Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14336    Accepted Submission(s): 5688 Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone…

题目链接:pid=2602">HDU 2602 Bone Collector Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 28903    Accepted Submission(s): 11789 Problem Description Many years ago , in Teddy's h…

HDOJ(HDU).2602 Bone Collector (DP 01背包) 题意分析 01背包的裸题 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 1005 using namespace std; int v[nmax],w[nmax],dp[nmax]; int main() { //freopen("in…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=2602 Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 77450    Accepted Submission(s): 32095 Problem Description Many years ago , in…

原题代号:HDU 2602 原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=2602 原题描述: Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2602 Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 54132    Accepted Submission(s): 22670 Problem Description Many years ago , in…

http://acm.hdu.edu.cn/showproblem.php?pid=2602 Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 32408    Accepted Submission(s): 13329 Problem Description Many years ago , in Tedd…

Bone Collector http://acm.hdu.edu.cn/showproblem.php?pid=2602 Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2602 题目分析:0-1背包  注意dp数组的清空, 二维转化为一维后的公式变化 /*Bone Collector Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 34192 Accepted Submission(s): 14066 Proble…

Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 60469    Accepted Submission(s): 25209 Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bo…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2602 Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …  The bone collect…

http://acm.hdu.edu.cn/showproblem.php?pid=2602 第一题 01背包问题 http://acm.hdu.edu.cn/showproblem.php?pid=1114 第二题 完全背包问题 http://acm.hdu.edu.cn/showproblem.php?pid=2191 第三题 多重背包问题 这里重复使用数组 认识倒序 和 正序的原因 转自:http://www.cppblog.com/tanky-woo/archive/2010/07/31…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2602 Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave…

Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …The bone collector had a big bag with a volume of…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2602 水题啊水题 还给我WA了好多次 因为我在j<w[i]的时候状态没有下传.. #include <cstdio> #include <algorithm> #include <cstring> using namespace std; typedef long long LL; typedef pair<int,int> PII; #define PB…

Problem Description Many years ago , in Teddy's hometown there was a man who was called "Bone Collector". This man like to collect varies of bones , such as dog's , cow's , also he went to the grave -The bone collector had a big bag with a volum…

Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 85530    Accepted Submission(s): 35381 Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bon…

Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 39532    Accepted Submission(s): 16385 Problem Description Many years ago , in Teddy's hometown there was a man who was called "Bo…

这种01背包的裸题,本来是不想写解题报告的.但是鉴于还没写过背包的解题报告.于是来一发. 这个真的是裸的01背包. 代码: #include <iostream> #include <cstdio> using namespace std; #define N 1007 int c[N],w[N],dp[N]; int main() { int t,i,n,V,v; scanf("%d",&t); while(t--) { scanf("%d%…

题意:给出包裹的大小v,然后给出n块骨头的价值value和体积volume,求出一路下来包裹可以携带骨头最大价值 思路:01背包 1.二维数组(不常用 #include<iostream> #include<stdio.h> #include<math.h> using namespace std; ][]; int main() { int i,j; int t,n,_v;//测试用例个数,物品种类,背包大小 ],v[];//花费,价值 scanf("%d&…

       题目大意:有n件物品,每件物品均有各自的价值和体积,给你一个容量为 V 的背包,问这个背包最多能装的物品的价值是多少?        解题思路:这是一道0 - 1 背包的简单模板题,也是基础的DP问题,状态转移方程                       f[i][j] = max{ f[ i - 1 ][j] , f[ i - 1 ][ j - v[i] ] + w[i]  }         边界条件:f[0][0] = f[0][1] = ……  = f[0][ V ]…

题目链接:https://vjudge.net/contest/103424#problem/A 题目大意: 第一行输入几组数据,第二行第一个数字代表物体个数,第二个数代表总体积.需要注意的是,第三排输入的是物品的价值,第四排的物品的体积.在不可以拆分物体的前提下,已知背包的总体积,最大能获取的价值是多少. 01背包模板题,没什么好说的.(附两种形式的dp数组解决方案) //一维dp数组实现(滚动数组) #include <iostream> #include <cstdio> #…

题意:给定一个体积,和一些物品的价值和体积,问你最大的价值. 析:最基础的01背包,dp[i] 表示体积 i 时最大价值. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream>…

题意:收藏骨头. 思路: 常规的01背包. #include <iostream> #define N 1005 using namespace std; int volume[N]; //体积 int value[N]; //价值 int dp[N]; //总价值(动态更新) int max(int a,int b) { return a>b?a:b; } void cal(int n,int v) //不断更新数组dp { int i,j; ;i<=n;i++) ;j--) d…

题意:这题就是一个纯粹的裸01背包 分析:WA了好几次.01背包实现的一些细节没搞懂 1.为什么dp[i][j]赋初值为0而不是value[i].由于第i个石头可能不放! 2.在进行状态转移之前要dp[i][j]=dp[i-1][j],不然肯定会WA啊.想想就明确了 3.终于结果是dp[n][v],不是每次求mx,由于状态转移就是这么推的啊 代码: #include<iostream> #include<cstring> #include<cmath> using na…

题意:01背包:有N件物品和一个容量为V的背包.每种物品均只有一件.第i件物品的费用是volume[i],价值是value[i],求解将哪些物品装入背包可使价值总和最大. 分析: 1.构造二维数组: dp[i][j]---前i件物品放入一个容量为j的背包可以获得的最大价值. dp[i][j] = max(dp[i - 1][j], dp[i - 1][j - volume[i]] + value[i]);---(a) (1)dp[i - 1][j]---不放第i件物品,因此前i件物品放入一个容量…

*注 虽然没什么人看我的博客但我还是要认认真真写给自己看 背包问题应用场景给定 n 种物品和一个背包.物品 i 的重量是 w i ,其价值为 v i ,背包的容量为C.应该如何选择装入背包中的物品,使得装入背包的总价值最大?*01 背包 *01 背包特点: 给定 n 种物品和一个背包 ( 每个物品只能选取一个).物品 i 的重量是w[i],其价值为v[i],背包的容量为C.应该如何选择装入背包中的物品,使得装入背包中的物品的总价值最大?*状态: dp[i][j] 表示在只能从 1-i 个物品中选…

很标准的01背包问题 //#define LOCAL #include <algorithm> #include <cstdio> #include <cstring> using namespace std; + ; int w[maxn], v[maxn], dp[maxn]; int main(void) { #ifdef LOCAL freopen("2602in.txt", "r", stdin); #endif int…

Bone Collector II Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3355    Accepted Submission(s): 1726 Problem Description The title of this problem is familiar,isn't it?yeah,if you had took par…

Bone Collector II Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4178    Accepted Submission(s): 2174 Problem Description The title of this problem is familiar,isn't it?yeah,if you had took pa…