leetCode:reverseInteger 反向整数【JAVA实现】

【leetCode:reverseInteger 反向整数【JAVA实现】】的更多相关文章

leetCode:reverseInteger 反向整数【JAVA实现】

反向整数给定一个 32 位有符号整数,将整数中的数字进行反转,如果超出整数的最大或者最小范围返回0 更多文章查看个人博客个人博客地址:反向整数方法一利用StringBuilder的reverse方法,将数字转换成字符反转然后再转换回整数 public int reverseInteger(int num) { if (num == 0 || (num < 10 && num > -10)) { return num; } // 获得绝对值去掉正负号 int temp…

LeetCode第[18]题(Java)：4Sum 标签：Array

题目难度:Medium 题目: Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadrup…

LeetCode第[1]题(Java)：Two Sum 标签：Array

题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 翻译: 给定一组整数,两个数字的返回索引,它们的和会等于一个特定…

LeetCode第[46]题(Java)：Permutations(求所有全排列) 含扩展——第[47]题Permutations 2

题目:求所有全排列难度:Medium 题目内容: Given a collection of distinct integers, return all possible permutations. 翻译:给定一组各不相同的整数,返回所有可能的排列. Example: Input: [1,2,3] Output: [ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 我的思路:每种情况中,每一个元素只出现一次,只是之间的顺序不同,那么…

LeetCode第[1]题(Java)：Two Sum （俩数和为目标数的下标）——EASY

题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 翻译: 给定一组整数,两个数字的返回索引,它们的和会等于一个特定…