the term used to describe the g…
2-SAT的入门题. a,a',b,b'分别表示两对夫妇,如果a,b有矛盾,那么a要来,就只能来b',b要来,就只能来a'.于是建了两条边(a,b'),(b,a'). 用tarjan强连通分量缩点染色后,如果同一对夫妇染色相同,说明两个要么都来,要么都不来,就不可能有解了.否则,形成的强连通分量中必定是对称的(abc是强连通分量,那么a'b'c'也会在一个强连通分量里),于是只要选择几个强连通分量就可以每个集合都选1个. #include <cstdio> #include <cstri…
以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…
感谢范意凯.陈申奥.庞可.杭业晟.王飞飏.周俊豪.沈逸轩等同学的收集整理.   题号:1003 Hangover求1/2+1/3+...1/n的和,问需多少项的和能超过给定的值 类似于Zerojudge a625 题号:1004 Financial Management 求12个实数的平均值   题号:1008 Maya Calendar 玛雅历 此题语言可选中文 PS:注意Haab历的日期是从0开始,而Tzolkin历的日期是从1开始   题号:1067 取石子游戏 此题语言为中文 PS:请百…
2992.357000 1000 A+B Problem1214.840000 1002 487-32791070.603000 1004 Financial Management880.192000 1003 Hangover792.762000 1001 Exponentiation752.486000 1006 Biorhythms705.902000 1005 I Think I Need a Houseboat686.540000 1011 Sticks647.566000 1007…
一条边<u,v>表示u选那么v一定被选. #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> using namespace std; ; ; struct EDGE{int to,next;}edge[Maxm]; int T,m,Stack[Maxn],head[Maxn],Belong[Maxn],Id[Maxn],Dfn[Maxn],L…
转自——http://blog.csdn.net/qwe20060514/article/details/8112550 =============================以下是最小生成树+并查集======================================[HDU]1213   How Many Tables   基础并查集★1272   小希的迷宫   基础并查集★1325&&poj1308  Is It A Tree?   基础并查集★1856   More i…