POJ 2826 An Easy Problem?! -- 思路来自kuangbin博客 下面三种情况比较特殊,特别是第三种 G++怎么交都是WA,同样的代码C++A了 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; const double eps = 1e-8;…
Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two wooden boards on the wall of his barn. Shown in the pictures below, the two boards on the wall just look like two segments on the plane, a…
An Easy Problem?! Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7837   Accepted: 1145 Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two wooden boards on the wall of his barn…
一定要注意位运算的优先级!!!我被这个卡了好久 判断线段相交模板题. 叉积,点积,规范相交,非规范相交的简单模板 用了“链表”优化之后还是$O(n^2)$的暴力,可是为什么能过$10^5$的数据? #include<cmath> #include<cstdio> #include<cstring> #include<algorithm> #define N 100005 using namespace std; struct Point { double x…
Pick-up sticks Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 7699   Accepted: 2843 Description Stan has n sticks of various length. He throws them one at a time on the floor in a random way. After finishing throwing, Stan tries to find…
An Easy Problem?! Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12970   Accepted: 1995 Description It's raining outside. Farmer Johnson's bull Ben wants some rain to water his flowers. Ben nails two wooden boards on the wall of his bar…
题目链接:http://poj.org/problem?id=1066 Time Limit: 1000MS Memory Limit: 10000K Description Archeologists from the Antiquities and Curios Museum (ACM) have flown to Egypt to examine the great pyramid of Key-Ops. Using state-of-the-art technology they are…
题目链接:http://poj.org/problem?id=2653 Time Limit: 3000MS Memory Limit: 65536K Description Stan has n sticks of various length. He throws them one at a time on the floor in a random way. After finishing throwing, Stan tries to find the top sticks, that…
题目传送门 题意:两条线段看成两块木板,雨水从上方往下垂直落下,问能接受到的水的体积 分析:恶心的分类讨论题,考虑各种情况,尤其是入口被堵住的情况,我的方法是先判断最高的两个点是否在交点的同一侧,然后看看是否高的点覆盖了低的点,用叉积判断方向,其他的情况见网上的解释.貌似没有什么卡精度的数据.最后膜拜楼教主,难以望其项背... /************************************************ * Author :Running_Time * Created Ti…
受该两块木板以形成槽的效果.Q槽可容纳雨水多,注意雨爆跌,思想是非常easy,分类讨论是有点差. 1.假定两条线段不相交或平行,然后再装0: 2.有一个平行x轴.连衣裙0. 3.若上面覆盖以下的,装0: 4.其他,叉积求面积. 直接上代码: #include <iostream> #include <cmath> #include <stdio.h> using namespace std; const double eps=1e-8; struct point{ do…