题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanatio…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…

［抄题］: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Ex…

传送门 Description The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Ou…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 位运算 日期 题目地址:https://leetcode.com/problems/total-hamming-distance/description/ 题目描述 The Hamming distance between two integers is the number of positions at which the correspondi…

▶ 与 Hamming  距离相关的两道题. ▶ 461. 求两个数 x 与 y 的哈夫曼距离. ● 代码,4 ms,对 x 和 y 使用异或,然后求值为 1 的位的个数. class Solution { public: int hammingDistance(int x, int y) { int i,temp; , temp = x ^ y; temp > ; temp &= temp - , i++); return i; } }; ● 代码,7 ms,转化为 bitset 来逐位比…

Fun one.. the punch line of this problem is quite common in Bit related problems on HackerRank - visualize it in your mind, and you will find: all bits on the same index among all numbers, will not involve other bits on other indices. So, we simply c…

class Solution { public: int totalHammingDistance(vector<int>& nums) { ; ; i < ; i++) { ; for (int n : nums) { << i)) { ones++; } } res += ones * (nums.size()-ones); } return res; } };…

两个整数的 汉明距离 指的是这两个数字的二进制数对应位不同的数量.计算一个数组中,任意两个数之间汉明距离的总和.示例:输入: 4, 14, 2输出: 6解释: 在二进制表示中,4表示为0100,14表示为1110,2表示为0010.(这样表示是为了体现后四位之间关系)所以答案为:HammingDistance(4, 14) + HammingDistance(4, 2) + HammingDistance(14, 2) = 2 + 2 + 2 = 6.注意:    数组中元素的范围为从 0到 1…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…

原题链接在这里:https://leetcode.com/problems/total-hamming-distance/ 题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs…

The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…

Total Highway Distance 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 Little Hi and Little Ho are playing a construction simulation game. They build N cities (numbered from 1 to N) in the game and connect them by N-1 highways. It is guaranteed that each pair…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/maximize-distance-to-closest-person/description/ 题目描述 In a row of seats, 1 represents a person sitting in that seat, and 0 represents that…

lightoj1146 Two men are moving concurrently, one man is moving from A to B and other man is moving from C to D. Initially the first man is at A, and the second man is at C. They maintain constant velocities such that when the first man reaches B, at…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 过两遍数组 日期 题目地址:https://leetcode.com/problems/shortest-distance-to-a-character/description/ 题目描述 Given a string S and a character C, return an array of integers representing the…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 中序遍历 日期 题目地址:https://leetcode.com/problems/minimum-distance-between-bst-nodes/description/ 题目描述 Given a Binary Search Tree (BST) with the root node root, return the minimum dif…

［抄题］: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanat…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

位运算基础 说到与(&).或(|).非(~).异或(^).位移等位运算,就得说到位运算的各种奇淫巧技,下面分运算符说明. 1. 与(&) 计算式 a&b,a.b各位中同为 1 才为 1,否则为0,a&1和a%2效果一样:来看两道典型的题目,第1道计算整数二进制中 1 的位数: //191. Number of 1 Bits int hammingWeight(uint32_t n) { ; ){ n=n&(n-); ++res; } return res; } n=…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

461. Hamming Distance 解题思路: 把两个数的每一位和1比较,如果结果不同说明这两位不同.要比较32次. int hammingDistance(int x, int y) { int result = 0; for (int i = 0; i < 32; i++) { if (((x>>i)&0x1) != ((y>>i)&0x1)) { result ++; } } return result; } 477. Total Hamming…

位运算基础 说到与(&).或(|).非(~).异或(^).位移等位运算,就得说到位运算的各种奇淫巧技,下面分运算符说明. 1. 与(&) 计算式 a&b,a.b各位中同为 1 才为 1,否则为0,a&1和a%2效果一样:来看两道典型的题目,第1道计算整数二进制中 1 的位数: //191. Number of 1 Bits int hammingWeight(uint32_t n) { ; ){ n=n&(n-); ++res; } return res; } n=…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

All LeetCode Questions List 题目汇总 Sorted by frequency of problems that appear in real interviews. Last updated: October 2, 2017Google (214)534 Design TinyURL388 Longest Absolute File Path683 K Empty Slots340 Longest Substring with At Most K Distinct C…

源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…

**401. Binary Watch 思路:产生两个list分别代表小时和分钟,然后遍历 public List<String> readBinaryWatch(int num) { List<String> res = new ArrayList<String>(); int[] hour = {8,4,2,1}; int[] minute = {32,16,8,4,2,1}; for(int i = 0; i <= num; i++){ //i表示时和分各有…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主啊(如果不方便注册博客园的话,可以下载下文提到的APP,在Feedback中给博主发邮件交流哈),同时也请大家踊跃地,大量地,盲目地提供各个题目的follow up一起讨论哈,多谢多谢,祝大家刷得愉快…