You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10259    Accepted Submission(s): 5074 Problem Description Many geometry(几何)problems were designed in the ACM/…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=1086 You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7167    Accepted Submission(s): 3480 Problem Description Ma…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6425    Accepted Submission(s): 3099 Problem Description Many geometry(几何)problems were designed in the ACM/I…

Shape of HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4972    Accepted Submission(s): 2250 Problem Description 话说上回讲到海东集团推选老总的事情,最终的结果是XHD以微弱优势当选,从此以后,“徐队”的称呼逐渐被“徐总”所取代,海东集团(HDU)也算是名副其实了.…

最大三角形 Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4015    Accepted Submission(s): 1433 Problem Description 老师在计算几何这门课上给Eddy布置了一道题目,题目是这样的:给定二维的平面上n个不同的点,要求在这些点里寻找三个点,使他们构成的三角形拥有的面积最大.Eddy对这道…

Shape of HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7797    Accepted Submission(s): 3526 Problem Description 话说上回讲到海东集团推选老总的事情,最终的结果是XHD以微弱优势当选,从此以后,"徐队"的称呼逐渐被"徐总"所取代,海东集…

Problem How Many Triangles (HDU 5784) 题目大意 给定平面上的n个点(n<2000),询问可以组成多少个锐角三角形. 解题分析 直接统计锐角三角形较困难,考虑问题的反面,统计直角三角形.钝角三角形.平角三角形(暂时这么叫吧QAQ). 首先枚举三角形的一个端点A,对其他点进行象限为第一关键字,极角为第二关键字排序. 然后使用三个指针,进行O(n)的扫描. 具体做法为用 i 指针指向三角形的第二个端点B.我们可以假想通过平移和旋转,把A点置于平面直角坐标系的原点,…

昨天用vim练了一道大水题,今天特地找了道稍难一点的题.不过也不是很难,简单的计算几何而已.练习用vim编码,用gdb调试,结果居然1A了,没调试...囧... 做法很简单,无非就是两种情况:①三个巫师构成一个钝角(极限情况是直角)三角形,那么所画的圆应该是钝角所对边为直径的圆:②三个巫师构成一个锐角三角形,那么所画的圆应该是三角形的外接圆. 就这样纸,上了点模板,代码如下: /* * Author : ben */ #include <cstdio> #include <cstdlib…

pid=1086">You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6997    Accepted Submission(s): 3385 Problem Description Many geometry(几何)problems were designe…

题目链接[http://acm.hdu.edu.cn/showproblem.php?pid=6206] 题意: 给出不共线的三个点,和一个点(x,y),然后判断(x,y)在不在这三个点组成的圆外. 题解: 咋一看很简单,实际也很简单,但是坐标都很大,会爆long double,怎么办?只有用java了. 公式: a = ((y2 - y1) * (y3 * y3 - y1 * y1 + x3 * x3 - x1 * x1) - (y3 - y1) * (y2 * y2 - y1 * y1 +…

openGL Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 170    Accepted Submission(s): 77 Problem Description Jiaoshou selected a course about “openGL” this semester. He was quite interested in m…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 48729    Accepted Submission(s): 12823 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

Surround the Trees Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10403    Accepted Submission(s): 4033 Problem Description There are a lot of trees in an area. A peasant wants to buy a rope to…

Lifting the Stone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7674    Accepted Submission(s): 3252 Problem Description There are many secret openings in the floor which are covered by a big…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10204    Accepted Submission(s): 5042 Problem Description Many geometry(几何)problems were designed in the ACM/…

Save Labman No.004 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 979    Accepted Submission(s): 306 Problem Description Due to the preeminent research conducted by Dr. Kyouma, human beings ha…

传送门:You can Solve a Geometry Problem too 题意:给n条线段,判断相交的点数. 分析:判断线段相交模板题,快速排斥实验原理就是每条线段代表的向量和该线段的一个端点与 另一条线段的两个端点构成的两个向量求叉积,如果线段相交那么另一条线段两个端点必定在该线段的两边,则该线段代表的向量必定会顺时针转一遍逆时针转一遍,叉积必定会小于等于0,同样对另一条线段这样判断一次即可. #include <algorithm> #include <cstdio>…

题意:求三角形内∠MPB+∠APC=∠MPC+∠APB的轨迹长度- - 1.基于M的中垂线       2.三角形内的圆弧(比赛只有看自己能否猜中),ps.以下是别人家的证明 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <vector> #include <queue> #include <set…

题目:给出一些线段,判断有几个交点. 问题:如何判断两条线段是否相交? 向量叉乘(行列式计算):向量a(x1,y1),向量b(x2,y2): 首先我们要明白一个定理:向量a×向量b(×为向量叉乘),若结果小于0,表示向量b在向量a的顺时针方向:若结果大于0,表示向量b在向量a的逆时针方向:若等于0,表示向量a与向量b平行.(顺逆时针是指两向量平移至起点相连,从某个方向旋转到另一个向量小于180度).如下图: 在上图中,OA×OB = 2 > 0, OB在OA的逆时针方向:OA×OC = -2 <…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11918    Accepted Submission(s): 5908 Problem Description Many geometry(几何)problems were designed in the ACM/…

A.GPA(HDU4802): 给你一些字符串对应的权重,求加权平均,如果是N,P不计入统计 GPA Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1193    Accepted Submission(s): 743 Problem Description In college, a student may take several…

思路:将飞机看成不动的,然后枚举时间看点是否在多边形内部. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PII pair<int, int> #define PLI pair<LL, int> #define ull unsigned long long using namespace std; +…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6932    Accepted Submission(s): 3350 Problem Description Many geometry(几何)problems were designed in the ACM/I…

Segment set Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4479    Accepted Submission(s): 1672 Problem Description A segment and all segments which are connected with it compose a segment set.…

链接:传送门 题意:给出 n 个线段找到交点个数 思路:数据量小,直接暴力判断所有线段是否相交 /************************************************************************* > File Name: hdu1086.cpp > Author: WArobot > Blog: http://www.cnblogs.com/WArobot/ > Created Time: 2017年05月07日 星期日 23时34…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13549    Accepted Submission(s): 6645 Problem Description Many geometry(几何)problems were designed in the ACM/…

HDU 1000 A + B Problem  I/O HDU 1001 Sum Problem  数学 HDU 1002 A + B Problem II  高精度加法 HDU 1003 Maxsum  贪心 HDU 1004 Let the Balloon Rise  字典树,map HDU 1005 Number Sequence  求数列循环节 HDU 1007 Quoit Design  最近点对 HDU 1008 Elevator  模拟 HDU 1010 Tempter of th…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6837 Accepted Submission(s): 3303 Problem Description Many geometry(几何)problems were designed in the ACM/ICPC. A…

HDU 3629 计算几何 题目描述:给你n个点(4~700), 问你能够成多少个不同的凸四边形. 解题报告: 暴力的话C(700,4)必然超时,发现,任何一个凹包必然是其中一点在其它3点构成的三角形内. 然后就考虑,能不能求出所有凹包的个数,然后用总数C(n, 4)减去凹包的个数,就是答案. 依次枚举每个点i,看看其它点能够成多少个包括点i的三角形,就是以这个点为中心的凹包的个数. 找三角形也要一定的技巧,也是通过逆向思维:找出有多少个三角形不包括点i,然后用总三角形个数C(n – 1, 3)…

Higher Math Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2219    Accepted Submission(s): 1219 Problem Description You are building a house. You’d prefer if all the walls have a precise right…