原文题目: 447. Add Strings 解题: 字符串的当做整数来做加法,其实就是大数加法的简化版本 思路: 1)考虑不同位数,如"1234"+“45”,需要先处理低两位,再处理num1的高两位 2)考虑进位,相加大于10时就要进位,进位值 = sum/10: 3)考虑最高位的进位,如“5099”+“4987”最后得到了五位的“10086” AC代码: class Solution { public: string addStrings(string num1, string n…

415. Add Strings Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain…

这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…

problem 415. Add Strings solution: class Solution { public: string addStrings(string num1, string num2) { ; ; ; string res = ""; || j>= || carry) { )?:(num1[i--]-)?:(num2[j--]-')) + carry;//注意运算符的优先级顺序. carry = tmp/; res = to_string(tmp%) + r…

LeetCode--Add Strings Question Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 doe…

415. Add Strings Easy Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not con…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

原题链接在这里:https://leetcode.com/problems/add-strings/ 题目: Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9.…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

［抄题］: 以字符串的形式给出两个非负整数 num1 和 num2,返回 num1和 num2 的和. 比如一个50位+一个100位. 给定 num1 = "123",num2 = "45" 返回 "168" [暴力解法]: 时间分析: 空间分析: ［思维问题］: ［一句话思路］: ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: sum求和或者循环退出的条件都是i j &g…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/add-strings/ Difficulty: Easy 题目描述 Given two non-negative integers num1 and num2 represented as string, return the sum of num1…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

没什么限定的话,先翻转,在一位一位加,记得进位就行了.. public class Solution { public String addStrings(String num1, String num2) { StringBuilder sb = new StringBuilder(num1); num1 = sb.reverse().toString(); sb = new StringBuilder(num2); num2 = sb.reverse().toString(); if(num…

Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

这是悦乐书的第223次更新,第236篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第90题(顺位题号是415).给定两个非负整数num1和num2表示为字符串,返回num1和num2的总和. 注意: num1和num2的长度均<5100. num1和num2都只包含数字0-9. num1和num2都不包含任何前导零. 您不能使用任何内置BigInteger库或直接将输入转换为整数. 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 6…

Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

1.题目描述 2.问题分析 直接按照加法运算规则运算即可,注意进位问题. 3.代码 string addStrings(string num1, string num2) { if( num1.empty() ) return num2; if( num2.empty() ) return num1; string::reverse_iterator it1 = num1.rbegin() ; string::reverse_iterator it2 = num2.rbegin() ; stri…

题目描述: 解决思路: 此题较简单,和前面[LeetCode67]方法一样. Java代码: public class LeetCode415 { public static void main(String[] args) { String a="1",b="9"; System.out.println(a+"和"+b+"相加的结果是:"+new Solution().addStrings(a, b)); } } class…

给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和.注意:    num1 和num2 的长度都小于 5100.    num1 和num2 都只包含数字 0-9.    num1 和num2 都不包含任何前导零.    你不能使用任何內建 BigInteger 库, 也不能直接将输入的字符串转换为整数形式.详见:https://leetcode.com/problems/add-strings/description/C++: class Solution { public:…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3873 访问. 给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和. 注意: num1 和num2 的长度都小于 5100. num1 和num2 都只包含数字 0-9. num1 和num2 都不包含任何前导零. 你不能使用任何內建 BigInteger 库, 也不能直接将输入的字符串转换为整数形式. Given two non-negative…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…

Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…

题目描述: 解题思路: 此题的思路简单,下面的代码用StringBuilder更加简单,注意最后的结果要反转过来.[LeetCode415]Add Strings的解法和本题一模一样. java代码: public class LeetCode67 { public static void main(String[] args) { String a="11",b="1"; System.out.println(a+"和"+b+"相加的…

Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

43. 字符串相乘 43. Multiply Strings 题目描述 给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. LeetCode43. Multiply Strings中等 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456&q…