[LeetCode&Python] Problem 868. Binary Gap】的更多相关文章

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problem 868. Binary Gap solution1: class Solution { public: int binaryGap(int N) { ; vector<int> pos; ; ) { ==) pos.push_back(k); k++; N >>=;//errr... } ; i<pos.size(); ++i) { res = max(res, pos[i]-pos[i-]); } return res; } }; solution2: cl…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 线性扫描 日期 题目地址:https://leetcode.com/problems/binary-gap/description/ 题目描述 Given a positive integer N, find and return the longest distance between two consecutive 1's in the bina…
题目要求 Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. 题目分析及思路 给定一个正整数,返回该数二进制形式中连续两个1的最长间隔.若是没有连续的两个1,则返回0.可将该数转成二进制形式,得到的结果…