LeetCode 461 Hamming Distance 解题报告】的更多相关文章

题目要求 The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. 题目分析及思路 题目给出两个整数,要求返回它们之间的Hamming distance.Hammi…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 方法一:异或 + 字符串分割 方法二:异或 + 字符串遍历 方法三:异或 + 位统计 二刷 python解法 方法一:异或 + 字符串count 方法二:循环异或 方法三:异或 + 单次遍历 日期 题目地址: https://leetcode.com/problems/hamming-distance/ Total Accepted:…
package BitManipulation; //Question 461. Hamming Distance /* The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note: 0 ≤ x,…
题目描述 两个整数之间的汉明距离指的是这两个数字对应二进制位不同的位置的数目. 给出两个整数 x 和 y,计算它们之间的汉明距离. 注意: 0 ≤ x, y < 231. 示例: 输入: x = 1, y = 4 输出: 2 解释: 1 (0 0 0 1) 4 (0 1 0 0) ↑ ↑ 上面的箭头指出了对应二进制位不同的位置. 思路 思路一: 对两个数进行异或操作,位级表示不同的那一位为 1,统计有多少个 1 . 思路二: 使用 Integer.bitcount() 来统计 1 个的个数. 思…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 位运算 日期 题目地址:https://leetcode.com/problems/total-hamming-distance/description/ 题目描述 The Hamming distance between two integers is the number of positions at which the correspondi…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Input: x = 1, y = 4 Output: 2 Explanation: 1   (0 0 0 1) 4   (0 1 0 0) ↑   ↑ 思路:就是求两数异或的二进制表示中有几个1. 如何求一个整数的二进制表示有几个一呢? while(x){x=x&(…
题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 2^31. Example: Input: x = 1, y = 4 Output: 2 Explanati…
传送门 Description The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output:…
1. 题目链接:https://leetcode.com/problems/hamming-distance/description/ 2.思路 常规做法做完看到评论区一个非常有意思的做法.用了n&=(n-1),这个地方的意思是,将最右边的1变成0.比方说: 最简单的例子: 原数字: 101011 n-1: 101010 n&(n-1):101011&101010=101010 再看另一个例子: 原数字:10100 n-1: 10011 n&(n-1):10100&…
[Leetcode/Javascript] 461.Hamming Distance 题目 The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note: 0 ≤ x, y < 231. Exampl…
problem 461. Hamming Distance solution1: 根据题意,所求汉明距离指的是两个数字的二进制对应位不同的个数.对应位异或操作为1的累积和. class Solution { public: int hammingDistance(int x, int y) { ; ; i<; i++) { <<i))^(y&(<<i))) ans++; } return ans; } }; solution2: 两个数字异或之后,统计结果二进制中1的…
[LeetCode]01 Matrix 解题报告 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/01-matrix/#/description 题目描述: Given a matrix consists of 0 and 1, find the distance of the nearest 0 for each cell. The distance between two adjacent cells is 1. Example:…
LeetCode 1 Two Sum 解题报告 偶然间听见leetcode这个平台,这里面题量也不是很多200多题,打算平时有空在研究生期间就刷完,跟跟多的练习算法的人进行交流思想,一定的ACM算法积累可以对以后在对算法中优化带来好处.Ok,今天是我做的第一题Add Two Sum. 题目要求 Given an array of integers, find two numbers such that they add up to a specific target number. The fu…
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The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 2^31. Example: Input: x = 1, y = 4 Output: 2 Explanation:…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanation: 1…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs of the given numbers. Example: Input: 4, 14, 2 Output: 6 Explanat…
题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Example: Input: x = 1, y = 4 Output: 2 Explanatio…
原题链接在这里:https://leetcode.com/problems/total-hamming-distance/ 题目: The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Now your job is to find the total Hamming distance between all pairs…
Unique Paths II Total Accepted: 31019 Total Submissions: 110866My Submissions Question Solution  Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How many unique paths would there be? An obstacle and empty spa…
hamming解题报告------------------------------------------------------------------------------------------------------------------------------------------------[题目] 找出N个二进制数,每个数有B位,使得各数两两之间“海明距离”至少为D.(若有多组解,输出字典序最小的.) 海明距离是指:两个二进制数不同二进制位的个数.[数据范围] 1<=N<=…
// 快速法求1的个数 int BitCount2(unsigned int n) { unsigned ; ; n; ++c) { n &= (n -) ; // 清除最低位的1 } return c ; } The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y,…
Distinct Subsequences Total Accepted: 38466 Total Submissions: 143567My Submissions Question Solution  Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed fro…
The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, calculate the Hamming distance. Note:0 ≤ x, y < 231. Input: x = 1, y = 4 Output: 2 Explanation: 1 (0 0 0 1…