[LintCode] Submatrix Sum 子矩阵之和】的更多相关文章

Given an integer matrix, find a submatrix where the sum of numbers is zero. Your code should return the coordinate of the left-up and right-down number. Have you met this question in a real interview? Yes Example Given matrix [ [1 ,5 ,7], [3 ,7 ,-8],…
Naive solution is O(n^4). But on 1 certain dimension, naive O(n^2) can be O(n) by this well-known equation: sum[i..j] = sum[0..j] - sum[0..i]. And pls take care of several corner cases. class Solution { public: /** * @param matrix an integer matrix *…
和为零的子矩阵 给定一个整数矩阵,请找出一个子矩阵,使得其数字之和等于0.输出答案时,请返回左上数字和右下数字的坐标. 样例 给定矩阵 [ [1 ,5 ,7], [3 ,7 ,-8], [4 ,-8 ,9], ] 返回 [(1,1), (2,2)] 挑战 O(n3) 时间复杂度 解题 直接暴露求解,时间复杂度O(N2*M2 ) public class Solution { /** * @param matrix an integer matrix * @return the coordinat…
To the Max Time Limit: 1000MSMemory Limit: 10000K Total Submissions: 38573Accepted: 20350 Description Given a two-dimensional array of positive and negative integers, a sub-rectangle is any contiguous sub-array of size 1*1 or greater located within t…
Maximal Subarray Sum : O(n) scan-and-update dynamic programming, https://en.wikipedia.org/wiki/Maximum_subarray_problem, https://leetcode.com/problems/maximum-subarray Maximal Submatrix Sum: given 2-D matrix, find the submatrix whose sum is largestwe…
Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that…
http://poj.org/problem?id=1050 我们已经知道求最大子段和的dp算法 参考here  也可参考编程之美有关最大子矩阵和部分. 然后将这个扩大到二维就是这道题.顺便说一下,有时候不要把问题想复杂了,有些问题只能靠暴力求解,而这道题是暴力加算法. 在这个题中,我们可以把二维压缩到一维然后求解最大子段.我们先枚举所求矩阵的起点行和结束行,然后把每一列的数据之和求出,用这些数据和就构造出一个一维的数组(代码中我没有明确表示出这个数组),然后用最大子段和的dp算法求解. 关于二…
K SUM My Submissions http://www.lintcode.com/en/problem/k-sum/ 题目来自九章算法 13% Accepted Given n distinct positive integers, integer k (k <= n) and a number target. Find k numbers where sum is target. Calculate how many solutions there are? Example Given…
4 Pointer solution. Key: when moving pointers, we skip duplicated ones. Ref: https://github.com/xbz/lintcode/blob/master/4_sum/4sum.cpp class Solution { void nextUnique(vector<int> &num, size_t &j) { ]) ++j; } public: vector<vector<int…
题目 三数之和 给出一个有n个整数的数组S,在S中找到三个整数a, b, c,找到所有使得a + b + c = 0的三元组. 样例 如S = {-1 0 1 2 -1 -4}, 你需要返回的三元组集合的是: (-1, 0, 1) (-1, -1, 2) 注意 在三元组(a, b, c),要求a <= b <= c. 结果不能包含重复的三元组. 解题: 法一:直接暴力,时间复杂度是O(N3) public class Solution { /** * @param numbers : Give…