题目链接:http://www.hihocoder.com/problemset/problem/1636 题目描述 在中国古代神话中,盘古是时间第一个人并且开天辟地,它从混沌中醒来并把混沌分为天地. 刚开始地上是没有山的,只有满地的石头. 这里有 \(N\) 堆石头,标号为从 \(1\) 到 \(N\) .盘古想要把它们合成一堆建造一座大山.如果某些堆石头的数量总和是 \(S\) ,盘古需要 \(S\) 秒才能把它们合成一堆,这新的一堆石头的数量就是 \(S\) . 不幸的是,每一次盘古只能把…

In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the beginning, there was no mountain on the earth, only stones all over…

队名:Unlimited Code Works(无尽编码)  队员:Wu.Wang.Zhou 先说一下队伍:Wu是大三学长:Wang高中noip省一:我最渣,去年来大学开始学的a+b,参加今年区域赛之前只学了大部分图论内容,以及一些数据结构.动态规划等内容,水平不及两个队友... ... 首先流水账式的记录一下比赛过程吧,最后再写这一年的感想.体会与将来的学习计划. 先从长春站说起... ... 长春站是我加入ACM以来参加的第一场ICPC,因此无比的激动!从杭州出发,乘了整整24小时的火车,终…

Description In country Light Tower, a presidential election is going on. There are two candidates,  Mr. X1 and Mr. X2, and both of them are not like good persons. One is called a liar and the other is called a maniac. They tear(Chinese English word,…

131072K   A digit sum S_b(n)Sb​(n) is a sum of the base-bb digits of nn. Such as S_{10}(233) = 2 + 3 + 3 = 8   S10​(233)=2+3+3=8, S_{2}(8)=1 + 0 + 0 = 1S2​(8)=1+0+0=1, S_{2}(7)=1 + 1 + 1 = 3S2​(7)=1+1+1=3. Given NN and bb, you need to calculate \sum_…

题意: 给你数字或 * 的串,你可以交换一个*和数字.在最前面添1.在一个地方插入*,问你使串满足入栈出栈的(RNP)运算法则. 思路: 引用:https://blog.csdn.net/u011580493/article/details/40077119 由于一个 * 能消除2个数字,然后生成一个数字.因此首先要保证数字个数大于等于 ‘*’ 个数+1. 如果数字个数不够,就在最前面添加. 然后开始从头开始遍历,遇到*就看当前的数字个数是否有两个或以上.不够的话,从最后面开始找第一个不是‘*’…

球队内线我也总水平,这所学校得到了前所未有的8地方,因为只有两个少年队.因此,我们13并且可以被分配到的地方,因为13和非常大的数目.据领队谁oj在之上a谁去让更多的冠军.我和tyh,sxk,doubleq运的在大二就有机会參加亚洲现场赛,非常激动.牡丹江赛区是我和sxk和doubleq组成rainbow战队,我们对这次区域赛事实上就是去张张见识,添加大赛经验(外加公费旅游2333),但是当我们真正来到赛场的时候不知道为上面我非常渴望拿一块牌子. 第一天热身赛,double迅速切下水题.我一直再…

#1636 : Pangu and Stones 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the begi…

Problem Description Here N (N ≥ 3) rabbits are playing by the river. They are playing on a number line, each occupying a different integer. In a single move, one of the outer rabbits jumps into a space between any other two. At no point may two rabbi…

Brute Force Sorting Time Limit: 1 Sec  Memory Limit: 128 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=6215 Description Beerus needs to sort an array of N integers. Algorithms are not Beerus's strength. Destruction is what he excels. He can destr…

Problem Description The sky was brushed clean by the wind and the stars were cold in a black sky. What a wonderful night. You observed that, sometimes the stars can form a regular polygon in the sky if we connect them properly. You want to record the…

Hello everyone! I am your old friend Rikka. Welcome to Xuzhou. This is the first problem, which is a problem about the minimum spanning tree (MST). I promise you all that this should be the easiest problemeasiest problem for most people. A minimum sp…

不知道怎样说起-- 感觉还没那个比赛的感觉呢?如今就结束了. 9号.10号的时候学校还评比国奖.励志奖啥的,由于要来比赛,所以那些事情队友的国奖不能答辩.自己的励志奖班里乱搞要投票,自己又不在,真是无语了--烦得要死.然后在这些事情还没处理好之前我们就这样10号中午从地大去北京站上火车了--那时真感觉这场带着这样的心情来现场赛感觉要打铁了-- 然后10号晚上队友的国奖让琦神帮答辩完了.得国奖无疑了.然后自己的励志奖也定下来一定得了.在火车上的我们也松了一口气.不能由于来比赛国奖励志奖都不得是不-…

昨晚乱入学弟的训练赛,想了一下这个题.推导的过程中,加深了对公理化的概率论理解.$\newcommand{\d}{\mathop{}\!\mathrm{d}}$ 解法一 考虑 $ d < L$ 的情形. \begin{equation*} P(X = 1) = \frac{d}{L} \end{equation*} \begin{align*} P(X = 2) &= \int_0^{L - d} \frac{\d x}{L} \frac{d}{L - x} \\ &= \frac{…

