Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…

Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…

Given a roman numeral, convert it to an integer. The answer is guaranteed to be within the range from 1 to 3999. Have you met this question in a real interview? Yes Clarification What is Roman Numeral? https://en.wikipedia.org/wiki/Roman_numerals htt…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 罗马数转化成数字问题,我们需要对于罗马数字很熟悉才能完成转换.以下截自百度百科: 罗马数字是最早的数字表示方式,比阿拉伯数字早2000多年,起源于罗马. 如今我们最常见的罗马数字就是钟表的表盘符号:Ⅰ,Ⅱ,Ⅲ,Ⅳ(IIII),Ⅴ,Ⅵ,Ⅶ,Ⅷ,Ⅸ,Ⅹ,Ⅺ,Ⅻ…… 对应阿拉伯数字(就是现…

题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路:与12题正好相反,罗马数字基本字符集:I V X L C D M (1, 5, 10, 50, 100, 500, 1000).思路是从字符串最低位开始匹配,累加相应字符对应的阿拉伯数字,要注意的就是I,X,L(1,10,100)要判断是在左还是在右,在左就减在右就加.…

Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i…

题目意思:罗马数字转int 思路:字符串从最后一位开始读,IV:+5-1 class Solution { public: int romanToInt(string s) { map<char,int> mymap; mymap[; mymap[; mymap[; mymap[; mymap[; mymap[; mymap[; ]]; ;i>=;--i){ ]]) ans-=mymap[s[i]]; else ans+=mymap[s[i]]; } return ans; } };…

题目链接 https://leetcode.com/problems/roman-to-integer/?tab=Description   int toNumber(char ch) { switch (ch) { case 'I': return 1; case 'V': return 5; case 'X': return 10; case 'L': return 50; case 'C': return 100; case 'D': return 500; case 'M': retur…

题目描述 罗马数字包含以下七种字符:I, V, X, L,C,D 和 M. 字符 数值 I 1 V 5 X 10 L 50 C 100 D 500 M 1000 例如, 罗马数字 2 写做 II ,即为两个并列的 1.12 写做 XII ,即为 X + II . 27 写做 XXVII, 即为 XX + V + II . 通常情况下,罗马数字中小的数字在大的数字的右边.但也存在特例,例如 4 不写做 IIII,而是 IV.数字 1 在数字 5 的左边,所表示的数等于大数 5 减小数 1 得到的数…

1.题目13. Roman to Integer Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is…

13. Roman to Integer Easy Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve i…

题目 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路 在进行罗马数字转化为整数的过程中,由于罗马数字是按照从左往右从大到小的顺序排列,于是可以分析,当左边罗马数字对应的整数A比右边一个罗马数字对应的整数B小的时候,表示B-A. 利用map建立一个罗马数字与整数的对应映射,检查字符串当前字符与下一个字符对应整数的大小关系. 这…

1.题目描述 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 2.我的分析思路 罗马数字转成阿拉伯数字,这里面需要知道罗马数字的构成规则.罗马数字通过7个不同字母的重复或组合,能够表示出所有正整数(罗马数字中没有0). I = 1 V = 5 X = 10 L = 50 C = 100 D = 500 M = 1000 比如:IV…

题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 题目分析: 将罗马数字转换成阿拉伯数字,规则如下:罗马数字共有七个,即I(1),V(5),X(10),L(50),C(100),D(500),M(1000). 按照下面的规则可以表示任意正整数. 重复数次:一个罗马数字重复几次,就表示这个数的几倍.右加左减:在一个较大的罗马数…

我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 013. Roman to Integer 问题 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. S…

13.Roman to Integer Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is writ…

Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. public class Solution { public int romanToInt(String s) { if (s == null || s.length()==0) { return 0; } Map<Character, Intege…

Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解法一:非递归 从左到右遍历每个字符,并记录上个字符来处理双字符情况即可. class Solution { public: int romanToInt(string s) { ; ; ; i < s.size(); i ++) { switch(…

1.题目: 原题:Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. Subscribe to see which companies asked this questio 解析:给出一个罗马数字,要求把其转换为一个整数.输入范围在1到3999内. 罗马数字的规则如下: 罗马数字 I V X L C D M 代表的阿拉伯数字 1 5…

题目内容: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 题目分析:罗马数字向阿拉伯数字的转换情况如下: 1.M=1000 D=500 C=100 L=50 X=10 V=5 I=1 2.若小的罗马符号出现在大的罗马符号的前面,则小的罗马符号代表的数字改为负.这种情况只能出现有限的情况. 因此目前想到两种方法. 第一种方法是再扫…

https://leetcode.com/problems/roman-to-integer/ 原题: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路: 关键是要搞清罗马数字规则.PS:不用考虑错误输入. 核心: 遍历一遍,相同字母合并成对应数,然后比较如果比它后面的小就减去,否则就加上.时间复杂度O(n). 具体解析: 基…

一天一道LeetCode系列 (一)题目 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. (二)解题 和上一题相反,这题将罗马数字转换成整形数. 注意到 4,9,40,90,400,900这些特殊的数字的区别就不难写出代码了. class Solution { public: int romanToInt(string s) {…

题目要求 Roman numerals are represented by seven different symbols: I, V, X, L, C, Dand M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, whi…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解法: 只要考虑两种情况即可: 第一,如果当前数字是最后一个数字,或者之后的数字比它小的话,则加上当前数字 第二,其他情况(即为4或者9,这种情况下才可能出现后面的罗马数字比前面的大),则减去这个数字 public class Solution { public int romanT…

能力有限,这道题采用的就是暴力方法,也只超过了39%的用户.需要注意的就是罗马数字如果IXC的后一位比前一位大的采取的是减的方式. Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 给定一个罗马数字,将其转换为整数. 输入保证在1到3999之间. class Solution { public int romanToInt(Stri…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路:有关罗马数字的相关知识可见博客Integer to roman.从左往右遍历字符串,比较当前为和下一位的值,若是当前数字比下一位大,或者当当前数字为最后时,则加上当前数字,否则减去当前数字.这就遇到一个问题,罗马数字的字符串不是按26个字母顺序来的,如何确定大小.解决办法一:写…

题意:将罗马数字1到3999转化成自然数字,这里用了STL库map将罗马字符映射到自然数字. I,V,X,L,C,D,M -> 1,5,10,50,100,500,1000 m[s[i]]<m[s[i+1]//如IV 就需要减去1 class Solution { public: map<char,int> m; Solution(){ ; ] = "IVXLCDM"; ,,,,,,}; ; i < N; ++i){ m[str[i]] = num[i];…

题目描述: Given a roman numeral, convert it to an integer. 解题分析: 这道题只要百度一下转换的规则,然后着这解释写代码即可.实现上并没有什么难度,直接看代码即可 具体代码: public class Solution { public int romanToInt(String s){ int[] value={1000,500,100,50,10,5,1}; char[] array ="MDCLXVI".toCharArray()…

问题描述: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解题思路: 上一题反过来就可以了,其实觉得这两道题很没有意思. 代码如下: public class Solution { public int romanToInt(String s) { int result; if (s == null || s.length()…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 相比Interger to Roman,本题明显要简单一些,按照规则直接翻译就好. AC代码: class Solution(object): def romanToInt(self, s): roman_to_int = {'I': 1, 'V': 5, 'X': 10, 'L':…