Another Longest Increasing Subsequence Problem Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/problem/visitOriginUrl.action?id=19929 Description Given a sequence of N pairs of integers, find the length of the longest incre…

SPOJ Another Longest Increasing Subsequence Problem 传送门:https://www.spoj.com/problems/LIS2/en/ 题意: 给定 N个数对 \((x_i,y_i)\),求最长上升子序列的长度.上升序列定义为满足\((x_i,y_i)\)对i<j 有 \(x_i<x_j\) 且 \(y_i<y_j\) 题解: 一个三维最长链问题 第一维是存位置,第二维存x,第三维存y 注意查询是查询到p[i].z-1然后更新 细节方…

Let SSS be a sequence of integers s1s_{1}s​1​​, s2s_{2}s​2​​, ........., sns_{n}s​n​​ Each integer is is associated with a weight by the following rules: (1) If is is negative, then its weight is 000. (2) If is is greater than or equal to 10000100001…

Let SS be a sequence of integers s_{1}s​1​​, s_{2}s​2​​, ......, s_{n}s​n​​Each integer is is associated with a weight by the following rules: (1) If is is negative, then its weight is 00. (2) If is is greater than or equal to 1000010000, then its we…

2017-09-24 20:15:22 writer:pprp 题目链接:https://nanti.jisuanke.com/t/17319 题意:给你一串数,给你一个处理方法,确定出这串数的权值,然后让你在这串数中找到最长非下降子序列,并算出对应的权值和 这道题花费我时间最长了,我还是不是特别理解LIS找到的一些模板也不怎么会使用,各种错误,趁这次机会好好理解一下 代码如下: //ac : L #include <iostream> #include <cstdio> #inc…

最长非递减子序列变形题,把大于等于10000的copy五次放回去就可以了 ac代码: #include <cstdio> #include <cstring> #include <iostream> #include <cstring> #include <algorithm> using namespace std; #define LL long long ; int a[N]; int dp[N]; int LIS(int a[],int…

Let's say we have two strings: str1 = 'ACDEB' str2 = 'AEBC' We need to find the longest common subsequence, which in this case should be 'AEB'. Using dynamic programming, we want to compare by char not by whole words. we need memo to keep tracking th…

Given a sequence of N pairs of integers, find the length of the longest increasing subsequence of it. An increasing sequence A1..An is a sequence such that for every i < j, Ai < Aj. A subsequence of a sequence is a sequence that appears in the same…

cdq分治,dp(i)表示以i为结尾的最长LIS,那么dp的递推是依赖于左边的. 因此在分治的时候需要利用左边的子问题来递推右边. (345ms? 区间树TLE /********************************************************* * ------------------ * * author AbyssFish * **********************************************************/ #inclu…

题目链接  LIS2 经典的三维偏序问题. 考虑$cdq$分治. 不过这题的顺序应该是 $cdq(l, mid)$ $solve(l, r)$ $cdq(mid+1, r)$ 因为有个$DP$. #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i(a); i <= (b); ++i) #define dec(i, a, b) for (int i(a); i >= (b); --…

分析 这回试了一下三级标题,不知道效果怎么样? 回到正题,二维最长上升子序列......嗯,我会树套树. 考虑\(CDQ\)分治,算法流程: 先递归进入左子区间. 将左,右子区间按\(x\)排序. 归并处理左右子区间,在过程中使用树状数组加速\(DP\). 还原右区间,清空树状数组. 递归进入右子区间. 代码 #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring>…

目录 @description@ @solution@ @accepted code@ @details@ @description@ 给定由若干长度 <= N 的 01 字符串组成的集合 S.请找到长度最长的串 t(如果有多个选字典序最小的),使得存在 >= K 个 S 中的字符串,使得 t 是这些字符串的子序列. 原题题面. @solution@ 先看看怎么检验串 t 是否为某个串 s 的子序列:从前往后匹配,贪心地找最前面一个能够匹配上的. 注意到匹配的过程可以建图:每个种类的串 s 建…

题目大意 有一个 01 串集合 \(S\),其中每个串的长度都不超过 \(N\),你要求出 \(S\) 中至少是 \(K\) 个串的子序列的最长串,如果有多解,输出字典序最小的那组解. 由于 \(S\) 可能很大,因此我们是这样描述 \(S\) 的: 你将得到 \((N+1)\) 个 01 串,第 \(i\) 个串的长度为 \(2^{i-1}\). 第 \(i\) 个字符串的第 \(j\) 个字符,代表数字 \((j−1)\) 的.长度为 \((i−1)\) 的二进制表示是否出现在 \(S\)…

考虑一张 \(n\) 个点的图(\(V=\{0,1,\cdots,n\}\)):点 \(i\) 连向 \(a_i-1\),即 \(\text{index}\) 连向 \(\text{value}\).若 \(a_i=0\),不连边. 容易发现,每个点的入度和出度均至多为 \(1\),这意味着这张图实际上是若干条链.在这张图上,长为 \(k\) 的递减子序列即为满足 \(pos_1<pos_2<\cdots<pos_{2k}\) 满足 \(pos_{2k+1-i}\) 连向 \(pos_i…

