Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square pl…

HDU_1241 Oil Deposits   Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land…

HDOJ(HDU).1241 Oil Deposits(DFS) [从零开始DFS(5)] 点我挑战题目 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (…

[编程题] 黑白树 时间限制:1秒 空间限制:32768K 一棵n个点的有根树,1号点为根,相邻的两个节点之间的距离为1.树上每个节点i对应一个值k[i].每个点都有一个颜色,初始的时候所有点都是白色的. 你需要通过一系列操作使得最终每个点变成黑色.每次操作需要选择一个节点i,i必须是白色的,然后i到根的链上(包括节点i与根)所有与节点i距离小于k[i]的点都会变黑,已经是黑的点保持为黑.问最少使用几次操作能把整棵树变黑. 输入描述: 第一行一个整数n (1 ≤ n ≤ 10^5) 接下来n-1…

DFS 深搜专题 入门典例 -- 凌宸1642 深度优先搜索 是一种 枚举所有完整路径以遍历所有情况的搜索方法 ,使用 递归 可以很好的实现 深度优先搜索. 1 最大价值 题目描述 ​ 有 n 件物品,每件物品的重量为 w[i] , 价值为 c[i] .现在需要选出若干件物品放入一个容器为 V 的背包中,使得在选入背包的物品重量和不超过容量 V 的前提下 ,让背包中的物品的价值之和最大,求最大价值.(1 ≤ n≤ 20 ) 输入描述: ​ 第一行输入物品总数 n 和 背包容量 v . ​ 第二行…

点击打开链接 Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 21383    Accepted Submission(s): 12319 Problem Description The GeoSurvComp geologic survey company is responsible for detecti…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15291    Accepted Submission(s): 8787 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil dep…

Oil Deposits Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8274 Accepted Submission(s): 4860 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground…

[题目链接:HDOJ-2952] Counting Sheep Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2476    Accepted Submission(s): 1621 Problem Description A while ago I had trouble sleeping. I used to lie awake,…

  技巧:遍历8个方向 ; dr <= ; dr++) ; dc <= ; dc++) || dc != ) dfs(r+dr, c+dc, id); 我的解法: #include<cstdio> #include<cstring> #include<iostream> #include<string> #include<algorithm> using namespace std; ; char buf[N][N]; int m,…

Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15533    Accepted Submission(s): 8911 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underg…

Oil Deposits Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 15   Accepted Submission(s) : 14 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description The GeoSurvComp geologic…

深搜,从一点向各处搜找到全部能走的地方. Problem Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on…

 Oil Deposits  The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots.…

Oil Deposits Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16655   Accepted: 8917 Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular r…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1241 Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18650    Accepted Submission(s): 10750 Problem Description The GeoSurvComp geolog…

Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square pl…

Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only…

Lake Counting Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18201   Accepted: 9192 Description Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100…

G - Oil Deposits Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular regi…

Oil Deposits The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1241 Oil Deposits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 33688    Accepted Submission(s): 19585 Problem Description The GeoSurvComp geolo…

The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyze…

 Stamps  The government of Nova Mareterrania requires that various legal documents have stamps attached to them so that the government can derive revenue from them. In terms of recent legislation, each class of document is limited in the number of st…

题目大意:给你一个m*n的矩阵,里面有两种符号,一种是 @ 表示这个位置有油田,另一种是 * 表示这个位置没有油田,现在规定相邻的任意块油田只算一块油田,这里的相邻包括上下左右以及斜的的四个方向相邻的位置.要你求出一共有多少块油田. 解题报告:用dfs,我的做法是首先在输入的时候将每个有油田的位置标记为1,否则标记为0,然后枚举每一个点,如果这个点有油田,则以这个点为起点,像周围的八个方向搜索,搜到了相邻的点就标记为2,当然这里也可以标记为0,只要是将已经搜过的点标记掉就是了,当dfs退出到ma…

链接 : Here! 思路 : 搜索判断连通块个数, 所以 $DFS$ 或则 $BFS$ 都行喽...., 首先记录一下整个地图中所有$Oil$的个数, 然后遍历整个地图, 从油田开始搜索它所能连通多少块其他油田, 只需要把它所连通的油田个数减去, 就ok了 /************************************************************************* > File Name: E.cpp > Author: > Mail: >…

http://115.28.138.223:81/view.page?opid=5 这道题问的很怪. 起点DFS,每一个点还要DFS一次,统计不能到终点的个数 数据量不大这样做也能AC #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int x,y,ax,ay,bx,by;//'#'0, '+'1, '-'2, '|'…

问题描述: 小哈去玩迷宫,结果迷路了,小哼去救小哈.迷宫由n行m列的单元格组成(n和m都小于等于50),每个单元格要么是空地,要么是障碍物. 问题:帮小哼找到一条从迷宫的起点通往小哈所在位置的最短路径.(注意:障碍物不能走,小哼也不能走出迷宫外,0表示空地,1表示障碍物) 输入: 5 4 0 0 1 00 0 0 00 0 1 00 1 0 00 0 0 11 1 4 3 输出: 7 代码: #include<cstdio> #include<iostream> #define I…

图是一种灵活的数据结构,一般作为一种模型用来定义对象之间的关系或联系.对象由顶点(V)表示,而对象之间的关系或者关联则通过图的边(E)来表示. 图可以分为有向图和无向图,一般用G=(V,E)来表示图.经常用邻接矩阵或者邻接表来描述一副图. 在图的基本算法中,最初需要接触的就是图的遍历算法,根据访问节点的顺序,可分为广度优先搜索(BFS)和深度优先搜索(DFS). 广度优先搜索(BFS) 广度优先搜索在进一步遍历图中顶点之前,先访问当前顶点的所有邻接结点. a .首先选择一个顶点作为起始结点,并将…

Sudoku Killer Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3723    Accepted Submission(s): 1170 Problem Description 自从2006年3月10日至11日的首届数独世界锦标赛以后,数独这项游戏越来越受到人们的喜爱和重视.据说,在2008北京奥运会上,会将数独列为一个单独的…