1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断select * from peoplewhere peopleId in (select  peopleId  from  people  group  by  peopleId  having count(peopleId) > 1) 例二: select * from testtable where numeber in (select number from people group by number havi…

select * from yryz_role_partner where user_id in (select user_id from yryz_role_partner group by user_id having count(1) >= 2)…

select * from (SELECT titleid,count(titleid) c FROM [DragonGuoShi].[dbo].[ArticleInfo] group by titleid,[CategoryCode] having count(titleid)>1)as t order by c delete [DragonGuoShi].[dbo].[ArticleInfo] where ID not in ( SELECT max(ID) c FROM [DragonGu…

SELECT * FROM tab_init WHERE id IN ( --根据Data分类获取数据最小ID列表 select max(id) from tab_init group by a,b ) 先找出重复数据的 最大的Id ( group by 后面可跟多列, 根据规则找到重复数据), 取出 id 最大或最小的 Id, 然后使用 in查询,就可以得到不重复的数据…

假设现有一张人员表(表名:Person),若想将姓名.身份证号.住址这三个字段完全相同的记录查找出来,使用 1: SELECT p1.* 2: FROM persons p1,persons p2 3: WHERE p1.id<>p2.id 4: AND p1.cardid = p2.cardid 5: AND p1.pname = p2.pname 6: AND p1.address = p2.address 可以实现该功能. 删除重复记录的SQL语句 1.用rowid方法 2.用group…

查询结果作为数据进行添加 INSERT INTO a ( Aid, Atitle, Url, Pic1 ) SELECT c Aid,d Atitle,e Url,f Pic1 FROM b 对于大神来说,不看都知道,但是对于和我一样的菜鸟,就需要解释一下了. a,b是数据表名称,c,d,e,f是数据.而c,d,e,f这些数据不一定非得来自b表,可以来自left join,right join和内连接查询出来的结果 个人觉得使用起来还是比较方便的. ) AND d IN (SELECT h FR…

select *from Awhere id in (select id from A group by id having count(1) >= 2) 注释:id 为重复的关键字(更换成所需要的) 开发实例: select CarlotName ,CheweiIDfrom Position_Car awhere a.CarlotName in (select CarlotName from Position_Car b group by b.CarlotName having count(1…

查找所有重复标题的记录: SELECT *FROM t_info aWHERE ((SELECT COUNT(*)FROM t_infoWHERE Title = a.Title) > 1)ORDER BY Title DESC 一.查找重复记录 1.查找全部重复记录 Select * From 表 Where 重复字段 In (Select 重复字段 From 表 Group By 重复字段 Having Count(*)>1) 2.过滤重复记录(只显示一条) Select * From H…

1.最直观的思路:要知道所有名字有重复人资料,首先必须知道哪个名字重复了:select name from emp group by name having count(*)>1所有名字重复人的记录是:select * from emp where name in (select name from emp group by name having count(*)>1) 2.稍微再聪明一点,就会想到,如果对每个名字都和原表进行比较,大于2个人名字与这条记录相同的就是合格的 ,就有:selec…

select user_name,count(*) as count from comm_user group by user_name having count>1;…