Longest Increasing Subsequence(LIS) 一个美丽的名字 非常经典的线性结构dp [朴素]:O(n^2) d(i)=max{0,d(j) :j<i&&a[j]<a[i]}+1 直接两个for [二分查找优化]:O(n^2) g(i):d值为i的最小的a  每次更新然后lower_bound即可 ［大于等于］ lower_boundReturn iterator to lower bound Returns an iterator pointing…

Given a sequence of integers, find the longest increasing subsequence (LIS). You code should return the length of the LIS. Have you met this question in a real interview?     Example For [5, 4, 1, 2, 3], the LIS  is [1, 2, 3], return 3 For [4, 2, 4,…

Given a sequence of integers, find the longest increasing subsequence (LIS). You code should return the length of the LIS. Example For [5, 4, 1, 2, 3], the LIS  is [1, 2, 3], return 3 For [4, 2, 4, 5, 3, 7], the LIS is [4, 4, 5, 7], return 4 Challeng…

Good subsequence Problem's Link:   http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1553 Mean: 给你一个长度为n的序列和一个值k,让你找出一个子序列,满足在这个子序列中max-min的值<=k,求这个子序列最长的长度. analyse: 这题做法很多,直接暴力枚举每一个数为起点. Time complexity: O(n) Source code:  方法一(暴力): // Memory Time //…

[循环数组的最大字串和]Maximal-sum Subsequence PROBLEM 题目描述 给一个 N×N 的矩阵 M,可以取连续的一段数(必须是横着或者竖着或者斜着,这个矩阵是循环的,具体如下).要求找到一个子序列,使得这个序列的和最大. 对于 N=8 的矩阵,如下序列都是合法的: ​ M2,1,M2,2,M2,3,M2,4,M2,5,M2,6,M2,7,M2,8. ​ M2,2,M2,3,M2,4. ​ M2,6,M2,7,M2,8,M2,1,M2,2. ​ M4,3,M5,3,M6,…

Palindrome subsequence Problem Description In mathematics, a subsequence is a sequence that can be derived from another sequence by deleting some elements without changing the order of the remaining elements. For example, the sequence <A, B, D> is a…

题目: Given a sequence of integers, find the longest increasing subsequence (LIS). You code should return the length of the LIS. Clarification What's the definition of longest increasing subsequence? The longest increasing subsequence problem is to fin…

标签: 动态规划 描述: Given a sequence of integers, find the longest increasing subsequence (LIS). You code should return the length of the LIS. Clarification What's the definition of longest increasing subsequence? The longest increasing subsequence problem…

发信人: fennec (fennec), 信区: Algorithm 标 题: acm 总结 by fennec 发信站: 吉林大学牡丹园站 (Wed Dec 8 16:27:55 2004) ACM总结(fennec) 其实在北京比赛完的时候,我就想写了,不过还是早了点,直到上海比赛结束,大家的心中都不是太好受.郭老师有句话:你们这样做也是对的,不成功就成仁.让我的心也能安慰了不少. 我是从大一下学期开始接触ACM的,那时候我们学校才刚刚起步,siyee,wjiang师兄可以说是我的领路人了…

首先看一下题目: Introduction Dynamic programming is a confusing name for a programming technique that dramatically reduces the runtime of algorithms: from exponential to polynomial. The basic idea is to try to avoid solving the same problem or subproblem tw…

2000年台湾大专题...英语阅读输入输出专场..我只能说很强势.. M. Frequent Subsets Problem The frequent subset problem is defined as follows. Suppose UU={1, 2,\ldots…,N} is the universe, and S_{1}S​1​​, S_{2}S​2​​,\ldots…,S_{M}S​M​​ are MM sets over UU. Given a positive constan…

The Heaviest Non-decreasing Subsequence Problem 解题心得 这个题就是一个简单的动态规划,非递减最长子序列的改版(加一个权重),只要把权重为5的改成5个权重为1的然后dp就可以解决了,注意要用nlogn的复杂度才可以. #include<bits/stdc++.h> using namespace std; const int maxn = 1e6+100; typedef long long ll; ll dp[maxn],num[maxn],w…

02Train Seats Reservation 问答 只看题面 33.87% 1000ms 131072K You are given a list of train stations, say from the station 11 to the station 100100. The passengers can order several tickets from one station to another before the train leaves the station on…

B. Train Seats Reservation You are given a list of train stations, say from the station 1 to the station 100. The passengers can order several tickets from one station to another before the train leaves the station one. We will issue one train from t…

Common Subsequence Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if…

More important than algorithms(just problems #$!%), the techniques/concepts residing at the base of such algorithms is more important. There are broadly 4 ways in which classification of algorithms can be done. Classification by purpose Each algorith…