Maximum Depth of Binary Tree Total Accepted: 63668 Total Submissions: 141121 My Submissions Question Solution Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [,,,,], / \ / \ 方法一:采用…

描述 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,1…

计算二叉树的最大深度 我的方法是找出两个子树的长度中最长的那个,然后加1 class Solution { public: int maxDepth(TreeNode* root) { ; ,maxDepth(root->right)+); } };…

104. Maximum Depth of Binary Tree -- Easy 方法 使用递归 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目标签:Tree 这道题目给了我们一个二叉树,要我们找到最大深度,就是从root点到最深的那个点之间点的数量.利用post order 来遍历二叉树,对于每一个点,它的两个chi…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 分析:求二叉树的最大深度 解法一:很容易想到的便是递归(深度优先搜索) (1)如果根节点是空,则返回0:否则转到(2) (2)  l = 左子树的最大深度; r = 右子树的最大深…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路:非常基础的一个题.DFS就可以.代码例如以下: /** * Definition for a binary tree node. * public class TreeNod…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…

题目: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求二叉树的深度,递归一下就可以求到了. python新手(我)发现python中没有三元运算符,不过可以用true_part if condition else false…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 思路:直接利用递归,此处二叉树的C++语言定义值得参考.…

题目要求 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. 题目分析及思路 给定一棵二叉树,要求返回它的最大深度.最大深度是指在从根结点到最远叶结点…

这道题是LeetCode里的第104道题. 给出题目: 给定一个二叉树,找出其最大深度. 二叉树的深度为根节点到最远叶子节点的最长路径上的节点数. 说明: 叶子节点是指没有子节点的节点. 示例: 给定二叉树 [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 返回它的最大深度 3 . DFS 递归算法,简单的二叉树题.如果看不懂代码,建议学习一下二叉树,这可是基础啊! 给出代码: 递归法: /** * Definition for a binary tree…

Problem: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 初看本题第一印象为递归写法.首先找出终止条件:node == NULL.若未进入递归终止状态,则分左子树和又子树进行递归,最终返回累加最大的值.其代码如下: /*…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求树的高度. 深度优先搜索遍历.递归实现. /** * Definition for a binary tree node. * public class TreeNode { *…

题目描述: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 解题思路: 分左子树和右子数递归调用. 代码如下: /** * Definition for a binary tree node. * public class Tr…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 解题思路: 递归,JAVA实现如下: public int maxDepth(TreeNode root) { if(root==null) return 0; return Ma…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left;…

给定一个二叉树,找出其最大深度.二叉树的深度为根节点到最远叶节点的最长路径上的节点数.案例:给出二叉树 [3,9,20,null,null,15,7],    3   / \  9  20    /  \   15   7返回最大深度为 3 .详见:https://leetcode.com/problems/maximum-depth-of-binary-tree/description/ Java实现: 递归实现: /** * Definition for a binary tree node…

104: class Solution { public: int maxDepth(TreeNode* root) { if(root == NULL) ; int left = maxDepth(root->left); int right = maxDepth(root->right); ; } }; 111: class Solution { public: int minDepth(TreeNode* root) { if(root == NULL) ; int left = min…

Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 给一个二叉树,找出它的最小深度.最小深度是从根节点向下到最近的叶节点的最短路径,就是最短路径的节点个数. 解法1:DFS 解法2: BFS Java: DFS, Time Comp…

258. Add Digits Digit root 数根问题 /** * @param {number} num * @return {number} */ var addDigits = function(num) { var b = (num-1) % 9 + 1 ; return b; }; //之所以num要-1再+1;是因为特殊情况下:当num是9的倍数时,0+9的数字根和0的数字根不同. 性质说明 1.任何数加9的数字根还是它本身.(特殊情况num=0)        小学学加法的…

104. Maximum Depth of Binary Tree Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题目大意: 给一颗二叉树,求最大深度. 解题方法: 1.利用递归遍历二叉树. 注意事项: C++代码: /**…

Maximum Depth of Binary Tree  Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 与Minimum Depth of Binary Tree对照看 解法一:递归,子树高度+1. /** * Defini…

[Leetcode] Maximum and Minimum Depth of Binary Tree 二叉树的最小最大深度 (最小有3种解法) 描述 解析 递归深度优先搜索 当求最大深度时,我们只要在左右子树中取较大的就行了. 然而最小深度时,如果左右子树中有一个为空会返回0,这时我们是不能算做有效深度的. 所以分成了三种情况,左子树为空,右子树为空,左右子树都不为空.当然,如果左右子树都为空的话,就会返回1. 广度优先搜索(类似层序遍历的思想) 递归解法本质是深度优先搜索,但因为我们是求最小…

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Have you met this question in a real interview? Yes Example Given a binary tree as follow:…

[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…

要求:此题正好和Maximum Depth of Binary Tree一题是相反的,即寻找二叉树的最小的深度值:从根节点到最近的叶子节点的距离. 结题思路:和找最大距离不同之处在于:找最小距离要注意(l<r)? l+1:r+1的区别应用,因为可能存在左右子树为空的情况,此时值就为0,但显然值是不为0的(只有当二叉树为空才为0),所以,在这里注意一下即可! 代码如下: struct TreeNode { int val; TreeNode *left; TreeNode *right; Tree…