Collect More Jewels Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6713    Accepted Submission(s): 1558 Problem Description It is written in the Book of The Lady: After the Creation, the cruel…

Collect More Jewels Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6148    Accepted Submission(s): 1386 Problem Description It is written in the Book of The Lady: After the Creation, the cruel…

Cleaning Robot (bfs+dfs) Here, we want to solve path planning for a mobile robot cleaning a rectangular room floor with furniture. Consider the room floor paved with square tiles whose size fits the cleaning robot (1 * 1). There are 'clean tiles' and…

Collect More Jewels Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5345    Accepted Submission(s): 1189 Problem Description It is written in the Book of The Lady: After the Creation, the cruel…

Collect More Jewels Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6857    Accepted Submission(s): 1592 Problem Description It is written in the Book of The Lady: After the Creation, the cruel…

题意: 一个n*m的迷宫,在t时刻后就会坍塌,问:在逃出来的前提下,能带出来多少价值的宝藏. 其中: ’*‘:代表墙壁: '.':代表道路: '@':代表起始位置: '<':代表出口: 'A'~'J':代表宝藏: 解题思路: 本题有两种思路:1,bfs+状态压缩:相比之下耗时多: 2,bfs+dfs:耗时较少: 在这里着重介绍第一种方法:(博主也是现学现卖啦^_^) 因为宝藏的数目比较少,所以我们可以对宝藏进行状态压缩(用二进制表示宝藏是否已经拾取,1表示已拾取,0表示未拾取), 标记数组vis…

题目如题.题解如题. 因为目标点最多仅仅有4个,先bfs出俩俩最短路(包含起点).再dfs最短路.)0s1A;(当年弱跪杭州之题,现看如此简单) #include<iostream> #include<vector> #include<cstdio> #include<cstring> #include<queue> using namespace std; struct point { int x,y; int cnt; }; char a[1…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1254 分析: 真正移动的是箱子,但是要移动箱子需要满足几个条件. 1.移动方向上没有障碍. 2.箱子后方没有障碍. 3.人可以到达箱子后方的地方.这里dfs或bfs都可以实现 按条件搜索即可. #include <cstdio> #include <cstring> #include <cmath> #include <iostream> #include &l…

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 129 Accepted Submission(s): 59 Problem Description 推箱子是一个很经典的游戏.今天我们来玩一个简单版本.在一个M*N的房间里有一个箱子和一个搬运工,搬运工的工作就是把箱子推到指定的位置,注意,搬运工只能推箱子而不能拉箱子,因此如果箱子被推到一个角…

#include <stdio.h> #define INF 32767 typedef struct MGraph{ ]; ][]; int ver_num, edge_num; }MGraph; void create_graph(MGraph *graph) { int i, j; getchar(); ; i < graph->ver_num; ++i) scanf("%c%*c",&(graph->vertexs[i])); ; i &l…