题目链接 题意 : 一个有n段长的金属棍,开始都涂上铜,分段涂成别的,金的值是3,银的值是2,铜的值是1,然后问你最后这n段总共的值是多少. 思路 : 线段树的区间更新.可以理解为线段树成段更新的模板题. //HDU 1698 #include <cstdio> #include <cstring> #include <iostream> using namespace std; ],p[] ; //lz延迟标记,每次更新不需要更新到底,使得更新延迟到下次更新或者查询的…

2017-08-30 18:54:40 writer:pprp 可以跟上一篇博客做个对比, 这种实现不是很好理解,上一篇比较好理解,但是感觉有的地方不够严密 代码如下: /* @theme:segmentation/interval T @writer:pprp @begin:15:26 @end:16:13 @declare: 使用lazy标记的线段树,HDU 1698 这次写的是带结构体的那种 @date:2017/8/30 */ #include <iostream> #include…

Just a Hook Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1698 Description In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made u…

题目地址:pid=1698">HDU 1698 区间替换裸题.相同利用lazy延迟标记数组,这里仅仅是当lazy下放的时候把以下的lazy也所有改成lazy就好了. 代码例如以下: #include <iostream> #include <cstdio> #include <string> #include <cstring> #include <stdlib.h> #include <math.h> #includ…

Just a Hook (HDU 1698) 题链 每一次都将一个区间整体进行修改,需要用到懒惰标记,懒惰标记的核心在于在查询前才更新,比如将当前点rt标记为col[rt],那么此点的左孩子和右孩子标记必然和其一致(直接替换,如果是累积则另当别论),同时这个区间也能很快求出了 线段树功能:区间更新+区间查询 #include <cstdio> #include <utility> #include <queue> #include <cstring> #de…

题目链接 HDU 1698 Problem Description: In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several consecutive metallic sticks which are of the same length. Now Pudge wants to do some…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=1698 题目: Problem Description   In the game of DotA, Pudge's meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several consecutive metallic sticks which are of t…

Just a Hook Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1698 Description In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several cons…

http://acm.hdu.edu.cn/showproblem.php?pid=1698 题意:给出1~n的数,每个数初始为1,每次改变[a,b]的值,最后求1~n的值之和. 思路: 区间更新题目,关于懒惰标记什么的参考这个吧http://blog.sina.com.cn/s/blog_a2dce6b30101l8bi.html,讲得不错的. #include<iostream> #include<cstring> #include<algorithm> using…

acm.hdu.edu.cn/showproblem.php?pid=1698 [AC] #include<cstdio> ; #define lson (i<<1) #define rson (i<<1|1) struct Seg { int l,r,lazy,val; }tree[maxn<<]; int val[maxn]; void push_up(int i) { tree[i].val=tree[lson].val+tree[rson].val;…