Description On January 1st 2002, The Netherlands, and several other European countries abandoned their national currency in favour of the Euro. This changed the ease of paying, and not just internationally. A student buying a 68 guilder book before J…

题意 : 给出 6 枚硬币的面值,然后要求求出对于 1~100 要用所给硬币凑出这 100 个面值且要求所用的硬币数都是最少的,问你最后使用硬币的平均个数以及对于单个面值所用硬币的最大数. 分析 :  问题建模就是属于完全背包了,但是和普通的完全背包不一样,这题可以使用硬币的负数值,其实面对负数面值的情况,解决方法将更新数序和普通完全背包的更新顺序相反即可,然后正反更新两次就能得出最后的答案了.在普通物品重量只有正数的情况下对于一个 dp[i] 是从下标值小于 i 的状态转移而来,为了达到物品能…

Q: 既是多重背包, 还是找零问题, 怎么处理? A: 题意理解有误, 店主支付的硬币没有限制, 不占额度, 所以此题不比 1252 难多少 Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins change…

题意: 给定6个硬币的币值, 问组成1~100这些数最少要几个硬币, 比如给定1 2 5 10 20 50, 组成40 可以是 20 + 20, 也可以是 50 -10, 最少硬币是2个. 分析: 这道题可以转化成是一道最短路的方法去做, 设一开始的起点为0(什么硬币都不取), 然后每个点都有12条路(对应正负6种币值), 每条路的权值为1, 令dis[maxn]初始化为inf, 求出dis[1]~dis[100]即可. 但是最大值maxn要取比100更大, 比如 构造100的最优方法为51+5…

背包 要么 BFS 意大利是说给你几个基本的货币,组成 1~100 所有货币,使用基本上的货币量以最小的. 出口 用法概率.和最大使用量. 能够BFS 有可能 . 只是记得数组开大点. 可能会出现 100 = 99+99 -98 的情况. 背包是先做一个全然背包,求得最少可能由多少相加. 然后做一个 01背包,看是否能被 减. 背包: #include<cstdio> #include<cstring> #include<string> #include<queu…

Euro Efficiency Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 20000/10000K (Java/Other) Total Submission(s) : 12   Accepted Submission(s) : 3 Problem Description On January 1st 2002, The Netherlands, and several other European countries aban…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…

Euro Efficiency Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4109   Accepted: 1754 Description On January 1st 2002, The Netherlands, and several other European countries abandoned their national currency in favour of the Euro. This ch…

题目大概的意思就是:小强用硬币买东西,硬币有N种,面值为Vi,店家有各种硬币都有无限个,而小强只有Ci个(分别对应Vi) 问最小交易硬币数,就是一个有找零的背包问题啦. 我的上一篇博客跟这hdu3591的类型非常非常接近,所以我很快就写完,并且很快地WA了无数次. 后来很苦恼,看看别人写的代码,他们的思想大概是这样子.用dp2去记载找零,就是dp2[i]=min{dp2[i],dp2[i-V]+1 } V为要付的总款 之后再从V到INF处得到ans=min{ans,dp[i]+dp2[i-V]}…