hdu1016 Prime Ring Problem(DFS)】的更多相关文章

Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 40339    Accepted Submission(s): 17813 Problem Description A ring is compose of n circles as shown in diagram. Put natural num…
Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 66391    Accepted Submission(s): 28456 Problem Description A ring is compose of n circles as shown in diagram. Put natural numb…
HDOJ(HDU).1016 Prime Ring Problem (DFS) [从零开始DFS(3)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (…
Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 34609    Accepted Submission(s): 15327 Problem Description A ring is compose of n circles as shown in diagram. Put natural numb…
Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 74594    Accepted Submission(s): 31690 Problem Description A ring is compose of n circles as shown in diagram. Put natural numb…
Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 31031    Accepted Submission(s): 13755 Problem Description A ring is compose of n circles as shown in diagram. Put natural numb…
题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1016 Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 34554    Accepted Submission(s): 15303 Problem Description A ring is compos…
K - Prime Ring Problem ================================================================================================================================= 题目大意是给出 1~n 个数 第一个数必定是 1 ,使得无论那两个相邻的数相加,都是质数(即大于1的自然数中,除了1和它本身以外不再有其他因数): 打印出所有可能,即直接用dfs 遍历所有可能性…
A ring is compose of n circles as shown in diagram. Put natural number 1, 2, ..., n into each circle separately, and the sum of numbers in two adjacent circles should be a prime. Note: the number of first circle should always be 1. Inputn (0 < n < 2…
dfs,用全局数组和变量保存并更新当前状态. 答案可以直接在搜索结束时打印,n为奇数时方案数为0. acm.hdu.edu.cn/showproblem.php?pid=1016 #include <cstdio> #include <cstring> using namespace std; ; int n; int ans[maxn], k; ]; ]; void init(){ memset(isprime, , sizeof isprime); isprime[] = is…