Average is not Fast Enough! http://acm.hdu.edu.cn/showproblem.php?pid=1036 Problem Description A relay is a race for two or more teams of runners. Each member of a team runs one section of the race. Your task is to help to evaluate the results of a r…

#include<stdio.h>int main(){ int n; double d; int num; char h,m1,m2,s1,s2; scanf("%d",&n); scanf("%lf",&d); while(scanf("%d",&num)!=EOF) { printf("%3d: ",num); bool flag=true; int sumtime=0; for(in…

Problem Description A relay is a race for two or more teams of runners. Each member of a team runs one section of the race. Your task is to help to evaluate the results of a relay race. You have to process several teams. For each team you are given a…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1036 心得:注意,要进行四舍五入的精确可以用+0.5实现. #include<iostream> #include<cstring> #include<cstdio> using namespace std; ]; int main(void) { double tim,dis; int pt,n,i,h,mm,ss,t1,t2; scanf("%d %lf&qu…

ACM训练计划建议 From:freecode#  Date:2015/5/20 前言: 老师要我们整理一份训练计划给下一届的学弟学妹们,整理出来了,费了不少笔墨,就也将它放到博客园上供大家参考. 菜鸟之作,大牛勿喷,如有不当或补充之处,欢迎指出. 本建议书分为三个阶段,大一.大二.大三.大四暂没整理,一方面是大四要面临考验和找工作的问题,坚持继续acm的很少,另一方面,本人还没大四…… 下面以个人经验分析一下这三个阶段建议学习的内容和具体的训练计划. 正文: 大一(第一阶段): 大一是时间最充…

ACM训练计划建议 From:freecode#  Date:2015/5/20 前言: 老师要我们整理一份训练计划给下一届的学弟学妹们,整理出来了,费了不少笔墨,就也将它放到博客园上供大家参考. 菜鸟之作,大牛勿喷,如有不当或补充之处,欢迎指出. 本建议书分为三个阶段,大一.大二.大三.大四暂没整理,一方面是大四要面临考验和找工作的问题,坚持继续acm的很少,另一方面,本人还没大四…… 下面以个人经验分析一下这三个阶段建议学习的内容和具体的训练计划. 正文: 大一(第一阶段): 大一是时间最充…