Continuous Login Time Limit: 2 Seconds      Memory Limit: 131072 KB      Special Judge Pierre is recently obsessed with an online game. To encourage users to log in, this game will give users a continuous login reward. The mechanism of continuous log…

Pierre is recently obsessed with an online game. To encourage users to log in, this game will give users a continuous login reward. The mechanism of continuous login reward is as follows: If you have not logged in on a certain day, the reward of that…

Continuous Login Time Limit: 2 Seconds      Memory Limit: 131072 KB      Special Judge Pierre is recently obsessed with an online game. To encourage users to log in, this game will give users a continuous login reward. The mechanism of continuous log…

原题:ZOJ 3768 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3768 一个结论:一个正整数总能用不超过三个前n项相加表示. 先找一个的,在找两个,三个的,二分找,用lower_bound函数. 代码: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <…

首先学习一下lower_bound() 函数lower_bound()在first和last中的前闭后开区间进行二分查找,返回大于或等于val的第一个元素位置.如果所有元素都小于val,则返回last的位置 举例如下: 一个数组number序列为:4,10,11,30,69,70,96,100.设要插入数字3,9,111.pos为要插入的位置的下标 则 pos = lower_bound( number, number + 8, 3) - number,pos = 0.即number数组的下标为…

BCD Code Time Limit: 5 Seconds      Memory Limit: 65536 KB Binary-coded decimal (BCD) is an encoding for decimal numbers in which each digit is represented by its own binary sequence. To encode a decimal number using the common BCD encoding, each dec…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2112 The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. T…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

详解OJ(Online Judge)中PHP代码的提交方法及要点 Introduction of How to submit PHP code to Online Judge Systems  Introduction of How to commit submission in PHP to Online Judge Systems 在目前常用的在线oj中,codeforces.spoj.uva.zoj 等的题目可使用PHP实现基本算法,zoj是目前对PHP支持较好的中文OJ. PHP是一门比…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

Dynamic Rankings Time Limit: 10 Seconds      Memory Limit: 32768 KB The Company Dynamic Rankings has developed a new kind of computer that is no longer satisfied with the query like to simply find the k-th smallest number of the given N numbers. They…

Painting Storages Time Limit: 2 Seconds      Memory Limit: 65536 KB There is a straight highway with N storages alongside it labeled by 1,2,3,...,N. Bob asks you to paint all storages with two colors: red and blue. Each storage will be painted with e…

什么是持续集成 持续集成(Continuous Integration)是经常合并小的代码更改的实践,而不是在开发周期结束时合并大的更改.目的是通过以较小的增量开发和测试来构建更健康的软件.这就是Travis CI出现的地方. 作为一个持续集成平台,Travis CI通过自动构建和测试代码更改来支持您的开发过程,并提供有关更改成功的即时反馈.Travis CI还可以通过管理部署和通知来自动化开发过程的其他部分.  Travis CI 介绍 官网:https://www.travis-ci.org…

前两天,带着学生们学习了简单的ASP.NET MVC,通过ADO.NET方式连接数据库,实现增删改查. 可能有一部分学生提前预习过,在我写登录SQL的时候,他们鄙视我说:“老师你这SQL有注入,随便都能登录了.不能这么写!” “呦?小伙子这都知道了?那你说说看 啥是注入?注入只能拿来绕过登录么?” 好吧,竟然在老子面前装逼,看来不给你点儿颜色看看,你还真是不明白天有多高.. 于是乎..哈哈.大清早的,轻松在班里装了一手好逼.. 呵呵.不说了,下面我把那个项目重写一下发上来吧.演示一下注入有哪些危…

p { margin-bottom: 0.1in; line-height: 120% } 一.一开始我是按照网友所说的 : rm -f ~/.gnome2/keyrings/login.keyring 删除秘钥文件, 按照网友的解决办法,这步之后,会打开新的程序会提示输入新的密码.但是重新打开谷歌浏览器,还是提示unlocking, 然后我开始排除问题所在,首先  cd ~/.gnome2/ 里面是空的了,有两种可能一种是我删掉了,一种就是本来就是空的,但keyrings文件夹应该还在才对.猜…

知识点:模块导入  变量赋值的两种形式  格式化输出  for循环  if...else 嵌套 #!C:\Program Files\Python35/bin # -*- conding:utf-8 -*- # author: Frank import getpass user,passwd= 'Frank','oldboy_python' msg = ''' Information of %s person: NAME: %s AGE: %s JOB: %s ID : %s ''' %(use…

新建web项目,添加default.aspx.Register.aspx.Login.aspx. default.aspx中添加LoginName.LoginStatus,LoginName的FormatString修改改变欢迎语.LoginStatus显示登录状态(未登录提示登录). Register.aspx 添加CreateUserWizard. Login.aspx中添加Login控件. 运行任意网站一次,添加web.config文件.在web.config中设置 <authentica…

