作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 单调栈 日期 题目地址: https://leetcode.com/problems/largest-rectangle-in-histogram/description/ 题目描述 Given n non-negative integers representing the histogram's bar height where the widt…
LeetCode 84. Largest Rectangle in Histogram 单调栈应用 leetcode+ 循环数组,求右边第一个大的数字 求一个数组中右边第一个比他大的数(单调栈 LeetCode--寻找数组中第三大的数…
Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram. Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]. The largest…
Problem: Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram. Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]. The…
原题 Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram. Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]. The large…
Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram. Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]. The largest…
Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram. Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]. The largest…
Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram. Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]. The largest…
给出 n 个非负整数来表示柱状图的各个柱子的高度,每个柱子紧挨彼此,且宽度为 1 .您的函数要能够求出该柱状图中,能勾勒出来的最大矩形的面积. 详见:https://leetcode.com/problems/largest-rectangle-in-histogram/description/ Java实现: 方法一:遍历数组,每找到一个局部峰值,就向前遍历所有的值,算出共同的矩形面积,每次对比保留最大值. class Solution { public int largestRectangl…
https://www.cnblogs.com/grandyang/p/4322653.html 1.存储一个单调递增的栈 2.如果你不加一个0进去,[1]这种情况就会输出结果0,而不是1 3.单调递增的栈,如果遇到比栈的top小的,就要计算一次.其实可以看到,这个top,从左向top是最大的,top向右也是最大的,所以只能乘以他自己. class Solution { public: int largestRectangleArea(vector<int>& heights) { s…