题目 给你两个二进制字符串,返回它们的和(用二进制表示). 输入为 非空 字符串且只包含数字 1 和 0. 题解 两个字符串从低位开始加,前面位不够补0.维护进位,最后加上最后一个进位,最后反转结果字符串. 代码 class Solution { public String addBinary(String a, String b) { StringBuilder sb = new StringBuilder(); int ca = 0; for(int i = a.length() - 1,…
Leetcode 67:Add Binary(二进制求和) (python.java) Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. 给定两个二进制字符串,返回他们的和(用二进制表示). 输入为非空字符串且只包含数字 1 和 0. Example 1: Input…
原文链接:https://swlaschin.gitbooks.io/fsharpforfunandprofit/content/posts/fvsc-sum-of-squares.html Comparing F# with C#: A simple sumF# PK C#:简单的求和 To see what some real F# code looks like, let's start with a simple problem: "sum the squares from 1 to N…
二进制求和 给定两个二进制字符串,返回他们的和(用二进制表示). 样例 a = 11 b = 1 返回 100 细节出了好多问题,提交了好多次... public class Solution { /** * @param a a number * @param b a number * @return the result */ public String addBinary(String a, String b) { int c = 0; int al = a.length() - 1; i…
LeetCode:范围求和||[598] 题目描述 给定一个初始元素全部为 0,大小为 m*n 的矩阵 M 以及在 M 上的一系列更新操作. 操作用二维数组表示,其中的每个操作用一个含有两个正整数 a 和 b 的数组表示,含义是将所有符合 0 <= i < a 以及 0 <= j < b 的元素 M[i][j] 的值都增加 1. 在执行给定的一系列操作后,你需要返回矩阵中含有最大整数的元素个数. 示例 1: 输入: m = 3, n = 3 operations = [[2,2],…
今天的华师 Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example:Given binary tree [3,9,20,null,null,15,7], 3 / 9 20 / 15 7 return its bottom-up level…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