Known Notation Time Limit: 2 Seconds      Memory Limit: 65536 KB Do you know reverse Polish notation (RPN)? It is a known notation in the area of mathematics and computer science. It is also known as postfix notation since every operator in an expres…

Problem Description Coach Pang is interested in Fibonacci numbers while Uncle Yang wants him to do some research on Spanning Tree. So Coach Pang decides to solve the following problem:Consider a bidirectional graph G with N vertices and M edges. All…

题意: 有一排n个石子(注意n可以为0),每次可以取1~K个连续的石子,Adrien先手,Austin后手,若谁不能取则谁输. 思路: (1) n为0时的情况进行特判,后手必胜. (2) 当k=1时,很容易可以发现:若n为偶数则后手赢,n为奇数则先手赢. (3) 当k>1时,只要先手保证这一排石子两边对称,则后手必败,所以可知k>1时先手必胜. #include<bits/stdc++.h> using namespace std; int main() { ios::sync_w…

Problem Description Consider a un-rooted tree T which is not the biological significance of tree or plant, but a tree as an undirected graph in graph theory with n nodes, labelled from 1 to n. If you cannot understand the concept of a tree here, plea…

Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his…

Information Entropy Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Information Theory is one of the most popular courses in Marjar University. In this course, there is an important chapter about information entropy. Entropy is t…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5071 Chat Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 476    Accepted Submission(s): 109 Problem Description As everyone knows, DRD has no g…

2017 ACM ICPC Asia Regional - Daejeon Problem A Broadcast Stations 题目描述:给出一棵树,每一个点有一个辐射距离\(p_i\)(待确定),但\(p_i==0\)的点不能辐射自己,只能由别的点辐射覆盖.求\(p_i\)的和的最小值. Problem B Connect3 题目描述:有一个\(4 \times 4\)的网格,两个人玩游戏,第一个人用黑棋,第二人用白棋.每次选择一列,将棋子扔下去,直到最下一个空的格子.现在给出第一个人下…

2017 ACM - ICPC Asia Ho Chi Minh City Regional Contest A - Arranging Wine 题目描述:有\(R\)个红箱和\(W\)个白箱,将这些箱子分成若干堆,使得每一堆只有一种颜色,然后将这些堆排成一排,使得相邻的堆的颜色不一样,并且每堆红箱的个数不能超过\(d\),问有多少种方案. solution 不会. B - Barcode 题目描述:有一排\(n\)个球,现在要给这\(n\)个球涂成红色或蓝色,使得红色球的个数等于蓝色球的个数…

Apple Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 982    Accepted Submission(s): 323 Problem Description Apple is Taotao's favourite fruit. In his backyard, there are three apple trees with…

2016年11月12到11月13为期两天的比赛,这是我们这个对第一次去打亚洲区域赛,经过这次比赛,我认识到了自己与别人的差距,也许我们与别人的起点不同,但这不是理由. 这次的比赛12号的热身赛两点开始,三个小时,四道题,但可惜的是我们一题没写出来,编译器的不熟悉,让我们弄了半个多小时,等把两题读完发现没有一点明确的思路,然后在那慢慢的试.最后时间过完了,也没搞出来.这半天就知道我们与别人的差距了,还有我们自己的知识点没有练好,做的题还是太少.回去后我们就商量13号正式赛要好好打,晚上早点睡,养足…

transaction transaction transaction Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 132768/132768 K (Java/Others)Total Submission(s): 1496    Accepted Submission(s): 723 Problem Description Kelukin is a businessman. Every day, he travels arou…

transaction transaction transaction Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 132768/132768 K (Java/Others)Total Submission(s): 1496    Accepted Submission(s): 723 Problem Description Kelukin is a businessman. Every day, he travels arou…

2019~2020icpc亚洲区域赛徐州站H. Yuuki and a problem 题意: 给定一个长度为\(n\)的序列,有两种操作: 1:单点修改. 2:查询区间\([L,R]\)范围内所有子集和中没出现的最小正整数. 思路: 对于维护序列的问题大概率是数据结构的题目了,先确定一下题目的性质. 操作2需要我们提取\([l,r]\)范围内的值,这可以用主席树解决,同时需要带修,所以可以用树状数组套主席树完成. 确定是树套树后,考虑怎么维护操作2. 我们考虑一个节点,先看看能不能表示成1,如…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud 现场赛的时候由于有个地方有点小问题,没有成功AC,导致与金牌失之交臂. 由于今天下午有点事情,无法打重现,所以下午只是花了十分钟做了一道J题,抢了个FB,2333333333 Yue Fei's Battle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 512000/512000 K (Java/Others)T…

有时候,很简单的模板题,可能有人没有做出来,(特指 I ),到时候一定要把所有的题目全部看一遍 目录 B 题解 E F 题解 H I 题解&代码 J B 输入样例 3 2 1 2 1 2 3 1 输出样例 1 说明 In the first sample case, the sequence [a1,a2,a3]=[0,1,0][a_1,a_2,a_3]=[0,1,0][a1,a2,a3]=[0,1,0] meets all the constraints and has the minimum…