A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you are supposed to sort the stru…

题意:给出N个结点的地址address.数据域data以及指针域next,然后给出链表的首地址,要求把在这个链表上的结点按data值从小到大输出.样例解释:按照输入,这条链表是这样的(结点格式为[address, data, next]):[00001, 0, 22222]→[22222, 1000, 12345]→[12345, -1, 33333]→[33333, 100000, 11111]→[11111,100, -1]按key值排序之后得到:[12345, -1, 00001]→[00…

1052 Linked List Sorting (25 分) A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, y…

1052. Linked List Sorting (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key a…

A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you are supposed to sort the stru…

A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you are supposed to sort the stru…

这场考试当年还参加了,当时直接用内置的排序了,否则自己写归并排序浪费时间啊,现在来练习一发.估计又有些节点没在链表里面,当时没考虑这个情况,所以一直有些case没过 #include <iostream> #include <cstdio> #include <vector> #include <unordered_map> using namespace std; class Node { public: int data; int next; Node(…

1052. Linked List Sorting (25) A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, yo…

1052 Linked List Sorting (25)(25 分) A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Nextpointer to the next structure. Now given a linked list…

1052 Linked List Sorting (25 分)   A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list,…

Linked List Sorting (链表)   A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you ar…

1052. Linked List Sorting (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key a…

1052. Linked List Sorting (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key a…

静态链表(用结构体数组模拟链表)     1052 Linked List Sorting (25分)   A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now…

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805425780670464 题意: 给定一些内存中的节点的地址,值以及下一节点所在地址. 要求对给定的头指针表示的链表进行排序. 思路: PAT的题目小细节真的很多啊.这道题要注意有可能有的节点是不在头指针链成的链表里的. 所以要先遍历一次链表,然后再排序. #include<cstdio> #include<cstdlib> #include<…

三个注意点: 1.给出的n个节点并不一定都在链表中 2.最后一组样例首地址即为-1 3.输出地址的时候一直忘记前面要补0... #include <iostream> #include <algorithm> #include <cstdio> #include <string.h> using namespace std; +; struct Node{ int addr; int val; int to; bool operator<(const…

题目 A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you are supposed to sort the s…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<stack> #include<vector> using namespace std;…

题意: 输入一个正整数N(<=100000),和一个链表的头结点地址.接着输入N行,每行包括一个结点的地址,结点存放的值(-1e5~1e5),指向下一个结点的地址.地址由五位包含前导零的正整数组成.以头结点地址开始的这条链表以值排序后得到的链表的长度和头结点,接着以升序按行输出每个结点的地址和值以及指向下一个结点的地址. trick: 题干说的postive N可是数据点4出现了N==0的数据,有些不解如果N==0应该包含的话不应该用nonnegative N吗... 数据点1包含有些结点并非在…

题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1028 题目描述: Excel can sort records according to any column. Now you are supposed to imitate this function. Input Each input file contains one test case. For each case, the first line contains two inte…

题目如下: A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you are supposed to sort th…

题意:链表排序 思路:题目本身并不难,但是这题仔细读题很重要.原题中有一句话,"For each case, the first line contains a positive N and an address of the head node, where N is the total number of nodes in memory",它没有明确表示这个N就是链表的结点个数,而是内存中含有的结点个数(大家可以相比较另外几道链表的题目,看看题目描述的细微差别).因此,在读入数据后…

1028 List Sorting (25 分)   Excel can sort records according to any column. Now you are supposed to imitate this function. Input Specification: Each input file contains one test case. For each case, the first line contains two integers N (≤) and C, wh…

Excel can sort records according to any column. Now you are supposed to imitate this function. Input Specification: Each input file contains one test case. For each case, the first line contains two integers N (≤) and C, where N is the number of reco…

题目链接 https://www.patest.cn/contests/pat-a-practise/1028 思路 就按照 它的三种方式 设计 comp 函数 然后快排就好了 但是 如果用 c++ 中的 string 保存名字的话 就会超时 所以 用 c 里面的 char *s 就可以过 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #incl…

题目 1. 思路 使用map存放所有的地址对 使用起始地址遍历map,结果存放在vector中 排序vector 输出vector 2. 注意点 开始的时候起始地址为-1 可能有些节点没有用到,注意排除 3. 代码 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<set> #include&…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…

准备每天刷两题PAT真题.(一句话题解) 1001 A+B Format  模拟输出,注意格式 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; string ans = ""; int main() { ; cin >> a >> b; c = a + b; ) {…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…