第十三届浙江省大学生程序设计竞赛 I 题, 一道模拟题. ZOJ  3944http://www.icpc.moe/onlinejudge/showProblem.do?problemCode=3944 In a BG (dinner gathering) for ZJU ICPC team, the coaches wanted to count the number of people present at the BG. They did that by having the waitre…

A Simple Tree Problem Time Limit: 3 Seconds      Memory Limit: 65536 KB Given a rooted tree, each node has a boolean (0 or 1) labeled on it. Initially, all the labels are 0. We define this kind of operation: given a subtree, negate all its labels. An…

In present (post production) IT infrastructure many different workstations, servers etc. have to be maintained on a daily basis. When running on *nix operating systems, the main tool to log into and execute arbitrary code on a remote machine is SSH .…

在给一个Login授予权限时,发现该Login已经存在,其对应的User也存在于指定的DB中,查看该Login在指定DB中已被授予的权限. 1,查看Login的Server PrincipalID select * from sys.server_principals sp where sp.name='Domain_Name\Llogin_Name' 2,查看Login是否属于Server Role的Member select * from sys.server_role_members sr…

这道题目还是简单的,但是自己WA了好几次,总结下: 1.对输入的总结,加上上次ZOJ Problem Set - 1334 Basically Speaking ac代码及总结这道题目的总结 题目要求输入的格式: START X Y Z END 这算做一个data set,这样反复,直到遇到ENDINPUT.我们可以先吸纳一个字符串判断其是否为ENDINPUT,若不是进入,获得XYZ后,吸纳END,再进行输出结果 2.注意题目是一个圆周,所以始终用锐角进行计算,即z=360-z; 3.知识点的误…

放了一个长长的暑假,可能是这辈子最后一个这么长的暑假了吧,呵呵...今天来实验室了,先找了zoj上面简单的题目练练手直接贴代码了,不解释,就是一道简单的密文转换问题: #include <stdio.h> #include <string.h> int main() { char cText[1000]; char start[10]; char end[5]; while(scanf("%s",start)!=EOF&&strcmp(start…

这道题目说白了是一道平面几何的数学问题,重在理解题目的意思: 题目说,弗雷德想买地盖房养老,但是土地每年会被密西西比河淹掉一部分,而且经调查是以半圆形的方式淹没的,每年淹没50平方英里,以初始水岸线为x轴,平分半圆为y轴,建立如下图的坐标系 问题:给出坐标点(y>0),让你判断在那一年这个坐标点会被淹没. 解决方案:我们可以转换成的数学模型是来比较坐标点到原点的距离与半圆半径的大小即可知道该点是否被淹没,公式如下: 1.由于每年半圆面积增长50平方英里,可得半径递推公式R2=sqrt(100/p…

今天在ZOJ上做了道很简单的题目是关于加密解密问题的,此题的关键点就在于求余的逆运算: 比如假设都是正整数 A=(B-C)%D 则 B - C = D*n + A 其中 A < D 移项 B = A+C + D*n 当B<D时,两边对D取摸,  B = B%D = ( A+C + D*n )%D = (A+C)%D 由此可得此题答案,见代码 #include <cstdio> #include <cstring> int main() { ]; ],ctext[]; w…

ZOJ ACM题集,编译环境VC6.0 #include <stdio.h> int main() { int a,b; while(scanf("%d%d",&a,&b)!=EOF) { printf("%d\n",a+b); } ; }…

Login <?php require "../include/DBClass.php"; $username=$_POST['UserName']; $password=$_POST['Password']; if(empty($username) || empty($password)){ Go_Msg("请填写用户名,密码!","../default.html"); exit; } DBConn(); $password=md5($p…

最近碰到一个有趣的错误:海外的一台数据库服务器上某些作业偶尔会报错,报错信息如下所示: ------------------------------------------------------------------------------------------------------------------------------------------------- 日期 2013/9/15 12:00:00 日志 作业历史记录 (JOB_SYNCHRONIZING_ESCM_DATA…

      早晨宁波那边的IT人员打电话告知数据库无法访问了.其实我在早晨也发现Ignite监控下的宁波的数据库服务器出现了异常,但是当时正在检查查看其它服务器发过来的各类邮件,还没等到我去确认具体情况,就收到了电话.我首先检查网络是否畅通,结果发现网络没有问题,然后远程登录到该服务器,查看了一下数据库的服务发现其运行正常,但是在本机使用MSSMS管理工具亦无法连接数据库,当下有两种方案:方案一:使用DAC登录数据库,检查具体情况,方案二:直接去查看错误日志,查看具体错误信息.于是为了快点找到原…

在前面的学习中,配置文件中的<http>...</http>都是采用的auto-config="true"这种自动配置模式,根据Spring Security文档的说明: ------------------ auto-config Automatically registers a login form, BASIC authentication, logout services. If set to "true", all of thes…