Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 Note:Bonus points if you could solve it b…

Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. /** * Definition for binary tree * struct TreeNode { * int val; *…

Symmetric Tree 题目链接 题目要求: Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 Note: Bonus poi…

101. Symmetric Tree My Submissions Question Total Accepted: 90196 Total Submissions: 273390 Difficulty: Easy 给定一颗二叉树,检查是否镜像对称(环绕中心对称) Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this bin…

从简单的道题目開始刷题目: Symmetric Tree 题目:Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 题目分析: 第一道…

这是悦乐书的第163次更新,第165篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第22题(顺位题号是101).给定二叉树,检查它是否是自身的镜像(即,围绕其中心对称). 例如,这个二叉树[1,2,2,3,4,4,3]是对称的: 1 / \ 2 2 / \ / \ 3 4 4 3 但是以下[1,2,2,null,3,null,3]不是: 1 / \ 2 2 \ \ 3 3 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,…

题目: Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 思路: 首先这是一个求关于中心成对称二叉树的题目 二叉树的思路就是找到一个…

题目 Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: But the following is not: Note: Bonus points if you could solve it both recursively and iteratively. confuse…

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree [1,2,2,3,4,4,3] is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following [1,2,2,null,3,null,3] is not: 1 / \ 2 2 \ \ 3 3 BFS…

#-*- coding: UTF-8 -*-# Definition for a binary tree node.# class TreeNode(object):#     def __init__(self, x):#         self.val = x#         self.left = None#         self.right = Noneclass Solution(object):    resultBool=True    def isSymmetric(se…