[题目链接] 点击打开链接 [算法] dijkstra [代码] #include<bits/stdc++.h> using namespace std; typedef long long ll; const ll INF = 1e15; const ll MAXN = 1e5; ll n,m,u,v,w,i,p,to,cost,x; ll dist[MAXN+],vis[MAXN+],last[MAXN+]; priority_queue< pair<ll,ll> >…

解题思路 heap+Dijkstra就能过.注意边是双向边,要用long long. 附上代码 #include <iostream> #include <queue> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef pair<long long, int> P; priority_queue<P, ve…

[codeforces 415D]Mashmokh and ACM 题意:美丽数列定义:对于数列中的每一个i都满足:arr[i+1]%arr[i]==0 输入n,k(1<=n,k<=2000),问满足[数列长度是k && 数列中每一个元素arr[i]在1~n之间 && 数列中元素可以重复]的数列有多少个?结果对10^9+7取余 解题思路:dp[i][j]表示长度是j,最后一位是i的种数 if(kk%i==0) dp[kk][j+1]+=dp[i][j] #inc…

[题目链接]:http://codeforces.com/contest/496/problem/E [题意] 给你n个歌曲; 每个歌曲有一个需要声音的区间li,ri; 然后给你m个人; 每个人也有一个声音区间Li,Ri以及最多能唱的歌曲数目ki; 某个人能唱某首歌当且仅当Li<=li&&ri<=Ri 问你要如何分配这n首歌给哪些人唱 或输出无解; [题解] 把和n+m个区间按照左端点排序; 左端点一样,就把人排在前面; 然后顺序枚举; 对于人,直接把它加入到multiset中…

time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output You are given an array of positive integers a1, a2, -, an × T of length n × T. We know that for any i > n it is true that ai = ai - n. Find the l…

time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output Student Vladislav came to his programming exam completely unprepared as usual. He got a question about some strange algorithm on a graph - somet…

time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output The tram in Berland goes along a straight line from the point 0 to the point s and back, passing 1 meter per t1 seconds in both directions. It me…

B. Name That Tune time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output It turns out that you are a great fan of rock band AC/PE. Peter learned that and started the following game: he plays the f…

[题目链接]:http://codeforces.com/contest/707/problem/E [题意] 给你一个n*m的方阵; 里面有k个联通块; 这k个联通块,每个连通块里面都是灯; 给你q个操作; 有以下两种类型 ①将第i个连通块里面灯取反 ②询问你(x1,y1)(x2,y2)这个矩形区域内灯的权值的和; [题解] 要用到二维的树状数组; 取反操作只要O(1)就能完成; 即先不管它是什么,取反就是了; 然后在询问的时候,直接用二维树状数组累加; 这里的累加可能是减也可能是加; 也可能…

[题目链接]:http://codeforces.com/contest/707/problem/C [题意] 给你一个数字n; 问你这个数字是不是某个三角形的一条边; 如果是让你输出另外两条边的大小; [题解] 首先明确n<=2的时候是无解的. n>2之后都有解; 这里设 n2+b2=a2 则有 n2=a2−b2 也即 n2=(a+b)∗(a−b) 这里对n分两类讨论; ① n为奇数 则令 a−b=1 a+b=n2 这样 2∗a=n2+1 因为n是奇数所以右边是个偶数; 得出来的a就是整数了…