问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道链表的深度拷贝题的难点就在于如何处理随机指针的问题,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果我们在每生成一个新节点给其随机指…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Example 1: Input: {"$id":"1","next":{"$id":"2&…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 深度复制: 仅简单的遍历一遍链表时,没法复制random pointer属性.所以有点懵,大神的做法如下,加入个人理解. 思路:对链表进行三次遍历. 第一次遍历复制每一个结…

题目描述: 中文: 给定一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点. 要求返回这个链表的深拷贝. 示例: 输入:{"$id":"1","next":{"$id":"2","next":null,"random":{"$ref":"2"},"val":2},"…

public RandomListNode copyRandomList(RandomListNode head) { /* 深复制,就是不能只是复制原链表变量,而是做一个和原来链表一模一样的新链表, 每一个节点都是新建的,而不是指向就节点 这个题的难点在于:随机节点. 随机节点有可能指向后边还没有建立的节点,这就没法指. 方法一:一一对应地记录每个新旧节点的映射关系,在常规节点建立后,就去查哈希表,找到对应 新节点的旧节点的random,就是新节点的random */ if (head==nu…

题目: Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 说明:给定已排好序的单链表,去重! 1)此链表默认无头节点,head指针指向的是第一个节点 2)链表为空或者只有一…

133. Clone Graph Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node lab…

  leetcode-19-Remove Nth From End of List—移除链表中倒数第n个元素 leetcode-21-Merge Two Sorted Lists—两个已排序链表归并 leetcode-23-Merge k Sorted Lists—k个已排序链表归并 leetcode-24-Swap Nodes in Pairs—链表中元素两两一组交换 leetcode-25-Reverse Nodes in K-Group—链表中元素k个一组逆序 leetcode-61-Ro…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道题的难点在于如何处理随机指针,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果在生成一个新节点给其随机指针赋值时,都去遍历原链表的话…